Electromagnetic induction : 2

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Q1.  A metal disc of radius a rotates with a constant angular velocity Ï‰ about itsaxis. The potential difference between the centre and the rim of the disc is (m=mass of elelctron, e=charge on electron
•   (mÏ‰2 a2)/e
•   1/2 (mÏ‰2 a2)/e
•  (eÏ‰2 a2)/2m
•  (eÏ‰2a2)/m
Solution
b

Q2.A 0.1 m long conductor carrying a current of 50 A is perpendicular to a magnetic field of 1.21 mT. The mechanical power to move the conductor with a speed of 1 ms-1 is
•   0.25 mW
•  6.25 mW
•  0.625 W
•  1 W
Solution
b

Q3.  A conducting square loop of side L and resistance R moves in its plane with a uniform velocity v perpendicular to one of its sides. A magnetic induction B, constant in time and space, pointing perpendicular to and into the plane of the loop exists everywhere
•  BLv/R clockwise
•  BLv/R anticlockwise
•  2BLv/R anticlockwise
•  Zero
Solution
d

Q4.  A flip coil consists of N turns of circular coils which lie in a uniform magnetic field. Plane of the coils is perpendicular to the magnetic filed as shown in figure. The coil is connected to a current integrator which measures the total charge passing through it. The coil is turned 180° about the diameter. The charge passing through the coil is
•  NBA/R
•  (√3 NBA)/2R
•  NBA/(√2 R)
•  2NBA/R
Solution
d

Q5.In figure, a square loop PQRS of side a and resistance r is placed near an infinitely long wire carrying a constant current I. The sides PQ and RS are parallel to the wire. The wire and the loop are in the same plane. The loop is rotated by 180° about an axis parallel to the long wire and passing through the mid-points of the sides QRand PS. The total amount of charge which passes through any point of the loop during rotation is
•  (Î¼0 Ia)/2Ï€r In2
•  (Î¼0 Ia)/Ï€r In2
•  (Î¼0 Ia2)/2Ï€r
•  Cannot be found because time of rotation is not given
Solution
b

Q6. In Fig (a) and (b), two air-cored solenoids P and Q have been shown. They are placed near each other. In Fig (a) when IP, the current in P, changes at the rate of 5 A s-1, an e.m.f. of 2 mV in induced in Q. The current in P is then switched off, and the current changing at 2 A s-1) is fed through Q as shown in the fig. What e.m.f. will be induced in P?
•  8×10-4 V
•  2×10^-3 V
•  5×10^-3 V
•  8×10-2 V
Solution
a

Q7. A square coil ACDE with its plane vertical is released from rest in a horizontal uniform magnetic filed B ⃗ of length 2L figure. The acceleration of the coil is
•  Less than g for all the time the loop crosses the magnetic field completely
•  Less than g when it enters the filed and greater than g when it comes out of the field
•  g all the time
•  Less than g when it enters and comes out of the field but equal to g when it is within the filed
Solution
d

Q8.A square conducting loop of side L is situated in gravity-free space. A small conducting circular loop of radius r(r≪L) is placed at the centre of the square loop, with its plane perpendicular to the plane of the square loop. The mutual inductance of the two coils is
•  (2√2 Î¼0 I)/L r2
•  T(√2 Î¼0 I0)/L r2
•  0
•  None of these
Solution
c

Q9.In the gives circuit fig, current through the 5 mH inductor in steady state is
•  8/3 A
•  2/3 A
•  1/3 A
•  2/3 A
Solution
b

Q10. Charge Q is uniformly distributed on a thin insulating ring of mass m which is initially at rest. To what angular velocity will the ring be accelerated when a magnetic fieldB, perpendicular to the plane of the ring, is switched on?
•  QB/2m
•  3QB/2m
•  QB/m
•  QB/4m
Solution
a

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Electromagnetic Induction - Quiz 2
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