NUCLEI QUIZ-7
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JEE Advanced Physics Syllabus can be referred by the IIT aspirants to get a detailed list of all topics that are important in cracking the entrance examination. JEE Advanced syllabus for Physics has been designed in such a way that it offers very practical and application-based learning to further make it easier for students to understand every concept or topic by correlating it with day-to-day experiences. In comparison to the other two subjects, the syllabus of JEE Advanced for physics is developed in such a way so as to test the deep understanding and application of concepts.
Q2. Which of the following is in the increasing order for penetrating power
Solution
(a)
Penetration power of γ is 100 times of β, while that of β is 100 times of α
Q3. Assuming that about 20 MeV of energy is released per fusion reaction
〖 _1 H〗^2+〖 _1 H〗^2→+〖 _2 He〗^4+E+ other particles
Then the mass of 〖 _1 H〗^2 consumed per day in a fusion reactor of power 1 megawatt will approximately be
Q4 A radioactive sample S_1 having an activity of 5μCi has twice the number of nuclei as another sample S_2 which has an activity of 10 μCi. The half lives of S_1 and S_2 can be
Q5. Consider two arbitrary decay equations and mark the correct alternative(s) given below:
_92^230 U→n+ _92^229 U
_92^230 U→p+ _91^229 U
Given: M( _92^230 U)=230.033927 u,
M( _92^229 U)=229.03349 u,m_n=1.008665 u,
M( _91^229 Pa)=229.032089,m_p=1.007825,1 a.m.u=931.5 MeV
Q6. 1.00 kg of ^235 U undergoes fission process. If energy released per event is 200 MeV, then the total energy released is
Q8 The activity of a radioactive element decreases to one-third of the original activity I_0 in a period of nine years. After a further lapse of nine years, its activity will be b>
Q9. During a negative beta decay
Solution
(c)
Following nuclear reaction takes place
〖 _0 n〗^(-1) ⇒_ 〖 _1 H〗^1+〖 _(-1) e〗^0+v ̅
Q10. The binding energy per nucleon of O^16 is 7.97MeV and that of O^17 is 7.75 MeV. The energy (in MeV) required to remove a neutron from O^17 is
Solution
(c)
The equation is O^17 →_0 n^1+O^16
∴ Energy required = B.E. of O^17- B.E. of O^16
=17×7.75-16×7.97=4.23 MeV