JEE Advanced Physics Syllabus can be referred by the IIT aspirants to get a detailed list of all topics that are important in cracking the entrance examination. JEE Advanced syllabus for Physics has been designed in such a way that it offers very practical and application-based learning to further make it easier for students to understand every concept or topic by correlating it with day-to-day experiences. In comparison to the other two subjects, the syllabus of JEE Advanced for physics is developed in such a way so as to test the deep understanding and application of concepts.

**Q131. A room at 20°C is heated by a heater of resistance 20 ohm connected to 200 V mains. The temperature is uniform throughout the room and the heat is transmitted through a glass window of area 1 m**

^{2}and thickness 0.2 cm. Calculate the temperature outside. Thermal conductivity of glass is 0.2 cal/m C° s and mechanical equivalent of heat is 4.2 J/cal**Q132. Two spherical bodies A (radius 6 cm) and B (radius 18 cm) are at temperature T_1 and T_2 respectively. The maximum intensity in the emission spectrum of A is at 500 nm and in that of B is at 1500 nm. Considering them to be black bodies, what will be the ratio of the rate of total energy radiated by A to that of ?**

**Q133. The graph of elongation of rod of a substance A with temperature rise is shown in Figure. A liquid B contained in a cylindrical vessel made up of substance A, graduated in millitres at 0°C is heated gradually. The readings of the liquid level in the vessel corresponding to different temperatures are shown in the figure. The real volume expansivity of liquid is**

**Q134. It takes 10 min for an electric kettle to heat a certain quantity of water from 0°C to 100°C. It takes 54 min to convert this water at 100°C into steam. Then latent heat of steam is**

**Q135. A clock with a metal pendulum beating seconds keeps correct time at 0°C. If it loses 12.5 s a day at 25°C, the coefficient of linear expansion of metal of pendulum is**

Solution

135 (a) Loss of time due to heating a pendulum is given as ∆T=1/2 Î±∆Î¸T ⇒12.5=1/2×Î±×(25-0)℃×86400s ⇒Î±=1/86400/℃

135 (a) Loss of time due to heating a pendulum is given as ∆T=1/2 Î±∆Î¸T ⇒12.5=1/2×Î±×(25-0)℃×86400s ⇒Î±=1/86400/℃

**Q136. The loss in weight of a solid when immersed in a liquid at 0°C is W_0 and at t°C is W. If cubical coefficients of expansion of the solid and the liquid are Î³_s and Î³_L, respectively, then W is equal to**

**Q137. A uniform solid brass sphere is rotating with angular speed Ï‰_0 about a diameter. If its temperature is now increased by 100°C, what will be its new angular speed. (Given Î±_B=2.0×10**

^{(-5)}per °C)
Solution

**Q138. A steel tape is placed around the earth at the equator. When the temperature is 0°C neglecting the expansion of the earth, the clearance between the tape and the ground if the temperature of the tape rises to 30°C, is nearly (Î±_steel=11×10**

^{(-6)}/K)**Q139. Water falls from a height 500 m. The rise in temperature of water at bottom if whole of energy remains in water, will be (specific heat of water is c=4.2 kJ kg**

^{(-1)})