As per analysis for previous years, it has been observed that students preparing for NEET find Physics out of all the sections to be complex to handle and the majority of them are not able to comprehend the reason behind it. This problem arises especially because these aspirants appearing for the examination are more inclined to have a keen interest in Biology due to their medical background.
Furthermore, sections such as Physics are dominantly based on theories, laws, numerical in comparison to a section of Biology which is more of fact-based, life sciences, and includes substantial explanations. By using the table given below, you easily and directly access to the topics and respective links of MCQs. Moreover, to make learning smooth and efficient, all the questions come with their supportive solutions to make utilization of time even more productive. Students will be covered for all their studies as the topics are available from basics to even the most advanced.
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**Q1.**An alternating voltage (in volt) given by V=200√2 sin (100t) is connected to 1Î¼F capacitor through an AC ammeter. The reading of the ammeter will be

Solution

It is a fact.

It is a fact.

**Q2.**In an AC circuit, V and I are given by V=150 sin (150t) volt and I=150 sin (150t+Ï€/3) amp. The power dissipated in the circuit is

Solution

Power P=1/2 V

Power P=1/2 V

_{0}I_{0}cosÏ•=0.5×150×150× cos 60°

=22500/4
=5625 W

**Q3.**The resonance frequency of the tank circuit of an oscillator when L=10/Ï€

^{2}mH and C=0.04 Î¼F are connected in parallel is

**Q4.**The process by which ac is converted into dc is known as

Solution

It is a fact.

It is a fact.

Solution

i

i

_{L}= 90/30 = 3Ai

_{C}= 90/20 = 4.5A
Net current through circuit i = i

_{C}-i_{L}=1.5 A∴ Z = V/i = 90/1.5 = 60Î©

**Q6.**An emf is 15 V is applied in a circuit coil containing 5 H inductance and 10 Î© resistance. The ratio of currents at time t=∞ and t=1 s is

Solution

Here, i=i

Here, i=i

_{0}at t=∞.Let i be the current at t = 1 sFrom i=i

_{0}(1-e^{-R/L t}) = i_{0}(1-e^{-10/5×1})=i

_{0}(1-1/e^{2})∴ i

_{0}/i= e^{2}/(e^{2}-1)**Q7.**A transformer is used to light 140 W, 24 V lamp from 240 V AC mains. The current in the mains is 0.7 A. The efficiency of transformer is nearest to

Solution

P

P

_{i}=240 × 0.7=168 W, P_{0}=140 WÎ· = P

_{0}/P_{i}×100=140/168×100 ≈80%**Q8.**Eddy current are produced when

Solution

Eddy currents are produced when a metal is kept in a varying magnetic field.

Eddy currents are produced when a metal is kept in a varying magnetic field.

**Q9.**An inductive circuit contains a resistance of 10 ohm and an inductance of 2.0 henry. If an ac voltage of 120 volt and frequency of 60 Hz is applied to this circuit, the current in the circuit would be nearly

**Q10.**The instantaneous values of current and voltage in an ac circuit are i=100 sin 314 t amp and e=200 in (314 t+Ï€/3)V respectively. If the resistance is 1Î©, then the reactance of the circuit will be

Solution

V

V

_{0}=i_{0}Z⇒200=100 Z ⇒Z=2Î©Also Z

^{2}=R^{2}+X_{L}^{2}⇒(2)^{2}=(1)^{2}+X_{L}^{2}⇒X_{L}=√3 Î©