As per analysis for previous years, it has been observed that students preparing for NEET find Physics out of all the sections to be complex to handle and the majority of them are not able to comprehend the reason behind it. This problem arises especially because these aspirants appearing for the examination are more inclined to have a keen interest in Biology due to their medical background. Furthermore, sections such as Physics are dominantly based on theories, laws, numerical in comparison to a section of Biology which is more of fact-based, life sciences, and includes substantial explanations. By using the table given below, you easily and directly access to the topics and respective links of MCQs. Moreover, to make learning smooth and efficient, all the questions come with their supportive solutions to make utilization of time even more productive. Students will be covered for all their studies as the topics are available from basics to even the most advanced.
.

**Q1.**Moment of inertia of a hollow cylinder of mass M and radius r about its own axis is?

Solution

Moment of inertia of a hollow cylinder of mass M and radius r about its own axis is Mr

Moment of inertia of a hollow cylinder of mass M and radius r about its own axis is Mr

^{2}**Q2.**A thin horizontal circular disc is rotating about a vertical axis passing through its centre. An insect is at rest at a point near the rim of the disc. The insect now moves along a diameter of the disc to reach other end. During the journey of the insect, the angular speed of the disc?

**Q3.**The vector product of the force (F) and distance (r) from the centre of action represents?

**Q4.**One circular ring and one circular disc, both are having the same mass and radius. The ratio of their moments of inertia about the axes passing through their centres and perpendicular to their planes, will be?

Solution

I

I

_{Ring}/I_{Disc}=(MR^{2})/(1/2MR^{2})=2:1**Q5.**When two bodies collide elastically, the force of interaction between them is?

Solution

When non-conservative force acts on a body, then mechanical energy is converted into non-mechanical energy and vice-versa.

When non-conservative force acts on a body, then mechanical energy is converted into non-mechanical energy and vice-versa.

**Q6.**A metre stick of mass 400 g is pivoted at one end and displaced through an angle 60°. The increase in its potential energy is?

Solution

Centre of mass of a stick lies at the mid point and when the stick is displaced through an angle 60° it rises upto height 'h' from the initial position

From the figure h=l/2-l/2 cosÎ¸=l/2(1-cosÎ¸) Hence the increment in potential energy of the stick =mgh=mg l/2 (1-cosÎ¸ )=0.4×10×1/2 (1-cos60° )=1J

Centre of mass of a stick lies at the mid point and when the stick is displaced through an angle 60° it rises upto height 'h' from the initial position

From the figure h=l/2-l/2 cosÎ¸=l/2(1-cosÎ¸) Hence the increment in potential energy of the stick =mgh=mg l/2 (1-cosÎ¸ )=0.4×10×1/2 (1-cos60° )=1J

**Q8.**A torque of 50 Nm acting on a wheel at rest rotates it through 200 radians in 5 sec. Calculate the angular acceleration produced?

Solution

Î¸=Ï‰

Î¸=Ï‰

_{0}t+1/2 Î±t^{2}⇒200=1/2 Î±(5)^{2}⇒Î±=16rad/s^{2}**Q9.**An isolated particle of mass m is moving in a horizontal plane (x-y), along the x-axis, at a certain height above the ground. It suddenly explodes into two fragments of masses m/4 and 3m/4. An instant later, the smaller fragment is at y=+15 cm. The larger fragment at the instant is at?

Solution

Since there is no external force acting on the particle, Hence y

Since there is no external force acting on the particle, Hence y

_{CM}=(m_{1}y_{1}+m_{2}y_{2})/(m_{1}+m_{2})=0, hence (m/4)×(+15)+(3m/4)(y_{2})=0⇒y_{2}=-5 cm**Q10.**The principle of conservation of angular momentum, states that angular momentum?

Solution

Remains conserved until the torque acting on it remain zero

Remains conserved until the torque acting on it remain zero