9394949438

[LATEST]$type=sticky$show=home$rm=0$va=0$count=4$va=0



Physics Quiz-4

Dear Readers,

If an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. Motion in a straight line is nothing but linear motion. As the name suggests, it’s in a particular straight line, thus it can be said that it uses only one dimension.


Q1. If a particle travels n equal distance with speeds v_1,v_2,…,v_n, then the average speed V ̅ of the particle will  be such that
  •  

  •  

  •  

  •  

Solution
t_1=s/v_1 ,t_2=s/v_2 ,…,t_n=s/v_n 
Average speed =(Total distance)/(Total time)









 V ̅=ns/(t_1+t_2+...+t_n )
ns/(s/v_1 +s/v_2 +...+s/v_n )=n/(1/v_1 +1/v_2 +...+1/v_n )
Taking reciprocal, we get 1/V ̅ =1/n (1/v_1 +1/v_2 +...+1/v_n )


Q2.The location of a particle is changed. What can we say about the displacement and distance covered by the particle?
  •  Both cannot be zero
  •  One of the two may be zero
  •  Both must be zero
  •  Both must be equal
Solution
If the location of a particle changes, then both distance and displacement must have some value.

Q3.  A ball is released from the top of a tower of height h. It takes time T to reach the ground. What is the position of the ball (from ground) after time T/3?
  •  h/9 m
  •  7h/9 m
  •  8h/9 m
  •  17h/18 m
Solution
We have h=1/2 gT^2
In T/3 second, distance fallen =1/2 g(T/3)^2=h/9
So position of the ball from the ground is
h-h/9=8h/9 m

Q4. The displacement-time graph of a body is shown in Fig












The velocity-time graph of the motion of the body will be
  •  

  •  

  •  

  •  

Solution
From 0 to t_1, velocity  is positive and constant as indicated by positive and constant slope
From t_1 to t_3, slope is zero, hence velocity is zero
From t_3 to t_4, velocity is negative and constant as indicated by negative and constant as indicated by negative and constant slope
Option (d) satisfies all these observations

Q5.The magnitude of displacement is equal to the distance covered in a given interval of time if the particle

  •  Moves with constant acceleration of time if the particle
  •  Moves with constant speed
  •  Moves in same direction with constant velocity or with variable velocity
  •  Moves with constant velocity
Solution
To have distance equal to magnitude of displacement, the particle has to move in the same direction. The velocity may or may not be constant.

Q6. 

       A thief is running away on a straight road in a jeep moving with a speed of 9 ms^(-1). A                       policeman chases him on a motor cycle moving at a speed of 10 ms^(-1). If the instantaneous         separation of the jeep from the motor cycle is 100 m, how long will it take for the policeman             to catch the thief?

  •  1 s
  •  19 s
  • 90 s
  •  100 s
Solution
Relative velocity of policeman w.r.t. the thief is 10-9=1 ms^(-1). Since the relative separation between them is 100 m, the time taken will be = relative separation relative velocity =100/1 = 100 s  

Q7.
The numerical value of the ratio of instantaneous velocity to instantaneous speed is
  •  Always less than one
  •  Always equal  to one
  •  Always more than one 
  •  Equal to or less than one
Solution
At any instant, the magnitudes of velocity and speed will be equal

Q8. A body is thrown vertically upwards from A, the top of a tower. It reaches the ground in time             t_1. If it is thrown vertically downwards from A with the same speed, it reaches the ground in           time t_2. If it is allowed to fall freely from A, then the time it takes to reach the ground is given         by

  •  t=(t_1+t_2)/2
  •  t=(t_1-t_2)/2
  •  t=(t_1-t_2)/2
  •  t=√(t_1/t_2)

Solution
Suppose the body be projected vertically upwards from A with a speed u_0
Using equation s=ut+(1/2)at^2, we get
For first case: -h=u_0 t_1-(1/2)gt_1^2  (i)
For second case: -h=-u_0 t_2-(1/2)gt_2^2  (ii)
(i)—(ii) ⇒0=u_0 (t_2+t_1 )+(1/2)g(t_2^2-t_1^2)
⇒u_0=(1/2)g(t_1-t_2)  (iii)
Putting the value of u_0 in (ii), we get
-h=-(1/2)g(t_1-t_2 ) t_2-(1/2)gt_2^2
⇒h=1/2 gt_1 t_2      (iv)
For third case: u=0,t=?
-h=0×t-(1/2)gt^2 or h=(1/2)gt^2 (v)
Combining Eq. (iv) and Eq. (v), we get
1/2 gt^2=1/2 gt_1 t_2 or t=√(t_1 t_2 )

Q9.

