Solid State Quiz-12
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Q1. Density of a crystal remains unchanged as a result of
Solution
Due to Frenkel defect, density of a crystal remains unchanged.
Due to Frenkel defect, density of a crystal remains unchanged.
Q2.Number of atoms in the unit cell of Na(bcc type crystal) and Mg(fcc type crystal ) are respectively :
Solution
Due to Frenkel defect, density of a crystal remains unchanged. .
Due to Frenkel defect, density of a crystal remains unchanged. .
Q3. The unit cell cube length for (just like structure) is 5.14 , Assuming anion-anion contact, the ionic radius for chloride ion is:
Solution
The distance between and ion can be derived as half of the edge length of cube= 1.815.
The distance between and ion can be derived as half of the edge length of cube= 1.815.
Q4. Silicon dioxide is an example of
Solution
is covalent crystal like diamond and graphite
is covalent crystal like diamond and graphite
Q5. In which of the following crystals alternate tetrahedral voids are occupied?
Solution
In structure, sulphide ions occupy all (fcc) lattice points while ions are present in alternate tetrahedral sites.Therefore, there is one ion for every ion.
In structure, sulphide ions occupy all (fcc) lattice points while ions are present in alternate tetrahedral sites.Therefore, there is one ion for every ion.
Q6. If the positions of and are interchanges in the crystal lattice with respect to and is
Solution
Each (in bcc) in is surrounded by six (in fcc) and each in is surrounded by six and thus, on interchanging and the fcc structure of will not change but with respect to it will be fcc and with respect to it will be bcc.
Each (in bcc) in is surrounded by six (in fcc) and each in is surrounded by six and thus, on interchanging and the fcc structure of will not change but with respect to it will be fcc and with respect to it will be bcc.
Q7.A solid has type structure with edge length 580.4 pm. The radius of is 100 pm. What is the radius of ?
Solution
has fcc structure and thus, = 290.2= 290.2 – 100 = 190.2
has fcc structure and thus, = 290.2= 290.2 – 100 = 190.2
Q8.Sodium metal crystallises at room temperature in a body centred cubic lattice with a cell edge The radius of sodium atom is
Solution
For a body centred cubic lattice radius,Therefore, radius of
For a body centred cubic lattice radius,Therefore, radius of
Q9.The elements commonly used for making transistors are
Solution
Si and Ge are used for making transistors.
Si and Ge are used for making transistors.
Q10. Most crystals show good cleavage because their atoms, ions and molecules are
Solution
Section 138 of the Negotiable Instruments Act, 1881 states that the dishonour of cheque is a criminal offence and is punishable by imprisonment up to two years or with monetary penalty or with both.
Section 138 of the Negotiable Instruments Act, 1881 states that the dishonour of cheque is a criminal offence and is punishable by imprisonment up to two years or with monetary penalty or with both.
