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MOVING CHARGES AND MAGNETISM-7

JEE Advanced Physics Syllabus can be referred by the IIT aspirants to get a detailed list of all topics that are important in cracking the entrance examination. JEE Advanced syllabus for Physics has been designed in such a way that it offers very practical and application-based learning to further make it easier for students to understand every concept or topic by correlating it with day-to-day experiences. In comparison to the other two subjects, the syllabus of JEE Advanced for physics is developed in such a way so as to test the deep understanding and application of concepts.

moving charge and magnetism is an easy to understand and a highly scoring topic. It might have a 6% weightage in the entire JEE Physics portion. You can practice these questions on regular basis to know what are the important points to remember at the moment when that question comes.

Q1. Currents I_1 and I_2 flow in the wires shown in figure. The field is zero at distance x to the right of O. Then

•  x=(I1/I2 )a
•  x=(I2/I1 )a
•  x=((I1-I2)/(I1+I2 ))a
•  x=((I1+I2)/(I1-I2 ))a
Solution

Q2. A current I enters at A in square loop on uniform resistance and leaves at B. The ratio of magnetic field at E, the centre of square, due to segment AB to that due to DC is

•  1
•  2
•  3
•  4
Solution

Q3. A loop of flexible conducting wire of length l lies in magnetic filed B which is normal to the plane of lop. A current I is passed through the loop. The tension developed in the wire to open up is

•   Ï€/2 BIl
•  BIl/2
•  BIl/2Ï€
•  BIl
Solution

Q4. Three long, straight and parallel wires are arranged as shown in figure. The force experienced by 10 cm length of wire Q is

•  1.4×10^(-4)N towards the right
•  1.4×10^(-4)N towards the left
•  2.6×10^(-4)N towards the right
•  2.6×10^(-4)N towards the left
Solution

Q5. Figure shows an Amperian path ABCDA. Part ABC is in vertical plane PSTU while part CDA is in horizontal plane PQRS. Direction of circulation along the path is shown by an arrow near point B and at D: ∮B ⃗.dl ⃗ for this path according to Ampere’s law will be

•  (I1-I2+I3 ) Î¼0
•  (-I1+I2 ) Î¼0
•  I3 Î¼0
•  (I1+I2 ) Î¼0
Solution

Q6. Positively charged particles are projected into a magnetic field. If the direction of the magnetic field is along the direction of motion of the charge particles, the particles get
•  Accelerated
•  Decelerated
• Deflected
•  No change in velocity
Solution

Q7. A steady current is set up in a cubic network composed of wires of equal resistance and length d as shown in figure. What is the magnetic field at the centre P due to the cubic network?

•  Î¼0/4Ï€ 2I/d
•  Î¼0/4Ï€ 3I/(√2 d)
•  0
•  Î¼0/4Ï€ (Î¸Ï€ I)/d
Solution

Q8. Two particles X and Y having equal charges, after being accelerated through the samew potential difference, enter a region of uniform magnetic field and describe circular paths of radii R1 and R2, respectively. The ration of masses of X and Y is
•  (R1⁄R2 )^(1/2)
•  (R2/R1)
•  (R1⁄R2 )^2
•  (R1/R2)
Solution

Q9. A semicircular wire of radiusR, carrying curerentI, is placed in a magnetic field as shown in Figure. On left side ofX'X, magnitude field strength is2B0, and on right side ofX'X, magnitude field strength is2B0. Both fields are directed inside the page. The magnitude force experienced by the wire would be

•  3IB0 R
•  2IB0 R
•  √10 IB0 R
•  √5 IB0 R
Solution

Q10. A circular current carrying coil has a radius R. The distance from the centre of the coil on the axis where the magnetic induction will be (1/8)th of its value at the centre of the coil, is
•  R/√3
•  R√3
•  2R/√3
• (2√3)R
Solution

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