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IIT JEE Main Result 2020

National Testing Agency (NTA) will release the JEE Main 2020 results after the exam. It will be announced online. For January session the tentative dates of the result would be 31st January while for April session it will be declared later. You can find the score of Physics, Chemistry, and Maths on the scorecard along with the final result. To appear in JEE Advanced it’s necessary to qualify in the JEE main. If you have appeared for both sessions of January and April the best of both scores would be considered. This scorecard will be used in admission in different IITs, NITs and GFTIs and many other institutes. Read the article in detail for the complete information.

JEE Main Result 2020 - Important Dates

Events January Attempt Dates April Attempt Dates
JEE Main 2020 Exam January 6 to 9, 2020 April 3 to 9, 2020
Release of Provisional Answer Key January second week April second week
Release of Final Answer Key January third week April third week
Declaration of Result January 31, 2020 April 30, 2020
Registration for JEE Advanced 2020 May first week, 2020
JEE Advanced 2020 May Second week, 2020
JEE Advanced 2020 Result May last week, 2020
Registration for JoSAA 2020 Counselling June 15, 2020

How to Check JEE Main Result 2020

JEE Main 2020 results for the January session will be released by the National Testing Agency (NTA) on January 31. This year, the JEE Main 2020 result will be declared for three papers - Paper-1 (BTech), Paper-2 (BArch) and Paper-3 (BPlan). To see JEE Main 2020 results, applicants will require their Application Number, Date of Birth and the Security Pin shown on the page. 

Alongside the result, NTA will likewise release the rundown of applicants who will score 100 percentile and JEE Main 2020 state toppers. NTA won't dispatch JEE Main 2020 scorecard through mail or post to competitors who appeared for the test. This year, the procedure of standardization has been utilized to decide the JEE Main results/merit list.

How to Check JEE Main Result 2020? 
  • Visit the official site of JEE Main or NTA to check your JEE Main result
  • Click the tab 'JEE (Main) April 2020 score' 
  • Enter your JEE Main Application Number and secret pin/date of birth 
  • Type the necessary subtleties, JEE Main 2020 result will be shown on the web 
  • Download or print your JEE Main 2020 scorecards 
  • Aspirants are encouraged to protect their scorecards till the confirmation procedure close 
  • JEE Main 2020 Result: Details Mentioned on Scorecard 
JEE Main 2020 result and scorecard contains the below data:
  • Name of the Applicant
  • Roll number 
  • Date of birth 
  • Guardians name 
  • State code of qualification 
  • Classification and nationality 
  • Subject-wise NTA scores 
S.No. State Code of Eligibility Candidate Name NTA Score
1 ANDAMAN AND NICOBAR ISLAND SHUBHANSHU PRASAD 98.7250736
2 ANDHRA PRADESH BOJJA CHETAN REDDY 100
3 ARUNACHAL PRADESH PRINCE KUMAR GUPTA 98.8802243
4 ASSAM PRADIPTA PARAG BORA 99.9963677
5 BIHAR ABHISHEK KUMAR 99.9771914
6 CHANDIGARH DISHANK JINDAL 99.997251
7 CHHATTISGARH RISHABH BHATNAGAR 99.972758
8 DADRA AND NAGAR HAVELI VISHWAJEET DESHMUKH 98.8751498
9 DAMAN & DIU ASHMIT SINGH 99.3978968
10 DELHI NAVNEET JINDAL 99.999083
11 FOREIGN/OCI/PIO/NEPAL/BHUTAN ANANYA AMANCHERLA 99.8928714
12 GOA JAIPRAKASH SURESH GURAV 99.9872898
13 GUJARAT RAGHAV SOMANI 99.9907511
14 HARYANA ASHUTOSH SINGLA 99.9981753
15 HIMACHAL PRADESH SARTHAK GUPTA 99.8950807
16 JAMMU AND KASHMIR AMAN YADAV 99.9789101
17 JHARKHAND ANKIT KUMAR JAIN 99.9899608
18 KARNATAKA KEVIN MARTIN 100
19 KERALA VISHNU VINOD 99.9990801
20 LAKSHADWEEP ABDUL JAVAD PA 88.3358227
21 MADHYA PRADESH DHRUV ARORA 100
22 MAHARASHTRA ANKIT KUMAR MISRA 100
23 MAHARASHTRA GUPTA KARTIKEY CHANDRESH 100
24 MAHARASHTRA RAJ ARYAN AGRAWAL 100
25 MANIPUR LAISHRAM PRINCE SINGH 97.5009989
26 MEGHALAYA GOURAV KUMAR 99.8872894
27 MIZORAM AKASH JYOTI SAHOO 94.521163
28 NAGALAND KARTIKEYA CHANDRA 96.7983937
29 ODISHA SIBASIS NAYAK 99.9844902
30 PUDUCHERRY CHIRANTANDIP MAHANTA 99.7827873
31 PUNJAB JAYESH SINGLA 100
32 RAJASTHAN SHUBHANKAR GAMBHIR 100
33 RAJASTHAN SAMBIT BEHERA 100
35 SIKKIM RAHUL GUPTA 99.1418764
36 TAMIL NADU GAURAV P 99.993561
37 TELANGANA ADELLY SAI KIRAN 100
38 TELANGANA YINDUKURI JAYANTH PHANI SAI 100
39 TELANGANA BATTEPATI KARTHIKEYA 100
40 TELANGANA VISWANATH K 100
41 TRIPURA SHAYANDEEP BHAUMIK 99.7457412
42 UTTAR PRADESH HIMANSHU GAURAV SINGH 100
43 UTTAR PRADESH NAMAN GUPTA 100
44 UTTARAKHAND PALLAV SEMWAL 99.9556053
45 WEST BENGAL SHASWATA DUTTA 99.9972491

