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ALTERNATING CURRENT QUIZ-6

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JEE Advanced Physics Syllabus can be referred by the IIT aspirants to get a detailed list of all topics that are important in cracking the entrance examination. JEE Advanced syllabus for Physics has been designed in such a way that it offers very practical and application-based learning to further make it easier for students to understand every concept or topic by correlating it with day-to-day experiences. In comparison to the other two subjects, the syllabus of JEE Advanced for physics is developed in such a way so as to test the deep understanding and application of concepts.

Q1. At time t = 0, a battery of 10 V is connected across points A and B in the given circuit. If the capacitors have no charge initially, at what time (in second) does the voltage across them become 4 V?(Take ln 5 = 1.6, ln 3 = 1.1)
  •  2
  •  3
  •  2.5
  •  3/2
Solution


Q2. An8 μF capacitor is connected across a 220 V, 50 Hz line. What is the peak value of charge through the capacitor?
  •  2.5×10(-3) C
  •  2.5×10(-4) C
  •  5×10(-5) C
  •  7.5×10(-2) C
Solution


Q3. What reading would you expect of a square-wave current, switching rapidly between +0.5 A and -0.5 A, when passed through an ac ammeter?
  •  0
  •  0.5 A
  •  0.25 A
  •  1.0 A
Solution

Q4. A capacitor of 10 μF and an inductor of 1 H are joined in series. An ac of 50 Hz is applied to this combination. What is the impedance of the combination?
  •  
  •  
  •  
  •  
Solution


Q5. Two resistors are connected in series across as 5 V rms source of alternating potential. The potential difference across 6 Ω resistor is 3 V. If R is replaced by a pure inductorL of such magnitude that current remains same, then the potential difference across L is
  •  1 V
  •  2 V
  •  3 V
  •  4 V
Solution


Q6. For the circuit shown in Fig, the ammeter A2 reads 1.6 A and ammeter A3 reads 0.4 A. Then
  •  ω=4/√LC
  •  f=2π/√LC
  •  The ammeter A1 reads 1.2 A
  •  The ammeter A1 reads 2A
Solution
Q7. In the above question, the capacitance in the circuit is
  •  100/(100 π) F
  •  25/(100 π) F
  •  √(125×75)/(100 π) F
  •  1/(100 π√(125×75)) F
Solution


Q8. A direct current of 5 A is superimposed on an alternating current I=10 sin⁡ωt flowing through a wire. The effective value of the resulting current will be
  •  (15/2) A
  •  5√3 A
  •  5√5A
  •  15 A
Solution


Q9. The rms value of an ac of 50 Hz is 10 A. The time taken by an alternating current in reaching from zero to maximum value and the peak value will be
  •  2×10(-2) s and 14.14 A
  •  1×10(-2) s and 7.07 A
  •  5×10(-3) s and 7.07 A
  •  5×10(-3) s and 14.14 A
Solution


Q10. An AC voltage source of variable angular frequency ω and fixed amplitude V0 is connected in series with a capacitance C and an electric bulb of resistance R (inductance zero). When ω is increased
  •  The bulb glows dimmer
  •  The bulb glows brighter
  •  Total impedance of the circuit is unchanged
  •  Total impedance of the circuit increases
Solution


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