9394949438

[LATEST]$type=sticky$show=home$rm=0$va=0$count=4$va=0

NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers

NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers- Comparing Numbers

Q1 Can you instantly find the greatest and the smallest numbers in each row?
2. 1473, 89423, 100, 5000, 310
3. 1834, 75284, 111, 2333, 450
4. 2853, 7691, 9999, 12002, 124

Answer: By Observing the number of digits and digit in the leftmost place can straight away tell us about the greatest and smallest number

(2) 1473, 89423, 100, 5000, 310

89423 is the greatest while 100 is the smallest

(3) 1834, 75284, 111, 2333, 450

75284 is the greatest 111 while is the smallest

(4) 2853, 7691, 9999, 12002, 124

12002 is the greatest while 124 is the smallest

Q2 Find the greatest and the smallest numbers.
(a) 4536, 4892, 4370, 4452
(b) 15623, 15073, 15189, 15800
(c) 25286, 25245, 25270, 25210
(d) 6895, 23787, 24569, 24659

Answer:

(a) 4536, 4892, 4370, 4452

4892 is the greatest while 4370 is the smallest

(b) 15623, 15073, 15189, 15800

15800 is the greatest while 15073 is the smallest
(c) 25286, 25245, 25270, 25210

25286 is the greatest while 25245 is the smallest
(d) 6895, 23787, 24569, 24659

24659 is the greatest while 6895 is the smallest

NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers: Number Formation

Q1 Use the given digits without repetition and make the greatest and smallest 4-digit numbers.
(a) 2, 8, 7, 4
(b) 9, 7, 4, 1
(c) 4, 7, 5, 0
(d) 1, 7, 6, 2
(e) 5, 4, 0, 3

Answer:

(a) 2, 8, 7, 4

8742 is the greatest while 2478 is the smallest

(b) 9, 7, 4, 1

9741 is the greatest 1479 while is the smallest

(c) 4, 7, 5, 0

4750 is the greatest while 4057 is the smallest

(d) 1, 7, 6, 2

7621 is the greatest while 1267 is the smallest

(e) 5, 4, 0, 3

5430 is the greatest while 3045 is the smallest

Q2 Now make the greatest and the smallest 4-digit numbers by using any one digit twice.
(a) 3, 8, 7
(b) 9, 0, 5
(c) 0, 4, 9
(d) 8, 5, 1

Answer:

(a) 3, 8, 7

8873 is the greatest while 3387 is the smallest

(b) 9, 0, 5

9950 is the greatest while 5009 is the smallest

(c) 0, 4, 9

9940 is the greatest while 4009 is the smallest

(d) 8, 5, 1

8851 is the greatest while 1158 is the smallest

Q3 Make the greatest and the smallest 4-digit numbers using any four different digits with conditions as given.

(a) Digit 7 is always at one's place
Greatest - 9 8 6 7
Smallest - 1 0 2 7
(Note, the number cannot begin with the digit 0. Why?)

(b) Digit 4 is always at tens place
Greatest - _ _ 4 _
Smallest - _ _ 4 _

(c) Digit 9 is always at hundreds place
Greatest - _ 9 _ _
Smallest - _ 9 _ _
(d) Digit 1 is always at thousands place
Greatest- 1 _ _ _
Smallest - 1 _ _ _

Answer:

(b) Digit 4 is always at tens place
Greatest - 98 47
Smallest - 10 42

(c) Digit 9 is always at hundreds place
Greatest - 8 976
Smallest - 1 902


(d) Digit 1 is always at thousands place
Greatest- 1987
Smallest - 1023

Q4 Take two digits, say 2 and 3. Make 4-digit numbers using both the digits an equal number of times.
Which is the greatest number?
Which is the smallest number?
How many different numbers can you make in all?

Answer:

Greatest number - 3322

Smallest number - 2233

Different numbers are

2222, 2232, 2233, 2322, 2333, 2332, 2323, 2223, 3222, 3223, 3232, 3233, 3322, 3333, 3332, 3323

There are 16 in total

NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers: Arrangement of Numbers

Q1 Arrange the following numbers in ascending order :
(a) 847, 9754, 8320, 571
(b) 9801, 25751, 36501, 38802

Answer:

(a) 847, 8320, 8320, 571

571 < 847 < 8320 < 8320

(b) 9801, 25751, 25751, 38802

9801 < 25751 < 25751 < 38802

Q2 Arrange the following numbers in descending order :
(a) 5000, 7500, 85400, 7861
(b) 1971, 45321, 88715

Answer:

(a) 5000, 7500, 85400, 7861

85400 > 7861 > 5000 > 75000


(b) 1971, 45321, 88715

88715 > 45321 > 1971

NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers: Revisiting Place Value

Q1 Read and expand the numbers wherever there are blanks.