Candidates who scored 100 Percentile in JEE Main 2019

SI No. Candidate Name State Code of Eligibility
1 Shubhan Srivastava Delhi
2 Kevin Martin Karnataka
3 Dhruv Arora Madhya Pradesh
4 Jayesh Singla Punjab
5 Battepati Karthikeya Telangana
6 Nishant Abhangi Rajasthan
7 Adelly Sai Kiran Telangana
8 Viswanath K Telangana
9 Konda Renu Andhra Pradesh
10 Abhay Pratap Singh Rathore Madhya Pradesh
11 Sambit Behera Rajasthan
12 Shubhankar Gambhir Rajasthan
13 Ankit Kumar Mishra Maharashtra
14 Himanshu Gaurav Singh Uttar Pradesh
15 Prakhar Jagwani Madhya Pradesh
16 Dravya Marwaha Haryana
17 Naman Gupta Uttar Pradesh
18 Gupta Kartikey Chandresh Maharashtra
19 Yindukuri Jayanth Phani Sai Telangana
20 Samiksha Das Rajasthan
21 Bojja Chetan Reddy Andhra Pradesh
22 Gudipaty Aniket Jharkhand
23 Jitender Kumar Yadav Haryana

Marking scheme of JEE Main 2020

NTA follows the predetermined marking scheme for calculating the marks obtained in each part of the question paper. The marking scheme is discussed below

For every correct answer 4 marks is awarded
For wrong answers 1 mark is deducted
For unanswered question No mark is awarded or deducted

How is the JEE Main result 2020 calculated?

JEE Main result is calculated in the form of percentile NTA score each for Physics, Chemistry and Mathematics and one combined score. NTA scores are obtained by normalization using the raw score obtained by the candidates. The following formula is used for obtaining the NTA score.
Total Percentile (T1P): 100 X No. of candidates appeared from the session with raw score EQUAL TO OR LESS than T1 score
Total No. of candidates appeared in the session
Mathematics Percentile (M1P) 100 X No. of candidates appeared from the session with raw score EQUAL TO OR LESS than M1 score in Mathematics
Total No. of candidates appeared in the session
Physics Percentile (P1P) 100 X No. of candidates appeared from the session with raw score EQUAL TO OR LESS than P1 score in Physics
Total No. of candidates appeared in the session
Chemistry Percentile (C1P): 100x No. of candidates appeared from the session with raw score EQUAL TO OR LESS than C1 score in Chemistry
Total No. of candidates appeared in the session

Declaration of the final result of JEE Main 2020 and All India Ranks
As we all know JEE Main 2020 will be conducted in two session- January and April. It will be held in different sessions and the calculation of sore will be done on normalized basis. There is a formula to calculate these scores which is preferred by NTA. 

Compilation and display of Paper 1 Result for First January session:
JEE Main 2020 Paper-1 first test date will be held in different session. The score will be displayed according to the corresponding marks secured by candidates in different subjects viz. Physics, Chemistry Maths etc.

Compilation and display of Paper 1 Result after April session:
Tie-Breaking
In case of a tie when two or more candidates obtain equal Total NTA Score in JEE Main 2020, inter-se merit of such candidates shall be determined in the following order:
  • Rank list for admission to B.E. /B. Tech
  • NTA score of raw mark in Mathematics
  • NTA score of raw mark in Physics
  • NTA score of raw mark in Chemistry
  • Candidates older in age
Still if there is a dispute and not able to meet the criteria for the same rank. NTA will conduct the exam in January and April sesion and the best of both the rank will be considered as a factor to compare the rank in the case. The rank will be considered as on All India Rank basis.

