NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers
NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Comparing Numbers
Q1 Can you instantly find the greatest and the smallest numbers in each row?
2. 1473, 89423, 100, 5000, 310
3. 1834, 75284, 111, 2333, 450
4. 2853, 7691, 9999, 12002, 124
Answer: By Observing the number of digits and digit in the leftmost place can straight away tell us about the greatest and smallest number
(2) 1473, 89423, 100, 5000, 310
89423 is the greatest while 100 is the smallest
(3) 1834, 75284, 111, 2333, 450
75284 is the greatest 111 while is the smallest
(4) 2853, 7691, 9999, 12002, 124
12002 is the greatest while 124 is the smallest
Q2 Find the greatest and the smallest numbers.
(a) 4536, 4892, 4370, 4452
(b) 15623, 15073, 15189, 15800
(c) 25286, 25245, 25270, 25210
(d) 6895, 23787, 24569, 24659
Answer:
(a) 4536, 4892, 4370, 4452
4892 is the greatest while 4370 is the smallest
(b) 15623, 15073, 15189, 15800
15800 is the greatest while 15073 is the smallest
(c) 25286, 25245, 25270, 25210
25286 is the greatest while 25245 is the smallest
(d) 6895, 23787, 24569, 24659
24659 is the greatest while 6895 is the smallest
NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers: Number Formation
Q1 Use the given digits without repetition and make the greatest and smallest 4digit numbers.
(a) 2, 8, 7, 4
(b) 9, 7, 4, 1
(c) 4, 7, 5, 0
(d) 1, 7, 6, 2
(e) 5, 4, 0, 3
Answer:
(a) 2, 8, 7, 4
8742 is the greatest while 2478 is the smallest
(b) 9, 7, 4, 1
9741 is the greatest 1479 while is the smallest
(c) 4, 7, 5, 0
4750 is the greatest while 4057 is the smallest
(d) 1, 7, 6, 2
7621 is the greatest while 1267 is the smallest
(e) 5, 4, 0, 3
5430 is the greatest while 3045 is the smallest
Q2 Now make the greatest and the smallest 4digit numbers by using any one digit twice.
(a) 3, 8, 7
(b) 9, 0, 5
(c) 0, 4, 9
(d) 8, 5, 1
Answer:
(a) 3, 8, 7
8873 is the greatest while 3387 is the smallest
(b) 9, 0, 5
9950 is the greatest while 5009 is the smallest
(c) 0, 4, 9
9940 is the greatest while 4009 is the smallest
(d) 8, 5, 1
8851 is the greatest while 1158 is the smallest
Q3 Make the greatest and the smallest 4digit numbers using any four different digits with conditions as given.
(a) Digit 7 is always at one's place
Greatest  9 8 6 7
Smallest  1 0 2 7
(Note, the number cannot begin with the digit 0. Why?)
(b) Digit 4 is always at tens place
Greatest  _ _ 4 _
Smallest  _ _ 4 _
(c) Digit 9 is always at hundreds place
Greatest  _ 9 _ _
Smallest  _ 9 _ _
(d) Digit 1 is always at thousands place
Greatest 1 _ _ _
Smallest  1 _ _ _
Answer:
(b) Digit 4 is always at tens place
Greatest  98 47
Smallest  10 42
(c) Digit 9 is always at hundreds place
Greatest  8 976
Smallest  1 902
(d) Digit 1 is always at thousands place
Greatest 1987
Smallest  1023
Q4 Take two digits, say 2 and 3. Make 4digit numbers using both the digits an equal number of times.
Which is the greatest number?
Which is the smallest number?
How many different numbers can you make in all?
Answer:
Greatest number  3322
Smallest number  2233
Different numbers are
2222, 2232, 2233, 2322, 2333, 2332, 2323, 2223, 3222, 3223, 3232, 3233, 3322, 3333, 3332, 3323
There are 16 in total
NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers: Arrangement of Numbers
Q1 Arrange the following numbers in ascending order :
(a) 847, 9754, 8320, 571
(b) 9801, 25751, 36501, 38802
Answer:
(a) 847, 8320, 8320, 571
571 < 847 < 8320 < 8320
(b) 9801, 25751, 25751, 38802
9801 < 25751 < 25751 < 38802
Q2 Arrange the following numbers in descending order :
(a) 5000, 7500, 85400, 7861
(b) 1971, 45321, 88715
Answer:
(a) 5000, 7500, 85400, 7861
85400 > 7861 > 5000 > 75000
(b) 1971, 45321, 88715
88715 > 45321 > 1971
NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers: Revisiting Place Value
Q1 Read and expand the numbers wherever there are blanks.
1. 50000 ________________________________________
2. 41000 ________________________________________
3. 47300 ________________________________________
4. 57630 ________________________________________
5. 29485________________________________________
6. 29085________________________________________
Answer:
1. 50000Fifty thousand
2. 41000forty one thousand
3. 47300 fortyseven thousand and three hundred
4. 57630 fiftyseven thousand six hundred
5. 29485 twentynine thousand and four hundred eightyfive
6. 29085 twentyNine Thousand and EightyFive
Q2 Read and expand the numbers wherever there are blanks.
4,57,928 _______________ _______________
4,07,928 _______________ _______________
4,00,829 _______________ _______________
4,00,029 _______________ _______________
Answer:
4,57,928 Four Lakhs Fifty Seven Thousand and Nine Hundred Twenty Eight
4,07,928 Four Lakhs Seven Thousand and Nine Hundred TwentyEight
4,00,829 Four Lakhs Eight Hundred TwentyNine
4,00,029 Four Lakhs and TwentyNine
Q3 You have the following digits 4, 5, 6, 0, 7 and 8.
Using them, make five numbers each with 6 digits.
(a) Put commas for easy reading.
(b) Arrange them in ascending and descending order.
Answer:
Given, digits :
Five 6digit numbers are:
NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Exercise 1.1
Q1 Fill in the blanks:
(a) 1 lakh = _______ ten thousand.
(b) 1 million = _______ hundred thousand.
(c) 1 crore = _______ ten lakh.
(d) 1 crore = _______ million.
(e) 1 million = _______ lakh.
Answer:
Let us take this as a physical world problem:
You went to a shop and you bought a toy of Rs. 100. You checked your pocket and found many notes but of only Rs.10
How many Rs.10 notes will you give to shopkeeper:
Well, it’s simple.
You will pay 10 notes.
How?
100/10 =10
The similar easy approach can be done in all the blanks,
Hint: Always remember to keep your eyes on a number of zeros
(a)1 lakh= 100000
1thousand= 1000
Ten thousand= 10*1000 = 10000
Therefore,
1 lakh/ 10 thousand =100000/10000 =10
So, 1lakh= 10 ten thousand
(b) 1 million= 1000000
1thousand= 1000
Hundred thousand= 100*1000 = 100000
Therefore,
1 million/ hundred thousand =1000000/100000 =10
So, 1milion= 10 hundred thousand
(c) 1 crore= 10000000 (7 zeros)
1lakh= 100000 (5 zeros)
Ten lakh= 10*1000 = 1000000( 6 zeros)
Therefore,
1 crore/ Ten lakh=10000000/1000000 =10
So, 1 crore= 10 Ten lakh
(d)1 crore= 10000000 (7 zeros)
1million= 100000 (6 zeros)
Therefore,
1 crore/ 1million=10000000/1000000 =10
So, 1 crore= 10 million
(e) 1 million= 1000000
1lakh= 100000
Therefore,
1million/ 10 lakh = 1000000/100000 =10
So, 1 million= 10 lakhs
See, all answers came out to be 10 but not everytime
Q2 Place commas correctly and write the numerals:
(a) Seventy three lakh seventy five thousand three hundred seven.
(b) Nine crore five lakh forty one.
(c) Seven crore fifty two lakh twenty one thousand three hundred two.
(d) Fifty eight million four hundred twenty three thousand two hundred two.
(e) Twenty three lakh thirty thousand ten.
Answer:
(a) Seventy three lakh seventy five thousand three hundred seven.
(b) Nine crore five lakh forty one.
(c) Seven crore fifty two lakh twenty one thousand three hundred two.
(d) Fifty eight million four hundred twenty three thousand two hundred two.
(e) Twenty three lakh thirty thousand ten.
Q3 Insert commas suitably and write the names according to Indian System of Numeration :
(a) 87595762 (b) 8546283 (c) 99900046 (d) 98432701
Answer:
(a) : Eight crores seventy five lakhs ninety five thousand seven hundred sixty two
(b) : Eighty five lakhs forty six thousand two hundred eighty three.
(c) : Nine crores ninety nine lakhs and forty six.
(d) : Nine crores eighty four lakhs thirty two thousand seven hundred and one.
NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers: Large Numbers in Practise
Q1 A box contains 2,00,000 medicine tablets each weighing 20 mg. What is the total weight of all the tablets in the box in grams and in kilograms? Answer:
Number of medicine tablets =
Weight of each medicine tablet =
Therefore, total weight =
Q2 A bus started its journey and reached different places with a speed of 60 km/hour.
(i) Find the total distance covered by the bus from A to D.
(ii) Find the total distance covered by the bus from D to G.
(iii) Find the total distance covered by the bus, if it starts from A and returns back to A.
(iv) Can you find the difference of distances from C to D and D to E?
Answer:
(i) Total distance from A to D = AB + BC + CD
(ii) Total distance between D to G = DE + EF + FG
(iii) Required distance = AD + DG + GA
(iv) The difference of distances from C to D and D to E
NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Exercise 1.2
Q1 A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days.
Answer: Given,

Tickets sold on the first day of exhibition = 1094

Tickets sold on the second day = 1812

Tickets sold on the third day = 2050

Tickets sold on the last day = 2751

Total number of tickets sold =
Total number of tickets sold =
Q2 Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?
Answer:
The number of runs scored by Shekhar so far = 6980
The number of runs Shekhar wishes to score = 10,000
The number of runs required =
Therefore, Shekhar requires .
Q3 In an election, the successful candidate registered 5,77,500 votes and his nearest rival secured 3,48,700 votes. By what margin did the successful candidate win the election?
Answer: Given,
Number of votes registered by the successful candidate = 5, 77,500 votes
Number of votes registered by the rival candidate = 3, 48,700 votes
The margin
Therefore, the successful candidate won the election by a margin of votes.
Q4 Kirti bookstore sold books worth 2,85,891 in the first week of June and books worth 4,00,768 in the second week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?
Answer: Given,
Worth of books sold in the first week =
Worth of books sold in the second week =
Total sale in the two weeks =
Clearly, sales in the second week is greater than the first year by
Q5 Find the difference between the greatest and the least 5digit number that can be written using the digits 6, 2, 7, 4, 3 each only once.
Answer:
Given, digits: 6, 2, 7, 4 and 3
Since, the digits have to be used only once, arrange them in ascending and descending order to get the minimum and maximum number.
Greatest number =
Smallest number =
The difference between the greatest and the least number
Q6 A machine, on an average, manufactures 2,825 screws a day. How many screws did it produce in the month of January 2006?
Answer:
Given,
Screws produced by machine in one day =
We know, there are 31 days in January
Screws produced in 31 days =
Therefore, screws produced in January 2006 =
Q7 A merchant had rupees 78,592 with her. She placed an order for purchasing 40 radio sets at rupees 1200 each. How much money will remain with her after the purchase?
Answer:
Total money merchant has =
Cost of one radio set =
Cost of 40 radio sets =
Money left with the merchant =
Therefore, money left with her after purchase =
Q8 A student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer? (Hint: Do you need to do both the multiplications?)
Answer: Given,
The student multiplied instead of .
Wrong answer =
Correct answer =
The difference in the answers =
Hence, his answer was greater than the correct answer by
Ques 9  To stitch a shirt, 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain? (Hint: convert data in cm.)
Answer: We know,
Given,
Length of cloth required to stitch a shirt =
Also,
Now, the cloth required for one shirt =
Number of shirts that can be stitched out =
Therefore, 18 shirts can be made from the given cloth.
And, cloth will remain unused.
Ques 10 Medicine is packed in boxes, each weighing 4 kg 500g. How many such boxes can be loaded in a van which cannot carry beyond 800 kg?
Answer We know,
Weight of each medicine box=
Weight limit of the van =
The number of boxes that can be loaded in the van =
Hence, 177 boxes can be loaded in the van.
Ques 11 The distance between the school and a student’s house is 1 km 875 m. Every day she walks both ways. Find the total distance covered by her in six days.
Answer: We know,
Given,  Distance between the school and her house =
The distance she covers each day =
Therefore, she will cover in six days.
Ques 12 A vessel has 4 litres and 500 ml of curd. In how many glasses, each of 25 ml capacity, can it be filled?
Answer:
We know,
Given, Capacity of vessel =
The capacity of a single glass =
Number of glasses required to fill the vessel =
Hence, 180 glasses are needed to fill the vessel completely.
NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Estimating to the Nearest Thousand Rounding Off
Ques 1 Round off the given numbers to the nearest tens, hundreds and thousands.
Given Number Approximate to Nearest Rounded Form
75847 Tens ________________
75847 Hundreds ________________
75847 Thousands ________________
75847 Ten thousands ________________
Answer:
Given Number 
Approximate to Nearest 
Rounded Form 
75847 
Tens 