1. 50000- ________________________________________
2. 41000- ________________________________________
3. 47300- ________________________________________
4. 57630- ________________________________________

5. 29485________________________________________
6. 29085________________________________________

Answer:

1. 50000-Fifty thousand
2. 41000-forty one thousand
3. 47300- forty-seven thousand and three hundred
4. 57630- fifty-seven thousand six hundred

5. 29485- twenty-nine thousand and four hundred eighty-five
6. 29085- twenty-Nine Thousand and Eighty-Five

Q2 Read and expand the numbers wherever there are blanks.

4,57,928 _______________ _______________

4,07,928 _______________ _______________

4,00,829 _______________ _______________

4,00,029 _______________ _______________

Answer:

4,57,928 Four Lakhs Fifty Seven Thousand and Nine Hundred Twenty Eight

4,07,928 Four Lakhs Seven Thousand and Nine Hundred Twenty-Eight

4,00,829 Four Lakhs Eight Hundred Twenty-Nine

4,00,029 Four Lakhs and Twenty-Nine

Q3 You have the following digits 4, 5, 6, 0, 7 and 8.

Using them, make five numbers each with 6 digits.

(a) Put commas for easy reading.

(b) Arrange them in ascending and descending order.

Answer:

Given, digits : 4, 5, 6, 0, 7, 8

Five 6-digit numbers are: 456078, 45708, 548760, 750486, 876540

NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers- Exercise 1.1

Q1 Fill in the blanks:

(a) 1 lakh = _______ ten thousand.

(b) 1 million = _______ hundred thousand.

(c) 1 crore = _______ ten lakh.

(d) 1 crore = _______ million.

(e) 1 million = _______ lakh.

Answer:

Let us take this as a physical world problem:

You went to a shop and you bought a toy of Rs. 100. You checked your pocket and found many notes but of only Rs.10

How many Rs.10 notes will you give to shopkeeper:

Well, it’s simple.

You will pay 10 notes.

How?

100/10 =10

The similar easy approach can be done in all the blanks,

Hint: Always remember to keep your eyes on a number of zeros

(a)1 lakh= 100000

1thousand= 1000

Ten thousand= 10*1000 = 10000

Therefore,

1 lakh/ 10 thousand =100000/10000 =10

So, 1lakh= 10 ten thousand

(b) 1 million= 1000000

1thousand= 1000

Hundred thousand= 100*1000 = 100000

Therefore,

1 million/ hundred thousand =1000000/100000 =10

So, 1milion= 10 hundred thousand

(c) 1 crore= 10000000 (7 zeros)

1lakh= 100000 (5 zeros)

Ten lakh= 10*1000 = 1000000( 6 zeros)

Therefore,

1 crore/ Ten lakh=10000000/1000000 =10

So, 1 crore= 10 Ten lakh

(d)1 crore= 10000000 (7 zeros)

1million= 100000 (6 zeros)

Therefore,

1 crore/ 1million=10000000/1000000 =10

So, 1 crore= 10 million

(e) 1 million= 1000000

1lakh= 100000

Therefore,

1million/ 10 lakh = 1000000/100000 =10

So, 1 million= 10 lakhs

See, all answers came out to be 10 but not everytime

Q2 Place commas correctly and write the numerals:

(a) Seventy three lakh seventy five thousand three hundred seven.

(b) Nine crore five lakh forty one.

(c) Seven crore fifty two lakh twenty one thousand three hundred two.

(d) Fifty eight million four hundred twenty three thousand two hundred two.

(e) Twenty three lakh thirty thousand ten.

Answer:

(a) Seventy three lakh seventy five thousand three hundred seven.

73,75,307

(b) Nine crore five lakh forty one.

9,05,00,041

(c) Seven crore fifty two lakh twenty one thousand three hundred two.

7,52,21,302

(d) Fifty eight million four hundred twenty three thousand two hundred two.

