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SOME BASIC CONCEPTS OF CHEMISTRY Quiz-50

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IIT JEE exam which consists of JEE Main and JEE Advanced is one of the most important entrance exams for engineering aspirants. The exam is held for candidates who are aspiring to pursue a career in the field of engineering and technical studies. Chemistry is important because everything you do is chemistry! Even your body is made of chemicals. Chemical reactions occur when you breathe, eat, or just sit there reading. All matter is made of chemicals, so the importance of chemistry is that it's the study of everything..

Q1.A metal oxide has the formula Z_2 O_3. It can be reduced by hydrogen to give free metal and water 0.2 g of the metal oxide requires 12 mg of hydrogen for complete reduction. The atomic weight of the metal is
  •  52
  •  104
  •  26
  •  78
Solution



Q2.1 mol of MnO_4^( 2-) in neutral aqueous medium disproportionates to :
  •  2/3 mol of MnO_4^( ⊖) and 1/3 mol of MnO_2
  •  1/3 mol of MnO_4^( ⊖) and 2/3 mol MnO_2
  •  1/3 mol of Mn_2 O_7 and 2/3 mol of MnO_2
  •  2/3 mol of Mn_2 O_7 and 1/3 mol of MnO_2
Solution

 




Q3.  A dark violet colour mixture in presence of dil. HCl changes to pale yellow solution. Mixture may contain
  •  MnO_4^-,Fe^(2+)
  •  MnO_4^-,C_2 O_4^(2-)
  •  I^-,Cr_2 O_7^(2-)
  •  None of correct
Solution

 



Q4. Of the following solutions the one that is acidic is
  •  ZnSO4(aq)
  •  NaAl(OH)4(aq)
  •  NaHCO3(aq)
  •  KNo3(aq)
Solution
((a) ZnSO_4+2H_2 O⟶Zn(OH)_2↓+2H_2 SO_4 acidic

Q5.H_2 S contains 94.11% sulphur; SO_2 contains 50% oxygen and H_2 O contains 11.11% hydrogen. Thus,
  •  Law of multiple proportion is followed
  •  Law of reciprocal proportion is followed
  •  Law of conservation of mass is followed
  •  All of the above
Solution
 (b) H_2 S 5.89 g H combines with=94.11 gS Hence, 1 g H combines with = 16g S SO_2 50 g O combine with=50 g S Hence, 1 g O combines with = 1 g S H_2 O 11.11 g H combines with=88.89 g O 1 g H combine with = 8 g O Thus, law of reciprocal proportion is followed

Q6. 100 mLof ozone at STP were passed through 100 mL of 10 volume H_2 O_2 solution. What is the volume strength of H_2 O_2 after the reaction?
  •  9.5
  •  9.0
  •  4.75
  •  4.5
Solution
(a) O_3 ⟶ O_2+O…(i)
H_2 O_2⟶H_2 O+O …(ii)
O + O⟶O_2…(iii)
1/2 vol 1/2 vol 1 vol
From equations (i) and (ii), we inter that 100 mL of O_3 at STP will produce 100 mL of molecular O_2 as such and 100 mL of oxygen molecule after reaction with H_2 O_2
This new volume of 100 mL of molecular oxygen after reaction with H_2 O_2 is contributed equally by O_3 and H_2 O_2. Thus, 50 mL of oxygen have been contributed by H_2 O_2
Again, we know
Volume of H_2 O_2× Volume strength of H_2 O_2 =Volume of O_2 at STP
∴100 mL of ’10 V’ H_2 O_2≡1000 mL of O_2 at STP After utilization of 50 mL of O_2, according to equation(iii), the balance (1000-50)=950 mL of O_2at STP are still retainable by 100 mL of H_2 O_2
Hence volume strength of H_2 O_2 after reaction (Volume of O_2 at STP)/(Volume of H_2 O_2 )=950/100=9.5 V
∴ Volume strength =9.5


Q7.The pH of 10^(-5) M HCl solution if 1 mL of it is diluted to 1000mL is
  •  5
  •  8
  •  7.02
  •  6.98
Solution
(d) Concentration of H^⊕ in 1 mL =10^(-5) M Concentration of H^⊕ in 1000 mL=10^(-8) M (pH=6.98)

Q8.Number of moles of NH_3 formed when 0.535 g of NH_4 Cl is completely decomposed by NaOH, is NH_4 Cl+NaOH→NH_3+NaCl+H_2 O
  •  0.01 mol
  •  5.35 mol
  •  1.7 g
  •  0.17 mol
Solution
(d) NH_4 Cl+NaOH→NH_3+NaCl+H_2 O 53.2 g =1 mol=17 g NH_3 0.535 g=0.17 g NH_3

Q9.A mixture of ethylene and excess of H_2 had a pressure of 600 mm Hg. The mixture was passed over nickel catalyst to convert ethylene to ethane. The pressure of the resultant mixture at the similar conditions of temperature and volume dropped to 400 mm Hg. The fraction of C_2 H_4 by volume in the original mixture is
  •  1/3 rd of the total volume
  •  1/4 th of the total volume
  •  2/3 rd of the total volume
  •  1/2 of the total volume
Solution

 




Q10.AgNO_3 gives white ppt with hypo changing to black after sometime. Black ppt is of a)
  •  Ag2S2O3
  •  Ag2SO4
  •  Ag2S4O6
  •  Ag2S
Solution

 



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SOME BASIC CONCEPTS OF CHEMISTRY Quiz-50
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