     The following graph shows the variation of velocity of a rocket with time. Then the maximum         height attained by the rocket is



  •  1.1 km
  •  5 km
  •  55 km
  •  None of these


Solution
Maximum height will be attained at 110 s. Because after 110 s, velocity becomes negative and rocket will start coming down. Area from 0 to 110 s is
1/2×110×1000=55,000 m=55 km

Q10. A train is moving at a constant speed V when its driver observes another train in front of him on the same track and moving in the same direction with constant speed v. If the distance between the trains is x, then what should be the minimum retardation of the train so as to avoid collision?
  •  (V+v)^2/x
  •  (V-v)^2/x
  •  (V+v)^2/2x
  • (V-v)^2/2x
Solution
Here relative velocity of the train w.r.t. other train is V-v. Hence, 0-(V-v)^2=2ax
or a=-(V-v)^2/2x  Minimum retardation =(V-v)^2/2x


author image

Written by: AUTHORNAME

AUTHORDESCRIPTION

Want to know more

Please fill in the details below:

INNER POST ADS

Latest IITJEE Articles$type=three$c=3$author=hide$comment=hide$rm=hide$date=hide$snippet=hide

Latest NEET Articles$type=three$c=3$author=hide$comment=hide$rm=hide$date=hide$snippet=hide

