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JEE Advanced Physics Syllabus can be referred by the IIT aspirants to get a detailed list of all topics that are important in cracking the entrance examination. JEE Advanced syllabus for Physics has been designed in such a way that it offers very practical and application-based learning to further make it easier for students to understand every concept or topic by correlating it with day-to-day experiences. In comparison to the other two subjects, the syllabus of JEE Advanced for physics is developed in such a way so as to test the deep understanding and application of concepts..

Q1.  Switch S of the circuit shown in Fig is closed at t=0
If e denotes the induced e.m.f. in L and i the current flowing through the circuit at time t, then which of the following graphs correctly represents the variation of e with i?
•
•
•
•
Solution
b

Q2.A uniform magnetic field of induction B fills a cylindrical volume of radius R. A rod AB of length 2l is placed as shown in figure. If B is changing at the rate dB/dt, the emf that is produced by the changing magnetic field and that acts between the ends of the rod is
•   dB/dt l√(R2-l2 )
•  dB/dt l√(R2+l2 )
•  1/2 dB/dt l√(R2-l2 )
•  1/2 dB/dt l√(R2+l2 )
Solution
a

Q3.  The frequency of oscillation of current in the inductance is
•  1/(3√LC)
•  1/(6Ï€√LC)
•  1/√LC
•  1/(2Ï€√LC)
Solution
b

Q4.  A uniform but time-varying magnetic field B(t) exists in a circular region of radius a and is directed into the plane of the paper, as shown. The magnitude of the induced electric filed at point P at a distance r from the centre of the circular region
•  Is zero
•  Decreases as 1/r
•  Increases as r
•  Decreases as 1/r2
Solution
b

Q5.A wire of fixed length is wound on a solenoid of length l and radius r. Its self-inductance is found to be L. Now, if the same wire is wound on a solenoid of length l/2 and radius r/2, then the self-inductance will be
•  2L
•  4L
•  L
•  8L
Solution
a

Q6. 6. An e.m.f of 15 V is applied in a circuit containing 5 H inductance and 10 Î© resistance. The ratio of the currents at time t=∞ and t=1 s is
•  e(1/2)/(e(1/2)-1)
•  e2/(e2-1))
•  1-e-1
•  e-1
Solution
b

Q7.Calculate the inductance of a unit length of a double tape line as shown in fig, if the tapes are separated by a distance h which is considerably less than their width b
•  (Î¼0 h)/b
•  (Î¼0 h)/2b
•  (2Î¼0 h)/b
•  (√2 Î¼0 h)/bt
Solution
a

Q8. The figure shows certain wire segments joined together to form a coplanar loop. The loop is placed in a perpendicular magnetic field in the direction going into the plane of the figure. The magnitude of the field increases with time. I1 and I2 are the currents in the segments ab and cd . Then,
•   I1>I2
•  TI2>I1
•  I1is in the direction ba and I2is in the direction cd
•  I1is in the direction ab and I2is in the direction dc
Solution
d

Q9.In fig, the mutual inductance of a coil and a very long straight wire is M, the coil has resistance R and self-inductance L. The current in the wire varies according to the law i=at, where a is a constant and t is the time, the time dependence of current in the coil is
•  M/aR
•  MaRe-Rt/L
•  M/R e-tR/L
•  Ma/R(1-e-tR/L)
Solution
d

Q10. The current generator i_g, shown in figure, sends a constant current i through the circuit. The wire ab has a length l and mass m slide on the smooth, horizontal rails connected to i_g. The entire system lies in a vertical magnetic field B. The velocity of the wire as a function of time is

•  ilBt/m
•  ilBt/2m
•  2ilBt/m
•  ilBt/3m
Solution
a

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BEST NEET COACHING CENTER | BEST IIT JEE COACHING INSTITUTE | BEST NEET & IIT JEE COACHING: Electromagnetic Induction - Quiz 6
Electromagnetic Induction - Quiz 6