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D and F block elements Quiz-17

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IIT JEE exam which consists of JEE Main and JEE Advanced is one of the most important entrance exams for engineering aspirants. The exam is held for candidates who are aspiring to pursue a career in the field of engineering and technical studies. Chemistry is important because everything you do is chemistry! Even your body is made of chemicals. Chemical reactions occur when you breathe, eat, or just sit there reading. All matter is made of chemicals, so the importance of chemistry is that it's the study of everything..

Q1. Out of [Fe(CN)6]4-,[Ni(CN)4 ]2- and [Ni(CO)4]
  •  All have identical geometry
  •  All are paramagnetic
  •  All are diamagnetic
  •  [Fe(CN)6]4- is diamagnetic but [Ni(CN)4]2- and [Ni(CO)4] are paramagnetic
Solution
c
Q2.Alkaline KMnO4 (Baeyer’s reagent) can be used to test unsaturation in (A)
In this case
  •  Unsaturation in side-chain is affected
  •  Unsaturation in benzene nucleus is affected
  •  Unsaturation in both is affected
  •  Baeyer’s reagent cannot be used
Solution
a
Q3.  Increasing basic properties of TiO2,ZrO2 and HfO2 are in order
  •  TiO222
  •  HfO222
  •  HfO222
  •  ZrO222
  • Solution
    a

    Q4. Fulminating gold is
    •  AuCl3
    •  Au2 S
    •  Au(NH2)=NH
    •  H[Au(Cl)4]
    Solution
    c
    Q5.The stability of ferric ion is due to
    •  Half filled f-orbitals
    •  Half filled d-orbitals
    •  Completely filled f-orbitals
    •  Completely filled d-orbitals
    Solution
    b
    Q6. Cuprous ion is colourless while cupric ion is coloured because
    •  Both have half-filled p-and d-orbitals
    •  Both have unpaired electrons in d-orbitals
    • Cuprous ion has incomplete d-orbital and cupric ion has a complete d-orbital
    •  Cuprous ion as a complete d-orbital and cupric ion has an incomplete d-orbital
    Solution
    d
    Q7.Select the correct statement for the lesser number of oxidations states in 3d-series
    •  In the beginning of the series it can be due to the presence of too few electrons to loose or share
  •  Towards the end of the series, it can be ascribed to the presence of too many electrons and thus fewer empty orbitals to share electrons with the ligands
  •  Both (a) and (b) are correct
  •  None of the above is correct
  • Solution
    c
    Q8.The element which forms ions in dimeric state is
    •  Iron
    •  Mercury
    •  Cadmium
    •  Nickel
    Solution
    b
    Q9.The common oxidation state of the elements of lanthanide series is
    •  +1
    •  +3
    •  +4
    •   +6
    Solution
    b
    Q10. At 300℃,FeCl3
    •  Decomposes into FeCl2 and Cl2
    •  Decomposes into Fe and Cl2
    •  Sublimes to give liquid FeCl3
    • Sublimes to give gaseous dimer (FeCl3)2
    Solution
    d

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