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JEE Advanced Physics Syllabus can be referred by the IIT aspirants to get a detailed list of all topics that are important in cracking the entrance examination. JEE Advanced syllabus for Physics has been designed in such a way that it offers very practical and application-based learning to further make it easier for students to understand every concept or topic by correlating it with day-to-day experiences. In comparison to the other two subjects, the syllabus of JEE Advanced for physics is developed in such a way so as to test the deep understanding and application of concepts.

Q1.  A conducing ring of mass 2 kg and radius 0.5 m is placed on a smooth horizontal plane. The ring carries a current of i=4A. A horizontal magnetic field B=10 T is switched on at time t=0 as shown in Figure. The initial angular acceleration of the ring will be

Solution

Q2.A wire is bent in the form of a circular arc with a straight portion AB. Magnetic induction at O when current I flowing in the wire, is

•  Î¼_0/2r(Ï€-Î¸+tan⁡Î¸)
•  (Î¼_0 I)/2Ï€r(Ï€+Î¸-tan⁡Î¸)
•  (Î¼_0 I)/2Ï€r(Ï€-Î¸+tan⁡Î¸)
•  (Î¼_0 I)/2Ï€r(-tan⁡Î¸+Ï€-Î¸)
Solution

Q3.  A consider a hypothetic spherical body. The body is cut into two parts about the diameter. One of hemispherical portion has mass distribution m whicle the other portion has identical charge distributionq. The body is rotated about the axis with constant speedÏ‰. Then, the ratio of magnetic moment to angular momentum is

•  q/2m
•  >q/2m
•  <q/2m
•  Cannot be calculated
Solution

Q4. A charged particle moves in a uniform magnetic field perpendicular to it, with a radius of curvature 4 cm. On passing through a metallic sheet it loses half of its kinetic energy. Then, the radius of curvature of the particle is
•  2cm
•  4cm
•  8cm
•  2√2 cm
Solution

Q5. A Q5.A charged particle is released from rest in a region of steady and uniform electric and magnetic fields which are parallel to each other. The particle will move in a

•  Straight line
•  circle
•  Helix
•  cycloid
Solution

Q6. Two concentric coils, each of radius equal to 2Ï€ cm, are placed at right angles to each other, Currents of 3A and 4A, respectively, are flowing through the two coils. The magnetic induction, in Wbm^(-2), at the centre of the coils will be

•  5×10^(-5)
•  7×10^(-5)
• 12×10^(-5)
•  10^(-5)
Solution

Q7.Same current i is flowing in three infinitely long wires along positive x-,y- and z-directions. The magnetic field at a point (0,0,-a) would be

•  (Î¼_0 i)/2Ï€a(j ̂-i ̂)
•  (Î¼_0 i)/2Ï€a(i ̂+j ̂)
•  (Î¼_0 i)/2Ï€a(i ̂-j ̂)
•  (Î¼_0 i)/2Ï€a(i ̂+j ̂+k ̂)
Solution

Q8.Two positive charge q_1 and q_2 are moving with velocities v_1 and v_2 when they are at points A andB, respectively, as shown in figure. The magnitude force experienced by charge q_1 due to the other charge q_2 is

•  (Î¼_0 q_1 q_2 v_1 v_2)/(8√2 Ï€a^2 )
•  T(Î¼_0 q_1 q_2 v_1 v_2)/(4√2 Ï€a^2 )
•  (Î¼_0 q_1 q_2 v_1 v_2)/(2√2 Ï€a^2 )
•  (Î¼_0 q_1 q_2 v_1 v_2)/(√2 Ï€a^2 )
Solution

Q9.An otherwise infinite, straight wire has two concentric loops os radii a and b carrying equal currents in opposite directions as shown in figure. The magnetic field at the common centre is zero for

•  a/b=(Ï€-1)/Ï€
•  a/b=Ï€/(Ï€+1)
•  a/b=(Ï€-1)/(Ï€+1)
•  a/b=(Ï€+1)/(Ï€-1)
Solution

Q10. The magnitude field at O due to current in the infinite wire forming a loop as shown in figure is

•  (Î¼_0 I)/4Ï€d(cos⁡〖Ï•_1+cos⁡〖Ï•_2 〗 〗)
•  Î¼_0/4Ï€ 2I/d(tan⁡〖Î¸_1 〗+〖tan⁡Î¸〗_2)
•  Î¼_0/4Ï€ I/d(sin⁡〖Ï•_1+sin⁡〖Ï•_2 〗 〗)
• Î¼_0/4Ï€ 2I/d(cos⁡〖Î¸_1 〗+〖cos⁡Î¸〗_2)
Solution

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