58,423,302

(e) Twenty three lakh thirty thousand ten.

23,30,010

Q3 Insert commas suitably and write the names according to Indian System of Numeration :

(a) 87595762 (b) 8546283 (c) 99900046 (d) 98432701

Answer:

(a) 8,75,95,762 : Eight crores seventy five lakhs ninety five thousand seven hundred sixty two

(b) 85,46,283 : Eighty five lakhs forty six thousand two hundred eighty three.

(c) 9,99,00,046 : Nine crores ninety nine lakhs and forty six.

(d) 9,84,32,701 : Nine crores eighty four lakhs thirty two thousand seven hundred and one.

NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers: Large Numbers in Practise

Q1 A box contains 2,00,000 medicine tablets each weighing 20 mg. What is the total weight of all the tablets in the box in grams and in kilograms? Answer:

Number of medicine tablets = 2,00,000

Weight of each medicine tablet = 20\ mg = \frac{20}{1000}\ g

Therefore, total weight = 2,00,000\times\frac{20}{1000}\ g

= 4,000\ g

= 4\ kg

Q2 A bus started its journey and reached different places with a speed of 60 km/hour.
(i) Find the total distance covered by the bus from A to D.
(ii) Find the total distance covered by the bus from D to G.
(iii) Find the total distance covered by the bus, if it starts from A and returns back to A.
(iv) Can you find the difference of distances from C to D and D to E?

Answer:

(i) Total distance from A to D = AB + BC + CD

= (4170 + 3410 + 2160)\ km = 9740\ km

(ii) Total distance between D to G = DE + EF + FG

= (8140 + 4830 + 2550)\ km = 15520\ km

(iii) Required distance = AD + DG + GA

= (4170 + 3410 + 2160 + 8140 + 4830 + 2550 + 1290)\ km = 26550 km

(iv) The difference of distances from C to D and D to E = (8140 - 2160)\ km = 5980\ km

NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers- Exercise 1.2

Q1 A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days.

Answer: Given,

  • Tickets sold on the first day of exhibition = 1094

  • Tickets sold on the second day = 1812

  • Tickets sold on the third day = 2050

  • Tickets sold on the last day = 2751

  • Total number of tickets sold =

\\ = 1094 + 1812 + 2050 + 2751 \\ = 7707

Total number of tickets sold = 7,707

Q2 Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?

 Answer:

The number of runs scored by Shekhar so far = 6980

The number of runs Shekhar wishes to score = 10,000

\therefore The number of runs required = 10,000 - 6,980

= 3,020\ runs

Therefore, Shekhar requires 3,020\ runs .

Q3 In an election, the successful candidate registered 5,77,500 votes and his nearest rival secured 3,48,700 votes. By what margin did the successful candidate win the election?

Answer: Given,

Number of votes registered by the successful candidate = 5, 77,500 votes

Number of votes registered by the rival candidate = 3, 48,700 votes

The margin = 5,77,500 - 3,48,700

= 2,28,800\ votes

Therefore, the successful candidate won the election by a margin of 2, 28,800 votes.

Q4 Kirti bookstore sold books worth 2,85,891 in the first week of June and books worth 4,00,768 in the second week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?

Answer: Given,

Worth of books sold in the first week = Rs \ 2,85,891

Worth of books sold in the second week = Rs\ 4, 00,768

Total sale in the two weeks = Rs. \ (2, 85,891 + 4, 00,768)

= Rs. \ 6, 86,659

Clearly, sales in the second week is greater than the first year by

Rs.\ (4, 00,768 - 2, 85,891) = Rs.\ 1, 14,877

Q5 Find the difference between the greatest and the least 5-digit number that can be written using the digits 6, 2, 7, 4, 3 each only once.

Answer:

Given, digits: 6, 2, 7, 4 and 3

Since, the digits have to be used only once, arrange them in ascending and descending order to get the minimum and maximum number.

Greatest number = 76,432

Smallest number = 23,467

\therefore The difference between the greatest and the least number
\\ = 76,432 - 23,467 \\ = 52,965

Q6 A machine, on an average, manufactures 2,825 screws a day. How many screws did it produce in the month of January 2006?

Answer:

Given,
Screws produced by machine in one day = 2, 825

We know, there are 31 days in January

\therefore Screws produced in 31 days = 2, 825 \times 31

= 87,575\ screws

Therefore, screws produced in January 2006 = 87,575

Q7 A merchant had rupees 78,592 with her. She placed an order for purchasing 40 radio sets at rupees 1200 each. How much money will remain with her after the purchase?

