The one subject in NEET which is candidates who can easily attain good marks is Chemistry. That's the reason, often, one doesn’t pay notice and choose to compromise it. But if one wants to rank above others, the tip is to be thorough with NEET chemistry concepts. The understanding of reactions and definite basic understanding is what requires major attention in Chemistry but once done it only gets simpler from there. The main focus on the to-do list should be on getting a hang of the NCERT syllabus of NEET chemistry.
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Q1. The splitting of an ester by an alcohol is known as
Solution
CH3 COOCH3+C2 H5OH⟶CH3 COOC2 H5+CH3OH
CH3 COOCH3+C2 H5OH⟶CH3 COOC2 H5+CH3OH
Q2.Etard’s reaction involves the preparation of benzaldehyde from
Solution
Toluene can be oxidized to benzaldehyde with a solution of chromyl chloride (CrO2 Cl2 ) in CS2 or CCl4This is known as Etard reaction. Further oxidation of benzaldehyde to benzoic acid is avoided by protection of carbonyl group.
Q4. Which of the following regent can effectively carried out the following conversion?
NaBH4 is a mild reducing agent and can not reduce less reactive ester group
Q5. Which product is obtained on reduction of methanal in the presence of concentrated NaOH?
Thus, reaction is called Cannizaro’s reaction.
Q6. The Sulphur present in an organic compound is oxidized by fuming nitric acid into:
Solution
Q7.Identify X in the sequence:
Solution
C5 H12O must be a tertiary alcohol as it gives alkene on treatment with Cu. Thus C4 H8O is a ketone.
C5 H12O must be a tertiary alcohol as it gives alkene on treatment with Cu. Thus C4 H8O is a ketone.
Q8.Formaldehyde can be distinguished from acetaldehyde by the use of:
Solution
Formaldehyde does not give iodoform reaction.
Formaldehyde does not give iodoform reaction.
Q9.Hydrated oxalic acid contains:
Solution
Hydrated oxalic acid is H2 C2 O4∙2H2 O
Hydrated oxalic acid is H2 C2 O4∙2H2 O
Q10. Tartronic acid is obtained from tartaric acid by:
Solution