NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers
NCERT solutions for class 6 maths chapter 2 Whole Numbers Topic: Predecessor and Successor
Q1 Write the predecessor and successor of 19; 1997; 12000; 49; 100000.
Answer: The predecessor and successor of:

19:

Predecessor : 18

Successor : 20

1997:

Predecessor : 1996

Successor : 1998

12000

Predecessor : 11999

Successor : 12001

49:

Predecessor : 48

Successor : 50

100000:

Predecessor : 99999

Successor : 100001
Q2 Is there any natural number that has no predecessor?
Answer: Every natural number has a predecessor. Although, it is interesting to know that the predecessor of 1 is not a natural number.
Q3 Is there any natural number which has no successor? Is there a last natural number?
Answer: Every natural number has a successor. There is no last natural number. There are infinite natural numbers.
NCERT solutions for class 6 maths chapter 2 Whole Numbers Topic: Whole Numbers
Q1 Are all natural numbers also whole numbers?
Answer: Yes, all the natural numbers are whole numbers. But, all whole numbers are not natural numbers.
Natural numbers = 1, 2, 3, 4, ....
Whole numbers= 1, 2, 3, 4, ....
Q2 Are all whole numbers also natural numbers?
Answer: No, all whole numbers are not natural numbers. 0 is a whole number, but it is not a natural number.
Q3 Which is the greatest whole number?
Answer: There are infinite whole numbers. Hence, there is no greatest whole number. Every whole number you can think of has a successor, which is greater than than the number.
NCERT solutions for class 6 maths chapter 2 Whole Numbers Exercise: 2.1
Q1 Write the next three natural numbers after 10999.
Answer: Given, 10999
The next three natural numbers are:
10999 + 1 = 11000
10999 + 2 = 11001
10999 + 3 = 11002
Q2 Write the three whole numbers occurring just before 10001.
Answer: Given, 10001
Three whole numbers occurring just before are:
11001  1 = 10000
11001  2 = 9999
11001  3 = 9998
Q3 Which is the smallest whole number?
Answer: The smallest whole number is 0. It has no whole number predecessor.
Q4 How many whole numbers are there between 32 and 53?
Answer: Given numbers are: 32 and 53
Number of whole numbers between 32 and 53 = (5332)  1 = 21  1 = 20
There are 20 whole numbers between 32 and 53
Q5 Write the successor of :
(a) 2440701 (b) 100199 (c) 1099999 (d) 2345670
Answer: The successor of following numbers are:

(a) 2440701

(b) 100199

(c) 1099999

(d) 2345670
Q6 Write the predecessor of :
(a) 94 (b) 10000 (c) 208090 (d) 7654321
Answer: The predecessor of the following numbers are:

(a) 94

(b) 10000

(c) 208090

(d) 7654321
Q7 In each of the following pairs of numbers, state which whole number is on the left of the other number on the number line. Also write them with the appropriate sign (>, <) between them.
(a) 530, 503 (b) 370, 307 (c) 98765, 56789 (d) 9830415, 10023001
Answer: The number on the left on the number line is smaller than the number that is on the right on the number line.

(a) 530, 503

is on the left.

(b) 370, 307

is on the left.

(c) 98765, 56789

is on the left.