Answer:

Total money merchant has = Rs.\ 78, 592

Cost of one radio set = Rs.\ 1200

\therefore Cost of 40 radio sets = Rs.\ (1200 \times 40 )= Rs.\ 48,000

\therefore Money left with the merchant = Rs.\ (78,592 - 48,000) = Rs. \ 30,592

Therefore, money left with her after purchase = Rs. \ 30,592

Q8 A student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer? (Hint: Do you need to do both the multiplications?)

Answer: Given,

The student multiplied 7236\ by\ 65 instead of 56 .

Wrong answer = 7236 \times 65

Correct answer = 7236 \times 56

\therefore The difference in the answers = 7236 \times 65 - 7236 \times 56

= 7236 \times (65 - 56) = 7236 \times 9

= 65124

Hence, his answer was greater than the correct answer by 65124

Ques 9 - To stitch a shirt, 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain? (Hint: convert data in cm.)

Answer: We know, (1\ m = 100\ cm)

Given,

Length of cloth required to stitch a shirt = 2\ m\ 15\ cm = 215\ cm

Also, 40\ m = (40\times100)\ cm = 4000\ cm

Now, the cloth required for one shirt = 215\ cm

Number of shirts that can be stitched out = 4000\div215

4000 = (18\times215) + 130

Therefore, 18 shirts can be made from the given cloth.

And, 130\ cm = 1\ m\ 30\ cm cloth will remain unused.

Ques 10- Medicine is packed in boxes, each weighing 4 kg 500g. How many such boxes can be loaded in a van which cannot carry beyond 800 kg?

Answer- We know, (1\ kg = 1000\ g)

Weight of each medicine box= 4\ kg\ 500\ g = 4500\ g

Weight limit of the van = 800\ kg = (800\times1000)\ g = 8,00,000\ g

\therefore The number of boxes that can be loaded in the van = 800000\div4500

800000 = (4500\times177) + 3500

Hence, 177 boxes can be loaded in the van.

Ques 11- The distance between the school and a student’s house is 1 km 875 m. Every day she walks both ways. Find the total distance covered by her in six days.

Answer: We know, (1\ km = 1000\ m)

Given, - Distance between the school and her house = 1\ km\ 875\ m = 1875\ m

The distance she covers each day = [(1875\times2)\times6]\ m

(1875\times12)\ m = 22500\ m

= 22000\ m\ 500\ m = 22\ km\ 500\ m

Therefore, she will cover 22\ km\ 500\ m in six days.

Ques 12- A vessel has 4 litres and 500 ml of curd. In how many glasses, each of 25 ml capacity, can it be filled?

Answer:

We know, (1\ l = 1000\ ml)

Given, Capacity of vessel = 4\ l\ 500\ ml = 4500\ ml

The capacity of a single glass = 25\ ml

\therefore Number of glasses required to fill the vessel = 4500\div25

4500 = (180\times25)+0

Hence, 180 glasses are needed to fill the vessel completely.

NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers- Estimating to the Nearest Thousand Rounding Off

Ques- 1 Round off the given numbers to the nearest tens, hundreds and thousands.

Given Number Approximate to Nearest Rounded Form
75847 Tens ________________
75847 Hundreds ________________
75847 Thousands ________________
75847 Ten thousands ________________

Answer:

Given Number

Approximate to Nearest

Rounded Form

75847

Tens

75850

75847

Hundreds

75800

75847

Thousands

76000

75847

Ten thousands

80000

NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers- Exercise 1.3

Ques 1- Estimate each of the following using general rule
(a) 730 + 998 (b) 796 – 314 (c) 12,904 +2,888 (d) 28,292 – 21,496

Answer:

(a) 730 + 998
By rounding off to hundreds,

730 rounds off to 700,

998 rounds off to 1000.

Required sum = 700+1000

= 1700

(b) 796-314

By rounding off to hundreds,

796 rounds off to 800,

314 rounds off to 300.

Required difference = 800-300

= 500

(c) 12904+2822

By rounding off to thousands,

2904 rounds off to 13000,

2822 rounds off to 3000.