Compilation and display of Paper 2 Result for January session
Compilation and display of Paper 2 Result after April session
JEE Main 2020 Paper-2 will be held in single shift and the total marks will be merged with the mark secure din Paper 1 and Paper 2. On the basis of this the overall merit list/ranking would be declared. Best of both the score will be considered for ranking.
In case of a tie when two or more candidates obtain equal Total Marks in JEE Main 2020, inter-se merit of such candidates shall be determined in the following order:

Difference between Percentage and Percentile
Percentage =Marks obtained / Total marks (x) 100

Percentile =100 (x) Number of candidates in the group with aggregate marks less than that obtained by the candidate / Total number of candidates in the group

JEE Main 2020 Cutoff

NTA will release the cut off separately along with the result. Cutoff mark is the minimum criteria to qualify in the exam. It will be also considered for admission in IITS, NITs and GFTIs. Students can find the JEE main cut off for previous year below:

JEE Main 2019 Cutoff

Category Cutoff Score
Common Merit List 89.754849
General (EWS) 78.2174869
OBC 74.3166557
SC 54.0128155
ST 44.3345172
PWD 0.1137173

JEE Main Cutoff for previous years

Category 2018 2017 2016 2015 2014 2013
General 74 81 100 105 115 113
OBC-NCL 45 49 70 70 74 70
SC 29 32 52 50 53 50
ST 24 27 48 44 47 45

JEE Main 2020 Rank List

NTA will release the JEE Main 2020 rank list along with the declaration of result. JEE Main rank list mentions the ranks obtained by students. NTA will release two types of rank, All India Rank and Category Rank. JEE Main 2020 Rank list will be prepared on the basis of candidates percentile score in the exam.

JEE Main Mark Vs Rank

Students who qualify JEE Main are provided percentile NTA score and its corresponding All India Rank and Category Rank. Joint Seat Allocation Authority (JoSAA) uses the All India Rank of Candidates for the allotment of seats in all the participating institutes. Students can find the reference JEE Main Mark vs Rank criteria in order to get an idea about their rank as per their score
JEE Main Scores JEE Main Ranks (CRL)
336 - 360 1 - 20
310 to 335 21 - 225
251 to 300 226 - 1492
201 to 250 1493 - 5752
151 to 200 5753 - 18377
101 to 150 18378 - 57131
51 to 100 57132 - 240541
1 to 50 240542 - 984170
-40 to 0 984171 - 1074221

JEE Main Marks vs Percentile

The result of JEE Main 2020 will be released in the form of NTA score, which is a percentile score obtained by normalization process. Normalization is done on the basis of candidates raw score obtained in each subject. Normalization is done to eliminate any parity in difficulty level of exam held across multiple session and shifts. The JEE Main result enlists percentile NTA score each for Physics, Chemistry and Mathematics and one combined score. Students can find for reference the JEE Main marks vs Percentile scores.

JEE Main Marks Percentile
360 to 310 100 - 99.98724751
309 to 299 99.985572 - 99.9740296
298 to 288 99.97589128 - 99.96258028
287 to 278 99.96146328 - 99.94424276
277 to 268 99.94098483 - 99.91929629
267 to 258 99.91836545 - 99.89081262
257 to 248 99.88643768 - 99.84845946
247 to 238 99.84510844 - 99.79959043
237 to 228 99.79679791 - 99.73294238
227 to 218 99.73005678 - 99.65475193
217 to 208 99.64888765 - 99.55273201
207 to 198 99.54919482 - 99.43609792
197 to 188 99.4200875 - 99.28958392
187 to 178 99.26473052 - 99.07781811
177 to 168 99.06329703 - 98.85683701
167 to 158 98.82509541 - 98.55710695
157 to 148 98.53104347 - 98.20040957
147 to 138 98.14939961 - 97.75686494
137 to 128 97.69477799 - 97.17648701
127 to 118 97.13841571 - 96.41990133
117 to 108 96.35511496 - 95.49744019
107 to 98 95.42678954 - 94.40128456
97 to 88 94.19473145 - 92.74709113
87 to 78 92.61891464 - 90.64227869
77 to 68 90.42902355 - 87.34180397
67 to 58 87.34180397 - 82.68016383
57 to 48 81.92571907 - 75.39020758
47 to 38 74.13450619 - 64.11300382
37 to 28 62.88839244 - 49.28762915
27 to 18 49.01228707 - 33.08815042
17 to 1 31.32570046 - 9.077538863

