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Aliphatic and Aromatic Amines Quiz-9

Dear Readers,

The one subject in NEET which is candidates who can easily attain good marks is Chemistry. That's the reason, often, one doesn’t pay notice and choose to compromise it. But if one wants to rank above others, the tip is to be thorough with NEET chemistry concepts. The understanding of reactions and definite basic understanding is what requires major attention in Chemistry but once done it only gets simpler from there. The main focus on the to-do list should be on getting a hang of the NCERT syllabus of NEET chemistry..

Q1. Reduction of nitrobenzene in the presence of gives
  •  Azobenzene
  •  Hydrazobenzene
  •  N-phenyl hydroxylamine
  •  Aniline
Solution
Reduction of nitrobenzene by  gives N-phenyl hydroxylamine.


Q2.Which of the following can be used to distinguish acetamide and urea?
  •  Fehling’s solution
  •  Biuret test
  •  Hofmann’s reaction
  •  NaOH solution
Solution
Urea gives biuret test. Biuret formed gives violet colour with  in alkaline medium.

Q3.  How may primary amines are possible for the formula ?
  •  1
  •  2
  •  3
  •  4
Solution
4

Q4. Which one of the following compound when heated with KOH and primary amines gives carbylamine test?
  •  
  •  
  •  
  •  
Solution


Q5.n-butylamine (I), diethylamine (II) and N, N-dimethylethylamine (III) have the same molar mass.
The increasing order of their boiling point is
  •  III < II < I
  •  I < II < III
  •  II < III < I
  •  II < I < III
Solution
 Intermolecular H-bonding is more in primary amines than in secondary amines as there are two H-atom available for H-bonding. Tertiary amines do not have intermolecular H-bonding due to absence of H-atom available for H-bonding. Therefore, the order of boiling points of the given amines is as follows


Q6.  as the product. The intermediates of the reaction are
The correct answer is
  •  A,B
  •  A,C
  • C,D
  •  B,D
Solution
A,B

Q7.2,4,6-tribromo aniline is a product of:
  •  Electrophilic addition on 
  •  Electrophilic substitution on 
  •  Nucleophilic addition on 
  •  Nucleophilic substitution on 
Solution
H-atom of  ring is replaced by  reactions

Q8.Ethylamine undergoes oxidation in the presence of followed by hydrolysis to form:
  •  An acid
  •  An alcohol
  •  An aldehyde
  •  a N-oxide
Solution


Q9.Which of the following amines is optically active?
  •  
  •  
  •  
  •  Sec. butylamine
Solution
Sec. butylamine

Q10. 
Which product will not show tautomerism? 
  •  W
  •  X
  •  Y
  •  Z
Solution
Presence of -H atom is the main condition for exhibiting tautomerism. The reactant taken in reaction (C) does not contain any -H atom, thus the product (Y)will also show the absence of -H atom, Hence, will show tautomerism

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