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Q1. Benzene and toluene form nearly ideal solutions. At 〖25〗^∘ C, the vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The partial vapour pressure of benzene at 〖20〗^∘ C for a solution containing 78 g of benzene and 46 g of toluene in torr is
  •  53.5
  •  37.5
  •  25
  •  50
Solution
Mixture contains 78 g benzene = 1 mole benzene and 46 g toluene = 0.5 mole toluene Total mole of benzene and toluene=1.5 mol Mole fraction of benzene in mixture =1/1.5=2/3 VP of benzene p_b^∘ =75 torr ∴ Partial vapour pressure of benzene = p_b^∘ X_b =75 ×2/3=50 torr

Q2.Which of the following liquid pairs shows a positive deviation from Raoult’s law?
  •  Water-hydrochloric acid
  •  Benzene-methanol
  •  Water-nitric acid
  •  Acetone-chloroform
Solution

Q3.  Following solutions at the same temperature will be isotonic :
  •   President
  •  Chief Justice of India
  •  Opposition Party in the Lok Sabha
  •  3.42 g of cane sugar in one litre water and 0.18 g of glucose in 0.1 litre water
Solution
For isotonic solutions, π_1= π_2(and for non-electrolytes also c_1=c_2).

Q4. Which of the following liquid pair shows a positive deviation from Raoult’s law?
  •  Water-nitric acid
  •  Water-hydrochloric acid
  •  Acetone-chloroform
  •  Benzene-methanol
Solution
D

Q5. Which of the following is the expression of Raoult’s law? (p=vapour pressure of pure solvent, p_s=vapour pressure of the solution)
  •  (p-p_s)/p=n/(n+N)
  •  (p_s-p)/p=N/(N+n)
  •  (p-p_s)/p_s =N/(N-n)
  •  (p_s-p)/p_s =(N-n)/N
Solution
 According to Raoult’s law, for non volatile solute, the relative lowering of vapour pressure of a solution is equal to the mole fraction of the solute (p-p_s)/p=n/(n+N)

Q6. Which of the following mixture does not show positive deviation from the Raoult’s law?
  •  Benzene + acetone
  •  Acetone + chloroform
  • Acetone + ethanol
  •  Water + ethanol
Solution
.



Q7.Who gave the phase rule?
  •  Nernst
  •  Raoult
  •  Willard Gibbs
  •  Ostwald
Solution
Gibbs gave phase rule for heterogeneous systems.

Q8.The volume of water to added to 100 〖cm〗^3 of 0.5 N H_2 〖SO〗_4 to get decinormal concentration is
  •  450 〖cm〗^3
  •  400 〖cm〗^3
  •  500 〖cm〗^3
  •  100〖 cm〗^3
Solution



Q9.40% by weight solution will contain how much mass of the solute in 1L solution, density of the solution is 1.2 g/mL?
  •  380 g
  •  38 g
  •  48 g
  •  480 g
Solution



Q10. The azeotropic mixture of water (b. pt.100℃) and HCl (b.pt. 85℃) boils at 108.5℃.When this mixture is distilled it is possible to obtain
  •  Pure water
  •  Neither HCl nor H_2 O in their pure states
  •  Pure water as well as HCl
  • Pure HCl
Solution
Azerotropic mixture has constant boiling mixture, it is not possible to separate the components of azeotropic mixture by boiling

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