(d) 9830415, 10023001

is on the left.
Q8 Which of the following statements are true (T) and which are false (F)?
(a) Zero is the smallest natural number.
(b) 400 is the predecessor of 399.
(c) Zero is the smallest whole number.
(d) 600 is the successor of 599.
(e) All natural numbers are whole numbers.
(f) All whole numbers are natural numbers.
(g) The predecessor of a twodigit number is never a singledigit number.
(h) 1 is the smallest whole number.
(i) The natural number 1 has no predecessor.
(j) The whole number 1 has no predecessor.
(k) The whole number 13 lies between 11 and 12.
(l) The whole number 0 has no predecessor.
(m) The successor of a twodigit number is always a twodigit number
Answer:
(a) Zero is the smallest natural number.  False. 0 is not a natural number.
(b) 400 is the predecessor of 399.  False. 400 is the successor of 399.
(c) Zero is the smallest whole number.  True.
(d) 600 is the successor of 599.  True
(e) All natural numbers are the whole numbers. True.
(f) All whole numbers are natural numbers. False. 0 is a whole number but not a natural number.
(g) The predecessor of a twodigit number is never a singledigit number. False. The predecessor of 10 is 9.
(h) 1 is the smallest whole number.  False. 0 is the smallest whole number.
(i) The natural number 1 has no predecessor.  True.
(j) The whole number 1 has no predecessor.  False. The whole number 1 has 0 as its predecessor.
(k) The whole number 13 lies between 11 and 12. False. The whole number 13 lies on the right side of 12 on the number line.
(l) The whole number 0 has no predecessor. True.
(m) The successor of a twodigit number is always a twodigit number False. The successor of 99 is 100.
NCERT solutions for class 6 maths chapter 2 Whole Numbers Topic: Properties of Whole Numbers
Q Find : 7 + 18 + 13; 16 + 12 + 4.
Answer: 7 + 18 + 13; 16 + 12 + 4
NCERT solutions for class 6 maths chapter 2 Whole Numbers Exercise: 2.2
Q1 Find the sum by suitable rearrangement:
(a) 837 + 208 + 363 (b) 1962 + 453 + 1538 + 647
Answer: Sum by suitable rearrangement:

(a) 837 + 208 + 363

(b) 1962 + 453 + 1538 + 647
Q2 Find the product by suitable rearrangement:
(a) 2 × 1768 × 50 (b) 4 × 166 × 25
(c) 8 × 291 × 125 (d) 625 × 279 × 16
(e) 285 × 5 × 60 (f) 125 × 40 × 8 × 25
Answer: The product of the following by suitable rearrangement are:

(a)

(b)

(c)

(d)

(e)

(f)
Q3 Find the value of the following:
(a) 297 × 17 + 297 × 3 (b) 54279 × 92 + 8 × 54279
(c) 81265 × 169 – 81265 × 69 (d) 3845 × 5 × 782 + 769 × 25 × 218
Answer:

(a)
Using Distributive law. 
(b)
Using Commutative under multiplication
Using Distributive law. 
(c)
Using Distributive law. 
(d)
Using distributive law.
Q4 Find the product using suitable properties.
(a) 738 × 103 (b) 854 × 102
(c) 258 × 1008 (d) 1005 × 168
Answer: The product of the folllowing using suitable properties are:

(a)
Using distributive law. 
(b)
Using distributive law. 
(c)
Using Distributive law. 
(d)
Using Distributive law.
Q5 A taxidriver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs rupees 44 per litre, how much did he spend in all on petrol?
Answer: Amount of petrol filled on Monday =
Amount of petrol filled on Tuesday =
Total amount of petrol =
Cost of 1 litre of petrol =
Cost of of petrol =
Q6 A vendor supplies 32 litres of milk to a hotel in the morning and 68 litres of milk in the evening. If the milk costs rupees 45 per litre, how much money is due to the vendor per day?
Answer: Amount of milk supplied in the morning =
Amount of milk supplied in the evening =
Total amount of petrol =
Cost of 1 litre of milk =
Cost of of milk =
Q7 Match the following:
(i) 425 × 136 = 425 × (6 + 30 +100) (a) Commutativity under multiplication.
(ii) 2 × 49 × 50 = 2 × 50 × 49 (b) Commutativity under addition.
(iii) 80 + 2005 + 20 = 80 + 20 + 2005 (c) Distributivity of multiplication over addition.
Answer:
(i) 
(c) Distributivity of multiplication over addition. 
(ii) 
(a) Commutativity under multiplication. 
(iii) 
(b) Commutativity under addition. 
NCERT solutions for class 6 maths chapter 2 Whole Numbers Topic: Patterns in Whole Numbers
Q1 Which numbers can be shown only as a line?
Answer: can be shown only as a line. They cannot be shown as a rectangle or square or triangle.
Q2 Which can be shown as squares?
Answer: and can be shown as squares.
4: 2 rows and 2 columns.
9: 3 rows and 3 columns
Q3 Which can be shown as rectangles?
Answer: can be shown as rectangles. (Note: We are not counting squares as rectangles here)
Q4 Write down the first seven numbers that can be arranged as triangles, e.g. 3, 6, ...
Answer: 3, 6, 10, 15, 21, 28, 36.
Q5 Some numbers can be shown by two rectangles, for example
Give at least five other such examples.
Answer: We can represent a number by two rectangles. for example 12 = 3 x 4 or 2 x 6
five other such examples are :

