Chemistry Aptitude Quiz
Dear Readers,
IIT JEE exam which consists of JEE Main and JEE Advanced is one of the most important entrance exams for engineering aspirants. The exam is held for candidates who are aspiring to pursue a career in the field of engineering and technical studies.
Chemistry is important because everything you do is chemistry! Even your body is made of chemicals. Chemical reactions occur when you breathe, eat, or just sit there reading. All matter is made of chemicals, so the importance of chemistry is that it's the study of everything..
Q1. A compound contains C=90% andH=10%.Empirical formula of the compound is:
Solution
Q2.An organic compound contains C=40%,O=53.5%, and H=6.5%. The empirical formula of the compound is :
Solution
Q3. 
Solution
(b)
I. The principal group (-COOH) is lost
II. Same as is (I)
III. One (-COOH) group is lost, but still one (-COOH) group
is left in the product
(b)
I. The principal group (-COOH) is lost
II. Same as is (I)
III. One (-COOH) group is lost, but still one (-COOH) group
is left in the product
Q4. 
Solution
(a)
(III)+I effect of two Me groups>(IV) standard (NH_3)>(I) EWG (C=O) groups> (II) EWG two (C=O) groups
(a)
(III)+I effect of two Me groups>(IV) standard (NH_3)>(I) EWG (C=O) groups> (II) EWG two (C=O) groups
Q5.Statement 1: Essential oils are volatile and are insoluble in H2O
Statement 2: Essential oils are purified by steam distillation
Statement 2: Essential oils are purified by steam distillation
Solution
(a)
Both statements are correct and (R) is the correct explanation for (A). Steam distillation is used to separate volatile compounds which are insoluble in H_2 O
(a)
Both statements are correct and (R) is the correct explanation for (A). Steam distillation is used to separate volatile compounds which are insoluble in H_2 O
Q6. Statement 1: In organic layer test, Cl2, water is added to the sodium extract, which oxidesBr^⊝ and I^⊝ ion to Br2 and I2, respectively
Statement 2: Reduction potential of Cl2 is greater than that of Br2 and I2
Statement 2: Reduction potential of Cl2 is greater than that of Br2 and I2
Solution
(a)
Both (A) and (R) are correct and (R) is the correct explanation for (A),
Cl_2+ Br^⊝→〖2Cl〗^⊝+Br2
Cl_2 + I^⊝ → 〖2Cl〗^⊝ +I₂
Reduction potential (E° Cl₂/Cl^⊝ )> E ° Br₂/Br^⊝ orE° I₂/I^⊝
(a)
Both (A) and (R) are correct and (R) is the correct explanation for (A),
Cl_2+ Br^⊝→〖2Cl〗^⊝+Br2
Cl_2 + I^⊝ → 〖2Cl〗^⊝ +I₂
Reduction potential (E° Cl₂/Cl^⊝ )> E ° Br₂/Br^⊝ orE° I₂/I^⊝
Q7.Statement 1: Pentane and 3-methyl pentane are chain isomers
Statement 2: Pentane is a straight–chain alkane while 3-methyl pentane is a branched-chain alkane
Statement 2: Pentane is a straight–chain alkane while 3-methyl pentane is a branched-chain alkane
Solution
(d)
(A) is false. They are homologues; since the number of C atoms in pentane and 3-methyl pentane is not same, they cannot be isomers. (R) is true
(d)
(A) is false. They are homologues; since the number of C atoms in pentane and 3-methyl pentane is not same, they cannot be isomers. (R) is true
Q8. Statement 1: Dehydration of alcohol is an example of elimination reaction
Statement 2: When H2SO4 or H3PO4(concentrated ) are used as dehydrating agent, the mechanism is E_1
Statement 2: When H2SO4 or H3PO4(concentrated ) are used as dehydrating agent, the mechanism is E_1
Solution
(b)
Alcohols leading to conjugated alkenes are more easily dehydrated than the alcohols leading to non-conjugated alkenes
(b)
Alcohols leading to conjugated alkenes are more easily dehydrated than the alcohols leading to non-conjugated alkenes
Q9.Statement 1: Alkene A (Me_2 C=CMe_2) is more stable than alkene B (Et2 C=CEt2)
Statement 2: Baker-Nathan effect
Statement 2: Baker-Nathan effect
Solution
(a) Both (A) and (R) are correct and (R) is the correct explanation of (A). Hyperconjugation is also called Baker-Nathan effect. In (A), there are 12 α-H atoms, whereas B has only 8 α-H atoms
(a) Both (A) and (R) are correct and (R) is the correct explanation of (A). Hyperconjugation is also called Baker-Nathan effect. In (A), there are 12 α-H atoms, whereas B has only 8 α-H atoms
Q10. Statement 1: Equivalent weight of ozone in the change O3→O2 is 8.
Statement 2: 1 mole O3 of on decomposition gives3/2 moles of O2.
Statement 2: 1 mole O3 of on decomposition gives3/2 moles of O2.
Solution
(b) 2O3→3O2
2 mol O3≡3 mol O2=3×2 eq O2
EO=M/6
=48/6=8
(b) 2O3→3O2
2 mol O3≡3 mol O2=3×2 eq O2
EO=M/6
=48/6=8