JEE Main 2020 Seat Matrix

Students can find here the seat matrix of JEE Main
Institute Type Seats
IIT 13,376
NITs 17,967
IIITs 4,023
GFTIs 4,683

JEE Main 2020 Reservation

All the participating institutes of JEE Main has reserved a certain number of seats for candidates belonging to reserved categories. Admission to candidates belonging to reserved categories are done considering the reservation criteria mandated by the Government. Students can find below the percentage of seats reserved in the institutes.
Categories Reservation Percentage
Scheduled Caste 15%
Scheduled Tribe 7.50%
OBC (NCL) 27%
Person with Disabilities 5%
Economically Weaker Section 10%

Eligibility Criteria for Appearing in JEE Advanced 2020

Students who will qualify JEE Main 2020 with the minimum cutoff mark as decided by the official authority becomes eligible to appear in JEE Advanced. Students can find below the previous year cutoff trends for appearing in JEE Advanced.
Category 2019 (NTA Score) 2018 2017 2016 2015 2014 2013
General 89.754849 74 81 100 105 115 113
OBC-NCL 78.2174869 45 49 70 70 74 70
SC 74.3166557 29 32 52 50 53 50
ST 54.0128155 24 27 48 44 47 45
PwD 44.3345172 35

Frequently Asked Question (FAQs) - JEE Main Result 2020

Q: How to know if qualified for JEE Advanced 2019 exam?
A:First of all check the cut off. If you have crossed this market then you have been qualified for the next round. You can check the details at JEE Main 2020 score card..

Q: How to check eligibility for JEE Advanced 2020?
A: Eligibility can be checked on the following basis:
Age limit – To appear in JEE Advanced 2020, honourable supreme court has declared the age not to be more than 25 years.
Qualifying examination – The candidates should have appeared and qualified 12th standard (or equivalent) examination in 2019 or 2020.
Number of attempts – JEE Advanced can be attempted by the candidates two times in two consecutive years.
JEE Main – All of the candidates have to qualify JEE Main exam and satisfy the specified cutoff for admissions into IITs through JEE Advanced exam.
IIT Admissions – Should not have been admitted in an IIT irrespective of whether or not he/she continued in the programme or accepted an IIT seat by reporting at a reporting centre in the past. Those candidates whose admission at IITs was cancelled after joining will also not be considered eligible for JEE Advanced.

Q: How many students appeared in JEE Mains 2019?
A: There are 608440 candidates were appeared in the January session and similarly, there are totally 881096 candidates participated in the April session. 77% of students appeared in both the sessions of JEE Main 2019 examination i.e., 11,47,125 candidates.

Q: What will my JEE Main result in April contain?
A: it will consist of percentile on the basis of ranks secured on all India basis.

Q: How will I know my best score? Will the April and January scores be given separately?
A: see for overall ranking the best of both the score will be considered and the score of both sessions will be mentioned separately.

Q: How will the ranking be calculated for JEE Main 2020 considering both the attempts?
A: JEE Main 2020 ranks will be calculated on the basis of the final percentile that will be mentioned for each candidate. The best of the two scores will be used for candidates who have appeared in both the sessions while the score of the session appeared will be used for all others.

Q: Since percentile can be the same in a session for two or more candidates, how will the ranks be awarded?
A: Well, the ranking will be as per the inter-se-merit guidelines which are discussed in detail in the article above. The ranks will be awarded as per the same.

Q: How can I know for which percentile I will get a seat?
A: This, unfortunately, is something that cannot be predicted just like that. Its better to use a rank predictor tool that uses past trends keeping your category in mind and then gives all those options.

Q: Will the JEE Advanced qualifying status be announced with the JEE Main 2020 result?
A: Yes, the cutoff marks, as well as JEE Advanced qualifying status, will be announced by NTA with the JEE Main result 2020. It must be noted that this is the cutoff to appear for JEE Advanced and not for admission through JEE Main.

Q: Should I drop one year if I don't get the requisite percentile for admissions?
A: This is not advisable as statistics show very few candidates succeeding in their second attempt. It is more prudent to take admissions in colleges /universities other than NITs, IIITs or GFTIs. That way you won't waste one whole year. However, if you are strong-minded about the reattempt and willing to work very hard, you may also choose to do so.

Q: Can I ask for revaluation of the result of JEE Main 2020?
A: No, you cannot ask for revaluation. This is a computer-based test hence chances of malpractices are less and NTA does not entertain revaluation.

Q: I think I should have got more marks when I check the answer key but my result shows a lower percentile? Can I get clarity on this?
A: Actually, NTA will release your marks and percentile. To know the calculation behind it, you will require statistics on how many students attempted the test along with you which NTA does not release. So chances of clarity on this is practically nil.

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