Name

Admissions,1,Alternating Current,60,AP EAMCET 2020,1,Basic Maths,2,BCECE 2020,1,best books for iit jee,2,best coaching institute for iit,1,best coaching institute for iit jee preparation,1,best iit jee coaching delhi,1,best iit jee coaching in delhi,2,best study material for iit jee,4,BITSAT Registration 2020,1,Blog,62,books for jee preparation,1,books recommended by iit toppers,3,Capacitance,3,CBSE,1,CBSE accounts exam,1,CBSE boards,1,CBSE NEET,9,cbse neet 2019,3,CBSE NEET 2020,1,cbse neet nic,1,Centre of Mass,2,Chemistry,58,Class 12 Physics,15,coaching for jee advanced,1,coaching institute for iit jee,2,Collision,2,COMEDK UGET 2020 Application Form,1,COMEDK UGET 2020 Exam Form,1,COMEDK UGET news,1,CUCET 2020,2,Current Electricity,4,CVR college,1,Digestion and Absorption Notes PDF,1,Electromagnetic Induction,3,Electronics,1,Electrostatics,3,Energy,1,Engineering & Medical,1,Fluid Mechanics,4,Gravitation,2,GUJCET 2020 Application Form,1,Heat,4,iit admission,1,iit advanced,1,iit coaching centre,3,iit coaching centre in delhi,2,iit coaching classes,2,iit coaching in delhi,1,iit coaching institute in delhi,1,iit entrance exam,1,iit entrance exam syllabus,2,iit exam pattern,2,iit jee,5,iit jee 2019,3,iit jee advanced,2,iit jee books,3,iit jee coaching,2,iit jee exam,3,iit jee exam 2019,1,iit jee exam pattern,3,iit jee institute,1,iit jee main 2019,2,iit jee mains,3,iit jee mains syllabus,2,iit jee material,1,iit jee online test,3,iit jee practice test,3,iit jee preparation,6,iit jee preparation in delhi,2,iit jee preparation time,1,iit jee preparation tips by toppers,2,iit jee question paper,1,iit jee study material,3,iit jee study materials,2,iit jee syllabus,2,iit jee syllabus 2019,2,iit jee test,3,iit preparation,2,iit preparation books,5,iit preparation time table,2,iit preparation tips,2,iit syllabus,2,iit test series,3,IITJEE,100,Important Biology Notes for NEET Preparation,1,IPU CET,1,JEE Advanced,83,jee advanced exam,2,jee advanced exam pattern,1,jee advanced paper,1,JEE Books,1,JEE Coaching Delhi,3,jee exam,3,jee exam 2019,6,JEE Exam Pattern,2,jee exam pattern 2019,1,jee exam preparation,1,JEE Main,85,jee main 2019,4,JEE Main 2020,1,JEE Main 2020 Application Form,2,JEE Main 2020 news,2,JEE Main 2020 Official Answer Key,1,JEE Main 2020 Registration,1,JEE Main 2020 Score,1,JEE Main application form,1,jee main coaching,1,JEE Main eligibility criteria,3,jee main exam,1,jee main exam 2019,3,jee main online question paper,1,jee main online test,3,JEE Main Paper-2 Result,1,jee main registration,2,jee main syllabus,2,JEE mains 2020,1,jee mains question bank,1,jee mains test papers,3,JEE Mock Test,2,jee notes,1,jee past papers,1,JEE Preparation,2,jee preparation in delhi,1,jee preparation material,4,JEE Study Material,1,jee syllabus,6,JEE Syllabus Chemistry,1,JEE Syllabus Maths,1,JEE Syllabus Physics,1,jee test series,3,KCET - 2020,1,Kinematics,1,Latest article,5,Latest Articles,61,Latest News,34,latest news about neet exam,1,Laws of Motion,2,Magnetic Effect of Current,3,Magnetism,3,MHT CET 2020,2,MHT CET 2020 exam schedule,1,Modern Physics,1,NCERT Solutions,15,neet,3,neet 2019,1,neet 2019 eligibility criteria,1,neet 2019 exam date,2,neet 2019 test series,2,NEET 2020,2,NEET 2020 Application Form,1,NEET 2020 Eligibility Criteria,1,NEET 2020 Registration,1,neet application form,1,neet application form 2019 last date,1,Neet Biology Syllabus,1,Neet Books,3,neet eligibility criteria,3,neet exam 2019,7,neet exam application,1,neet exam date,1,neet exam details,1,neet exam pattern,6,neet exam pattern 2019,2,neet examination,1,neet mock test 2019,1,Neet Notes,3,Neet Online Application Form,3,neet online test,2,neet past papers,1,neet physics syllabus,1,neet practice test,2,NEET preparation books,1,neet qualification marks,1,NEET question paper 2019,1,neet question papers,1,neet registration,1,Neet Study Material,3,neet syllabus,6,neet syllabus 2019,5,NEET Syllabus 2020,1,neet syllabus chemistry,1,neet syllabus for biology,1,neet syllabus for physics,1,neet test series,1,neet ug 2019,2,news,5,online study material for iit jee,1,Optical Instruments,1,Physics,110,physics books for iit jee,1,Power,1,Practical Physics,1,Quiz,5,Ray Optics,1,Rotational Motion,3,SHM,3,Simple Harmonic Motion,3,study materials for iit jee,1,Study Notes,110,study notes for iit jee,1,Thermodynamics,4,TS EAMCET Notification,2,Units and Dimensions,1,UPSEE 2020,1,UPSEE 2020 Application Form,2,UPSEE EXAM,1,Vectors,2,VITEE Application form,1,Wave Motion,3,Wave Optics,1,WBJEE 2020 Admit Card,1,WBJEE 2020 Answer Key,1,Work,1,
ltr
item
BEST NEET COACHING CENTER | BEST IIT JEE COACHING INSTITUTE | BEST NEET & IIT JEE COACHING: Motion In a Straight Line-Quiz-4
Motion In a Straight Line-Quiz-4
https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhdTkD1xPmS-I70VrXTbcq66geR-kNqW-5l_n7UhWd0HvrtMKxVSkGBDdi44Nut-6rRWJYXYkgZYFuCkY0vyHZex7MJgiND3yHwKJa_jaHBPYzhbekUwpsr6mMZpxDlbpL6m20vrdbWSVI/s320/QUIZ+BACK.png
https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhdTkD1xPmS-I70VrXTbcq66geR-kNqW-5l_n7UhWd0HvrtMKxVSkGBDdi44Nut-6rRWJYXYkgZYFuCkY0vyHZex7MJgiND3yHwKJa_jaHBPYzhbekUwpsr6mMZpxDlbpL6m20vrdbWSVI/s72-c/QUIZ+BACK.png
BEST NEET COACHING CENTER | BEST IIT JEE COACHING INSTITUTE | BEST NEET & IIT JEE COACHING
https://www.cleariitmedical.com/2021/07/motion-in-straight-line-quiz-4.html
https://www.cleariitmedical.com/
https://www.cleariitmedical.com/
https://www.cleariitmedical.com/2021/07/motion-in-straight-line-quiz-4.html
true
7783647550433378923
UTF-8
Loaded All Posts Not found any posts VIEW ALL Readmore Reply Cancel reply Delete By Home PAGES POSTS View All RECOMMENDED FOR YOU LABEL ARCHIVE SEARCH ALL POSTS Not found any post match with your request Back Home Sunday Monday Tuesday Wednesday Thursday Friday Saturday Sun Mon Tue Wed Thu Fri Sat January February March April May June July August September October November December Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec just now 1 minute ago $$1$$ minutes ago 1 hour ago $$1$$ hours ago Yesterday $$1$$ days ago $$1$$ weeks ago more than 5 weeks ago Followers Follow THIS CONTENT IS PREMIUM Please share to unlock Copy All Code Select All Code All codes were copied to your clipboard Can not copy the codes / texts, please press [CTRL]+[C] (or CMD+C with Mac) to copy

STAY CONNECTED