Required sum = 13000+3000

= 16000

(d) 28,296 - 21, 496

By rounding off to nearest thousands,

28,296 rounds off to 28000,

21,496 rounds off to 21,000

Required difference = 28,000 - 21,000

= 7,000

Q2 Give a rough estimate (by rounding off to nearest hundreds) and also a closer estimate (by rounding off to nearest tens) :
\\(a) 439 + 334 + 4,317 \\\\(b) 1,08,734 - 47,599 \\\\ (c) 8325- 491 \\\\ (d) 4,89,348 � 48,365

Answer:

(a) 439 + 334 + 4,317

Rounding off to nearest hundreds,

439 rounds off to 400

334 rounds off to 300

4317 rounds off to 4300,

Required sum = 400+300+4300

= 5000

Again, by rounding off to nearest tens,

439 rounds off to 440

334 rounds off to 330

4317 rounds off to 4320,

Required sum = 440+330+4320

= 5090

(b) 1,08,734 - 47,599

Rounding off to nearest hundreds,

1, 08,734 rounds off to 1, 08,700

47,599 rounds off to 47,600

Required difference = 1, 08,700 - 47,600

= 61100

Also, rounding off to nearest tens,

1, 08,734 rounds off to 1, 08,730

47,599 rounds off to 47,600

Required difference = 1, 08,730 - 47,600

= 61130

(c) 8325 - 491

Rounding off to nearest hundreds,

8325 rounds off to 8300

491 rounds off to 500

Required difference = 8300 - 500

= 7800

Also, rounding off to nearest tens,

8325 rounds off to 8330

491 rounds off to 490

Required difference = 8330 - 490

= 7840

(d) 4,89,348 - 48,365

Rounding off to nearest hundreds,

4,89,348 rounds off to 4,89,300

48,365 rounds off to 48,400

Required difference = 489300 - 48400

= 440900

Also, rounding off to nearest tens,

4,89,348 rounds off to 4,89,350

48,365 rounds off to 48,370

Required difference = 489350 - 48370

= 440980

Ques 3-Estimate the following products using the general rule:
(a) 578 × 161 (b) 5281 × 3491 (c) 1291 × 592 (d) 9250 × 29

Answer:

(a) 578\times161

Rounding off by general rule,

578 rounds off to 600

161 rounds off to 200,

Required product = 600\times200

= 120000

(b) 5281\times3491

Rounding off by the general rule,

5281 rounds off to 5000

3491 rounds off to 3500

Required product = 5000\times3500

= 1,75,00,000

(c) 1291\times592

Rounding off by general rule,

1291 rounds off to 1300

592 rounds off to 600

Required product = 1300\times600

= 780000

(d) 9250\times29

Rounding off by general rule,

9250 rounds off to 10000

29 rounds off to 30Required product = 10000 \times 30

= 300000

NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers- Topic Using Brackets

Ques 1- Write the expressions for each of the following using brackets.
(a) Four multiplied by the sum of nine and two.
(b) Divide the difference of eighteen and six by four.
(c) Forty five divided by three times the sum of three and two.

Answer:

(a) Four multiplied by the sum of nine and two.

= 4\times(9+2) = 4\times11 = 44
(b) Divide the difference of eighteen and six by four.

= \frac{18-6}{4} = \frac{12}{4} = 3
(c) Forty-five divided by three times the sum of three and two.

= \frac{45}{3(3+2)}

= \frac{45}{15} = 3

Ques 2- Write in Roman numerals.
1. 73
2. 92

Answer: In Roman numerals:
\\ 1.\ 73 - LXXIII \\ 2.\ 92 - XCII

Responsive Table
Chapter No. Chapter Name
Chapter 1 NCERT Solutions for class 6 maths chapter 1 Knowing Our Numbers
Chapter 2 NCERT solutions for class 6 maths chapter 2 Whole Numbers
Chapter 3 NCERT solutions for class 6 maths chapter 3 Playing with Numbers
Chapter 4 NCERT Solutions for class 6 maths chapter 4 Basic Geometrical Ideas
Chapter 5 NCERT solutions for class 6 maths chapter 5 Understanding Elementary Shapes
Chapter 6 NCERT solutions for class 6 maths chapter 6 Integers
Chapter 7 NCERT Solutions for class 6 maths chapter 7 Fractions
Chapter 8 NCERT solutions for class 6 maths chapter 8 Decimals
Chapter 9 NCERT solutions for class 6 maths chapter 9 Data Handling
Chapter 10 NCERT solutions for class 6 maths chapter 10 Mensuration
Chapter 11 NCERT Solutions for class 6 maths chapter 11 Algebra
Chapter 12 NCERT solutions for class 6 maths chapter 12 Ratio and Proportion
Chapter 13 NCERT solutions for class 6 maths chapter 13 Symmetry
Chapter 14 NCERT Solutions for class 6 maths chapter 14 Practical Geometry

