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SOLUTIONS QUIZ 18

Dear Readers,


The one subject in NEET which is candidates who can easily attain good marks is Chemistry. That's the reason, often, one doesn’t pay notice and choose to compromise it. But if one wants to rank above others, the tip is to be thorough with NEET chemistry concepts. The understanding of reactions and definite basic understanding is what requires major attention in Chemistry but once done it only gets simpler from there. The main focus on the to-do list should be on getting a hang of the NCERT syllabus of NEET chemistry. .

Q1.  Mole fraction of solute in an aqueous solution which boils at 100.104. 𝐾b for H2O = 0.52 K molality-1:
  •   3.6 × 10 -3
  •   0.004
  •   5.6 × 10-3
  •   0.996
Solution
∆𝑇 = 𝐾𝑏 × 1000 × 𝑤 × 18/𝑚 × 𝑊 × 18
 ∴ 0.104 =0.52 ×1000 × 𝑛 /𝑁 ×18 
 ∴ 𝑛/𝑁= 3.6 × 10-3 or 1 +𝑛/𝑁 = 1.0036 
or 
 𝑁/𝑛 + 𝑁= 0.996 
∴ 𝑛/𝑛+𝑁 = 0.004

Q2. Colligative properties of a solution depends upon
  •   Nature of both solvent and solute
  •   Nature of solute only
  •   Number of solvent particles
  •   The number of solute particles
Solution
The properties of solution which depend only on the number of solute particles but not on the nature of the solute taken are called colligative properties.


Q3.   X is dissolved in water. Maximum boiling point is observed when X is ….(0.1 M each)
  •    𝐶𝑎𝑆𝑂4
  •   𝐵𝑎𝐶𝑙2
  •   NaCl
  •   Urea
Solution
Elevation in boiling point is colligative property and depends upon number of ions of molecules or particles. 
 𝐶𝑎𝑆𝑂4 → 𝐶𝑎2+ + 𝑆𝑂4 2- ∴ 2 ions
 𝐵𝑎𝐶𝑙2 → 𝐵𝑎2+ + 2𝐶𝑙− ∴ 3 ions 
 NaCl → 𝑁𝑎+ + 𝐶𝑙- ∴ 2 ions 
 urea → no dissociation ∴ 1 molecule
 ∵ 𝐵𝑎𝐶𝑙2furnishes maximum ions.
 ∴ 𝐵𝑎𝐶𝑙2 will have maximum boiling point.

Q4.  Lowering of vapour pressure is highest for
  •   0.1 M BaCl2
  •   0.1 M glucose
  •   0.1 M MgSO4
  •   Urea
Solution
𝑝0 − 𝑝s /𝑝0 = molality × (1 − 𝛼 + 𝑥𝛼 + 𝑦𝛼) 
 The value of 𝑝0 − 𝑝s is maximum for BaCl2


Q5. The statement “the relative lowering of the vapour pressure is equal to th ratio ot moles of the solute to the total number of the moles in the solution” refers to
  •   Hess’s law
  •   Dalton’s law
  •   Raoult’s law
  •   Charles’law
Solution
  According to Raoult’ law, 𝑝−𝑝s / 𝑝 = 𝑛/𝑛+𝑁

Q6.  A solution of two liquids boils at a temperature more than the boiling point of either them. Hence, the binary solution shows
  •   Negative deviation from Raoult’s law
  •   Positive deviation from Raoult’s law
  • No deviation from Raoult’s law
  •   Positive or negative deviation from Raoult’s law depending upon the composition
Solution
Negative deviation from Raoult’s law


Q7. Which of the following is true when components forming an ideal solution are mixed?  

 
  •   ∆𝐻m = ∆𝑉m = 0
  •   ∆𝐻m < ∆𝑉m
  •   ∆𝐻m = ∆𝑉m = 1
  •   ∆𝐻m > ∆𝑉m
Solution

∆𝐻m = ∆𝑉m = 0


Q8. The relative lowering of vapour pressure of an aqueous solution containing non-volatile solute is 0.0125. The molality of the solution is NaOH solution
  •   Vapour pressure
  • Osmotic pressure
  •   Boiling point
  •   Freezing point
Solution
Osmotic pressure


Q9. The normality of 10% (weight/volume) acetic acid is

  •   1 N
  •   1.3 N
  •   1.7 N
  •   1.9 N
Solution
𝑁 = 𝑤 × 1000 / eq.wt.×𝑉(mL) = 10 × 1000 / 60 × 100 = 1.66 N

Q10.  Two solutions of substance (non-electrolyte) are mixed in the following manner. 480 mL of 1.5 M first solution +520 mL of 1.2 M second solution. What is the molarity of the final mixture ?  

 

  •   2.70M
  •   1.344 M
  •   1.50 M
  •   1.20M
Solution
Total molarity = 𝑀1𝑉1+ 𝑀2𝑉2 / 𝑉1+ 𝑉2 
= 1.5 × 480+1.2 × 520 /480+520
 = 1.344 m

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