24 = 12 x 2 or 24 = 6 x 4

18 = 9 x 2 or 18 = 3 x 6

15 = 15 x 1 or 15 = 3 x 5

30 = 10 x 3 or 30 = 5 x 6

40 = 10 x 4 or 40 = 5 x 8.
NCERT solutions for class 6 maths chapter 2 Whole Numbers Exercise: 2.3
Q1 Which of the following will not represent zero:
(a) 1 + 0 (b) 0 × 0 (c) 0/ 2 (d) (1010)/2
Answer:

(a) 1 + 0
It does not represent zero. 
(b) 0 × 0
It represents zero. 
(c)
It represents zero. 
(d)
It represents zero.
Q2 If the product of two whole numbers is zero, can we say that one or both of them will be zero? Justify through examples.
Answer: If the product of 2 whole numbers is zero, then one of them is definitely zero.
For example, 0 x 2 = 0 and 17 x 0 = 0
If the product of 2 whole numbers is zero, then both of them may be zero.
0 x 0 = 0
However, 2 x 3 = 6 (Since numbers to be multiplied are not equal to zero, the result of the product will also be nonzero.)
Q3 If the product of two whole numbers is 1, can we say that one or both of them will be 1? Justify through examples.
Answer: If the product of 2 numbers is 1, then both the numbers have to equal to 1.
For example, 1 x 1 = 1
However, 1 x 6 = 6
Clearly, the product of two whole numbers will be 1 in the situation when both numbers to be multiplied are 1.
Q4 Find using distributive property :
(a) 728 101 (b) 5437 1001 (c) 824 25 (d) 4275 125 (e) 504 35
Answer:

(a) 728 101= 728 (100 + 1)

= 728 100 + 728 1

= 72800 + 728

= 73528

(b) 5437 1001 = 5437 (1000 + 1)

= 5437 1000 + 5437 1

= 5437000 + 5437

= 5442437

(c) 824 25 (800 + 24) 25 = (800 + 25  1) 25

=800 25+25 x 251 25

= 20000 + 625  25

= 20000 + 600

= 20600

(d) 4275 125 = (4000 + 200 + 100  25) 125

= 4000 125 + 200 125 + 100 125  25 125

= 500000 + 25000 + 12500  3125

= 534375

(e) 504 35 = (500 + 4) 35

= 500 x 35 +4 35

= 17500 + 140

= 17640
Q5 Study the pattern :
1 8 + 1 = 9 1234 8 + 4 = 9876
12 8 + 2 = 98 12345 8 + 5 = 98765
123 8 + 3 = 987
Write the next two steps. Can you say how the pattern works?
(Hint: 12345 = 11111 + 1111 + 111 + 11 + 1).
Answer: 123456 8 + 6 = 987648 + 6 = 987654
1234567 8 + 7 = 9876536 + 7 = 9876543
Yes, the pattern works.
As 123456 = 111111 + 11111 + 1111 + 111 + 11 + 1,
123456 8 = (111111 + 11111 + 1111 + 111 + 11 + 1) 8
= 111111 8 + 11111 8 + 1111 8 + 111 8 + 11 8 + 1 8
= 888888 + 88888 + 8888 + 888 + 88 + 8
= 987648
And,
123456 8 + 6 = 987648 + 6 = 987648
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Reference Books Solutions
 HC Verma Part 1
 HC Verma Part 2
 RD Sharma Class 9
 RD Sharma Class 10
 RS Aggarwal Class 10
 Lakhmir Singh Class 9
 Lakhmir Singh Class 10