JEE Advanced Physics Syllabus can be referred by the IIT aspirants to get a detailed list of all topics that are important in cracking the entrance examination. JEE Advanced syllabus for Physics has been designed in such a way that it offers very practical and application-based learning to further make it easier for students to understand every concept or topic by correlating it with day-to-day experiences. In comparison to the other two subjects, the syllabus of JEE Advanced for physics is developed in such a way so as to test the deep understanding and application of concepts.

**Q1. The best method to reduce random error is**

Solution

(c)

Random error is reduced by making large number of observations and taking mean of all the results

Random error is reduced by making large number of observations and taking mean of all the results

**Q3. Which of the following is the most precise instrument for measuring length?**

Solution

(c)

Screw gauge has minimum least count of 0.001 cm; hence, it is the most precise instrument

Screw gauge has minimum least count of 0.001 cm; hence, it is the most precise instrument

**Q4. Which of the following product of e, h, Î¼, G (where Î¼ is the permeability) be taken so that the dimensions of the product are same as that of speed of light?**

**Q5. A vernier callipers has 1 mm marks on the main scale. It has 20 equal divisions on the Vernier scale which match with 16 main scale divisions. For this Vernier callipers , the least count is**

**Q6. The length l, breadth b, and thickness t of a block of wood were measured with the help of a measuring scale. The result with permissible errors (in cm) are:**

l = 15.12 ± 0.01, b = 10.15 ± 0.01, and t = 5.28 ± 0.01. The percentage error in volume up to proper significant figures is

l = 15.12 ± 0.01, b = 10.15 ± 0.01, and t = 5.28 ± 0.01. The percentage error in volume up to proper significant figures is

**Q7. If frequency F, velocity V, and density D are considered fundamental units, the dimensional formula for momentum will be**

**Q8. The quantities A and B are related by the relation A/B=m, where m is the linear mass density and A is force, the dimensions of B will be**

**Q10. Dimensional formula for torque is**

Solution

(a)

Torque = force × distance =[M L

Torque = force × distance =[M L

^{2}T^{-2}]