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CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES QUIZ-15

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JEE Advanced is a high level exam that checks your concept by putting various types of questions. The questions are in a different format from JEE mains.m, herein the questions are : single correct multiple choice questions, multiple correct multiple choice questions, statement based questions and comprehension type questions.

Q1. The first ionization potential of Al is smaller than that of Mg because
  •  The atomic size of Al>Mg
  •  The atomic size of Al
  •   Al has one unpaired electron in p-orbital
  •   The atomic number of Al>Mg
Solution. (c)

Q2.The ionization potential of nitrogen is
  •  Same as that of oxygen
  •  Less than that of oxygen
  •  Greater than that of oxygen
  •   None of the above
Solution.
(a)

Q3.  Which of the following sets of elements is arranged in order of increasing electronegativity based on Pauling scale?
  •   S, Si, P
  •  P, S, Si
  •   S, P, Si
  •  P, Si, S
  • Solution. (d)
    Q4.  For Be, Z_eff=1.95 and for Be^(x+), Z_eff=2.30. Hence, ion is
    •  Be^+
    •  Be^(2+)
    •  Be^(3+)
    •  Be^0
    Solution (b)
    Q5. Ionic hydrides react with water to give
    •  A basic solution
    •   An acidic solution
    •  A hydride ion
    •   Protons
    Solution  (b)
    Q6. Going down in a group from F to I, which of the following properties increases
    •  Ionic radius
    •  Ionization energy
    • Oxidizing power
    •   Electronegativity
    Solution. (d)

    Q7.In which case bond length is shortened?
    •  When multiplicity occurs between atoms
    •  When electronegativities are different
    •  In both cases
    •   None of the above cases
    Solution
    (a)


    Q8.Ionization energy of the element X(g) is I and the electron affinity of X^+ (g) is E then
    •  I=E
    •  I=-E
    •  I=E/2
    •   I=-E/2
    Solution
    (b)

    Q9.The ionization energy of hydrogen is 13.6 eV and the first ionization energy of helium is 24.6 eV. Energy evolved in the following electron-gain process is
    •  -49.2 eV
    •  -54.4 eV
    •   -27.2 eV
    •  -79.0 eV
    Solution
    (a) AB_2 has bcc structure, A^(2+) possess face centred cubic lattice. B^- ions occupy all the (100%) tetrahedral voids. Thus each A^(2+) is in contact with B^- and each B^- with 4A^(2+) ions.

    Q10.Which pair is different from the others?
    •  Li-Mg
    •   B-Si
    •   Be-Al
    •  Li-Na
    Solution
    (b) All factual statements


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