As per analysis for previous years, it has been observed that students preparing for NEET find Physics out of all the sections to be complex to handle and the majority of them are not able to comprehend the reason behind it. This problem arises especially because these aspirants appearing for the examination are more inclined to have a keen interest in Biology due to their medical background. Furthermore, sections such as Physics are dominantly based on theories, laws, numerical in comparison to a section of Biology which is more of fact-based, life sciences, and includes substantial explanations. By using the table given below, you easily and directly access to the topics and respective links of MCQs. Moreover, to make learning smooth and efficient, all the questions come with their supportive solutions to make utilization of time even more productive. Students will be covered for all their studies as the topics are available from basics to even the most advanced.
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**Q1.**An engine develops 10 kW of power. How much time will it take to lift a mass of 200 kgto a height of 40 m (g=10 m/sec

^{2})?

Solution

P= mgh/t=10×10

P= mgh/t=10×10

^{3}⇒t=(200×40×10)/(10×10^{3})=8 sec**Q2.**A neutron having mass of 1.67×10

^{-27}kg and moving at 10

^{8}m/s collides with a deutron at rest and sticks to it. If the mass of the deutron is 3.34×10

^{-27}kg then the speed of the combination is?

Solution

According to law of conservation of momentum Momentum of neutron = Momentum of combination ⇒1.67×10

According to law of conservation of momentum Momentum of neutron = Momentum of combination ⇒1.67×10

^{-27}×10^{8}=(1.67 ×10^{-27}+3.34×10^{-27})v ∴v=3.33×10^{7}m/s**Q3.**A ball of mass 2kg and another of mass 4kg are dropped together from a 60 feet tall building. After a tall of 30 feet each towards earth, their respective kinetic energies will be in the ratio of?

Solution

Kinetic energy =1/2 mv

Kinetic energy =1/2 mv

^{2}As both balls are falling through same height therefore the possess same velocity But KE∝m [If v= constant] ∴(KE)_{1}/(KE)_{2}=m_{1}/m_{2}=2/4=1/2

**Q4.**10 L of water per second is lifted from well through 20 m and delivered with a velocity of 10ms

^{-1},then the power of the motor is?

Solution

Power ,p=(Total Energy)/t = (mgh+1/2 mv

Power ,p=(Total Energy)/t = (mgh+1/2 mv

^{2})/t (10×10×20+1/2+10×10×10)/1 =2000+500=2500 W=2.5 KW**Q5.**A bucket tied to a string is lowered at a constant acceleration of g/4. If the mass of the bucket is m and is lowered by a distance d, the work done by the string will be?

**Q6.**A 20 kg ball moving with a velocity 6 ms

^{-1}collides with a 30 kg ball initially at rest .if both of them coalesce ,then final velocity of the combined mass is ?

Solution

From conservation of momentum. Momentum before collision =Momentum after collision m

From conservation of momentum. Momentum before collision =Momentum after collision m

_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}20×6+30×0=20v+30v ∴20×6=50v Or v=120/50=2.4ms^{-1}**Q7.**A body of mass 3 kg acted upon by a constant force is displaced by Smetre, given by relationS= 1/3 t

^{2}, where t is in second. Work done by the force in 2 seconds is?

Solution

Given that, S=1/3 t

Given that, S=1/3 t

^{2}v=dS/dt=2/3 t; a=(d^{2}S)/(dt^{2})=2/3 F=ma=3×2/3=2N; Work=2×1/3 t^{2}At t=2 Work =2×1/3×2×2=8/3 J**Q8.**The blocks of mass m each are connected to a spring of spring constant k as shown in figure. The maximum displacement in the block is?

Solution

1/2 kx

1/2 kx

^{2}=1/2 mv^{2}+1/2 mv^{2}=mv^{2}x=√((2mv^{2})/k)**Q9.**In an elastic collision of two particles the following is conserved?

Solution

Total kinetic energy of both the particles

Total kinetic energy of both the particles

**Q10.**A rod AB of mass 10 kg and length 4 m rests on a horizontal floor with end A fixed so as to rotate it in vertical plane about perpendicular axis passing through A. If the work done on the rod is 100 J, the height to which the end B be raised vertically above the floor is?: