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JEE Advanced Physics Syllabus can be referred by the IIT aspirants to get a detailed list of all topics that are important in cracking the entrance examination. JEE Advanced syllabus for Physics has been designed in such a way that it offers very practical and application-based learning to further make it easier for students to understand every concept or topic by correlating it with day-to-day experiences. In comparison to the other two subjects, the syllabus of JEE Advanced for physics is developed in such a way so as to test the deep understanding and application of concepts..

Q1. Young’s double-slit experiment is carried with two thin sheets of thickness 10.4µm each and refractive index µ1=1.52 and µ2=1.40 covering the slits S1 and S2, respectively. If white light of range 400 nm to 780 nm is used, then which wavelength will form maxima exactly at point O, the centre of the screen?
  •  416 nm only
  •  624 nm only
  •  416 nm and 624 nm only
  •  None of these

Q2. Consider the optical system shown in figure. The point source of light S is having wavelength equal to λ. The light is reaching screen after reflection. For point P to be 2nd maxima, the value of λ would be (D>>d and d>>λ)
    12d2 / D
    6d2 / D
    3d2 / D
    24d2 / D

Q3. A beam of electron is used in an YDSE experiment. The slit width is d. When the velocity of electron is increased, then
  •   No interference is observed
  •   Fringe width increases
  •   Fringe width decreases
  •   Fringe width remains same

Q4. Microwaves from a transmitter are directed towards a plane reflector. A detector moves along the normal to the reflector. Between positions of 14 successive maxima, the detector travels a distance of 0.14 m. What is the frequency of transmitter?
  •  1.5x1010Hz
  •  3.0x1010Hz
  •  1.5x109Hz
  •  3.0x109Hz
Q5. In YDSE of equal width slits, if intensity at the center of screen is I0, then intensity at a distance of β/4 from the central maxima is
  •  I0
    I0 / 2
    I0 / 4
    I0 / 3
Q6. A ray of light of intensity I is incident on a parallel glass-slab at a point A as shown in fig. It undergoes partial reflection and refraction. At each reflection 25% of incident energy is reflected. The rays AB and A'B' undergo interference. The ratio Imax/Imin is
  •  4 : 1
  •  8 : 1
  •  7 : 1
  •  49 : 1
Q7. A double-slit arrangement produces interferences fringes for sodium light (λ=589nm) that have an angular separation of 3.50x10-3 rad. For what wavelength would the angular separation be 10% greater?
  •   527nm
  •   648nm
  •   722nm
  •   449nm
Q8. Two identical sources each of intensity I0 have a separation d=λ/8, where is the wavelength of the waves emitted by either source. The phase difference of the sources is π/4. The intensity distribution I(θ) in the radiation field as a function of θ, which specifies the direction from the sources to the distant observation point P is given by
  •   I(θ)=I0cos2θ
  •   I(θ)=
    I0 / 4
    cos2 (
    πθ / 8
  •   I(θ)= I0cos2θ [
    π / 8
  •   I(θ)=I0sin2θ
Q9. In a double-slit experiment, instead of taking slits of equal width, one slit is made twice as wide as the other. Then, in the interference pattern
  •  The intensities of both the maxima and the minima increases
  •  The intensity of the maximum increase and minima has zero intensity
  •  The intensity of the maxima decreases and that of minima increases
  •  The intensity of the maxima decreases and the minima has zero intensity
Q10. A double-slit experiment is immersed in a liquid of refractive index 1.33. It has slit separation of 1 mm and distance between the plane of slits and screen is 1.33 m. The slits are illuminated by a parallel beam of light whose wavelength in air is 6830Å. Then the fringe width is
  •   6.3x10-4
  •   8.3x10-4
  •  6.3x10-2
  •   6.3x10-5

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