IIT JEE exam which consists of JEE Main and JEE Advanced is one of the most important entrance exams for engineering aspirants. The exam is held for candidates who are aspiring to pursue a career in the field of engineering and technical studies.
Chemistry is important because everything you do is chemistry! Even your body is made of chemicals. Chemical reactions occur when you breathe, eat, or just sit there reading. All matter is made of chemicals, so the importance of chemistry is that it's the study of everything..
Q1. After the emission of a β-particle followed by α-particle from 〖_83^214〗Bi;the number of neutrons in the atom is
Solution
Q2.In the Schrodinger’s wave equation Ψ represents
Solution
(b)
Ψ=wave function
(b)
Ψ=wave function
Q3. Which of the following has the maximum penetrating power?
Solution
Part C
Part C
Q4. Which of the following projectiles is the best for bombarding the nuclide?
Solution
(d) Neutron is the best projectile
(d) Neutron is the best projectile
Q5.Which of the following is false?
Solution
(b)
1. True
2. False. The angular momentum depends only on the azimuthal quantum number
3. True
4. True
(b)
1. True
2. False. The angular momentum depends only on the azimuthal quantum number
3. True
4. True
Q6. Which of the following elements belongs to 4n-series?
Solution
(c) Pb-208 belongs to 4n series
(c) Pb-208 belongs to 4n series
Q7.The radius of second Bohr’s orbit is
Solution
Q8.Sodium chloride imparts a yellow colour to the Bunsen flame. This can be interpreted due to the
Solution
Part C
Part C
Q9.When n/p ratio of an isotope is greater than the stable isotope of that element, it emits
Solution
(a)
Isotope must have some number of proton, therefore β-particle will be emitted
(a)
Isotope must have some number of proton, therefore β-particle will be emitted
Q10. The electronic configuration of a diapositive ion M^(2+)is 2, 8,14 and its mass number is 56. The number of neutrons present is
Solution
(c)
Electronic configuration of M^(2+)=2+8+14=24e^-
Since two e^- has been lost in forming M^(2+) ion from metal, so total number of protons should be =24+2=26
Hence, number of neutrons =56-26=30
(c)
Electronic configuration of M^(2+)=2+8+14=24e^-
Since two e^- has been lost in forming M^(2+) ion from metal, so total number of protons should be =24+2=26
Hence, number of neutrons =56-26=30