Study Resources Quick Links

Want to know more

Want to Know More
Please fill in the details below:

INNER POST ADS

Latest IITJEE Articles$type=three$c=3$author=hide$comment=hide$rm=hide$date=hide$snippet=hide

Latest NEET Articles$type=three$c=3$author=hide$comment=hide$rm=hide$date=hide$snippet=hide

Name

Admissions,1,Alternating Current,60,AP EAMCET 2020,1,Basic Maths,2,BCECE 2020,1,best books for iit jee,2,best coaching institute for iit,1,best coaching institute for iit jee preparation,1,best iit jee coaching delhi,1,best iit jee coaching in delhi,2,best study material for iit jee,4,BITSAT Registration 2020,1,Blog,62,books for jee preparation,1,books recommended by iit toppers,3,Capacitance,3,CBSE,1,CBSE accounts exam,1,CBSE boards,1,CBSE NEET,9,cbse neet 2019,3,CBSE NEET 2020,1,cbse neet nic,1,Centre of Mass,2,Chemistry,58,Class 12 Physics,15,coaching for jee advanced,1,coaching institute for iit jee,2,Collision,2,COMEDK UGET 2020 Application Form,1,COMEDK UGET 2020 Exam Form,1,COMEDK UGET news,1,CUCET 2020,2,Current Electricity,4,CVR college,1,Electromagnetic Induction,3,Electronics,1,Electrostatics,3,Energy,1,Fluid Mechanics,4,Gravitation,2,GUJCET 2020 Application Form,1,Heat,4,iit admission,1,iit advanced,1,iit coaching centre,3,iit coaching centre in delhi,2,iit coaching classes,2,iit coaching in delhi,1,iit coaching institute in delhi,1,iit entrance exam,1,iit entrance exam syllabus,2,iit exam pattern,2,iit jee,5,iit jee 2019,3,iit jee advanced,2,iit jee books,3,iit jee coaching,2,iit jee exam,3,iit jee exam 2019,1,iit jee exam pattern,3,iit jee institute,1,iit jee main 2019,2,iit jee mains,3,iit jee mains syllabus,2,iit jee material,1,iit jee online test,3,iit jee practice test,3,iit jee preparation,6,iit jee preparation in delhi,2,iit jee preparation time,1,iit jee preparation tips by toppers,2,iit jee question paper,1,iit jee study material,3,iit jee study materials,2,iit jee syllabus,2,iit jee syllabus 2019,2,iit jee test,3,iit preparation,2,iit preparation books,5,iit preparation time table,2,iit preparation tips,2,iit syllabus,2,iit test series,3,IITJEE,100,IPU CET,1,JEE Advanced,83,jee advanced exam,2,jee advanced exam pattern,1,jee advanced paper,1,JEE Books,1,JEE Coaching Delhi,3,jee exam,3,jee exam 2019,6,JEE Exam Pattern,2,jee exam pattern 2019,1,jee exam preparation,1,JEE Main,85,jee main 2019,4,JEE Main 2020,1,JEE Main 2020 Application Form,2,JEE Main 2020 news,2,JEE Main 2020 Official Answer Key,1,JEE Main 2020 Registration,1,JEE Main 2020 Score,1,JEE Main application form,1,jee main coaching,1,JEE Main eligibility criteria,3,jee main exam,1,jee main exam 2019,3,jee main online question paper,1,jee main online test,3,JEE Main Paper-2 Result,1,jee main registration,2,jee main syllabus,2,JEE mains 2020,1,jee mains question bank,1,jee mains test papers,3,JEE Mock Test,2,jee notes,1,jee past papers,1,JEE Preparation,2,jee preparation in delhi,1,jee preparation material,4,JEE Study Material,1,jee syllabus,6,JEE Syllabus Chemistry,1,JEE Syllabus Maths,1,JEE Syllabus Physics,1,jee test series,3,KCET - 2020,1,Kinematics,1,Latest article,5,Latest Articles,61,Latest News,34,latest news about neet exam,1,Laws of Motion,2,Magnetic Effect