75847 
Hundreds 

75847 
Thousands 

75847 
Ten thousands 
NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Exercise 1.3
Ques 1 Estimate each of the following using general rule
(a) 730 + 998 (b) 796 – 314 (c) 12,904 +2,888 (d) 28,292 – 21,496
Answer:
(a)
By rounding off to hundreds,
730 rounds off to 700,
998 rounds off to 1000.
Required sum =
(b)
By rounding off to hundreds,
796 rounds off to 800,
314 rounds off to 300.
Required difference =
(c)
By rounding off to thousands,
2904 rounds off to 13000,
2822 rounds off to 3000.
Required sum =
(d)
By rounding off to nearest thousands,
28,296 rounds off to 28000,
21,496 rounds off to 21,000
Required difference =
Q2 Give a rough estimate (by rounding off to nearest hundreds) and also a closer estimate (by rounding off to nearest tens) :
Answer:
(a)
Rounding off to nearest hundreds,
439 rounds off to 400
334 rounds off to 300
4317 rounds off to 4300,
Required sum =
Again, by rounding off to nearest tens,
439 rounds off to 440
334 rounds off to 330
4317 rounds off to 4320,
Required sum =
(b)
Rounding off to nearest hundreds,
rounds off to
rounds off to
Required difference =
Also, rounding off to nearest tens,
rounds off to
rounds off to
Required difference =
(c)
Rounding off to nearest hundreds,
8325 rounds off to 8300
491 rounds off to 500
Required difference =
Also, rounding off to nearest tens,
8325 rounds off to 8330
491 rounds off to 490
Required difference =
(d)
Rounding off to nearest hundreds,
rounds off to
rounds off to
Required difference =
Also, rounding off to nearest tens,
rounds off to
rounds off to
Required difference =
Ques 3Estimate the following products using the general rule:
(a) 578 × 161 (b) 5281 × 3491 (c) 1291 × 592 (d) 9250 × 29
Answer:
(a)
Rounding off by general rule,
578 rounds off to 600
161 rounds off to 200,
Required product =
(b)
Rounding off by the general rule,
5281 rounds off to 5000
3491 rounds off to 3500
Required product =
(c)
Rounding off by general rule,
1291 rounds off to 1300
592 rounds off to 600
Required product =
(d)
Rounding off by general rule,
9250 rounds off to 10000
29 rounds off to 30Required product =
NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Topic Using Brackets
Ques 1 Write the expressions for each of the following using brackets.
(a) Four multiplied by the sum of nine and two.
(b) Divide the difference of eighteen and six by four.
(c) Forty five divided by three times the sum of three and two.
Answer:
(a) Four multiplied by the sum of nine and two.
(b) Divide the difference of eighteen and six by four.
(c) Fortyfive divided by three times the sum of three and two.
Ques 2 Write in Roman numerals.
1. 73
2. 92
Answer: In Roman numerals:
Study Resources Quick Links
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Reference Books Solutions
 HC Verma Part 1
 HC Verma Part 2
 RD Sharma Class 9
 RD Sharma Class 10
 RS Aggarwal Class 10
 Lakhmir Singh Class 9
 Lakhmir Singh Class 10