of Current,3,Magnetism,3,MHT CET 2020,2,MHT CET 2020 exam schedule,1,Modern Physics,1,NCERT Solutions,15,neet,3,neet 2019,1,neet 2019 eligibility criteria,1,neet 2019 exam date,2,neet 2019 test series,2,NEET 2020,2,NEET 2020 Application Form,1,NEET 2020 Eligibility Criteria,1,NEET 2020 Registration,1,neet application form,1,neet application form 2019 last date,1,Neet Biology Syllabus,1,Neet Books,3,neet eligibility criteria,3,neet exam 2019,7,neet exam application,1,neet exam date,1,neet exam details,1,neet exam pattern,6,neet exam pattern 2019,2,neet examination,1,neet mock test 2019,1,Neet Notes,3,Neet Online Application Form,3,neet online test,2,neet past papers,1,neet physics syllabus,1,neet practice test,2,NEET preparation books,1,neet qualification marks,1,NEET question paper 2019,1,neet question papers,1,neet registration,1,Neet Study Material,3,neet syllabus,6,neet syllabus 2019,5,NEET Syllabus 2020,1,neet syllabus chemistry,1,neet syllabus for biology,1,neet syllabus for physics,1,neet test series,1,neet ug 2019,2,news,5,online study material for iit jee,1,Optical Instruments,1,Physics,110,physics books for iit jee,1,Power,1,Practical Physics,1,Quiz,5,Ray Optics,1,Rotational Motion,3,SHM,3,Simple Harmonic Motion,3,study materials for iit jee,1,Study Notes,110,study notes for iit jee,1,Thermodynamics,4,TS EAMCET Notification,2,Units and Dimensions,1,UPSEE 2020,1,UPSEE 2020 Application Form,2,UPSEE EXAM,1,Vectors,2,VITEE Application form,1,Wave Motion,3,Wave Optics,1,WBJEE 2020 Admit Card,1,WBJEE 2020 Answer Key,1,Work,1,
ltr
item
Best IIT JEE Coaching Institute in Delhi | NEET Coaching Institute in Delhi: Class 6 Maths Chapter 1 Knowing Our Numbers
Class 6 Maths Chapter 1 Knowing Our Numbers
https://1.bp.blogspot.com/-Yv01lPGLV1w/X2nRF1KvCRI/AAAAAAAAAGQ/TB6U06CJkzcL1rv7OkV97Zf6egCN5kW6wCNcBGAsYHQ/s320/b4b8f445-4290-4f1f-96b7-e69b7277545e.jpg
https://1.bp.blogspot.com/-Yv01lPGLV1w/X2nRF1KvCRI/AAAAAAAAAGQ/TB6U06CJkzcL1rv7OkV97Zf6egCN5kW6wCNcBGAsYHQ/s72-c/b4b8f445-4290-4f1f-96b7-e69b7277545e.jpg
Best IIT JEE Coaching Institute in Delhi | NEET Coaching Institute in Delhi
https://www.cleariitmedical.com/2020/09/NCERT-Solutions-for-Class-6-Maths-Chapter-1-Knowing-Our-Numbers.html
https://www.cleariitmedical.com/
https://www.cleariitmedical.com/
https://www.cleariitmedical.com/2020/09/NCERT-Solutions-for-Class-6-Maths-Chapter-1-Knowing-Our-Numbers.html
true
7783647550433378923
UTF-8
Loaded All Posts Not found any posts VIEW ALL Readmore Reply Cancel reply Delete By Home PAGES POSTS View All RECOMMENDED FOR YOU LABEL ARCHIVE SEARCH ALL POSTS Not found any post match with your request Back Home Sunday Monday Tuesday Wednesday Thursday Friday Saturday Sun Mon Tue Wed Thu Fri Sat January February March April May June July August September October November December Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec just now 1 minute ago $$1$$ minutes ago 1 hour ago $$1$$ hours ago Yesterday $$1$$ days ago $$1$$ weeks ago more than 5 weeks ago Followers Follow THIS CONTENT IS PREMIUM Please share to unlock Copy All Code Select All Code All codes were copied to your clipboard Can not copy the codes / texts, please press [CTRL]+[C] (or CMD+C with Mac) to copy