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As per analysis for previous years, it has been observed that students preparing for NEET find Physics out of all the sections to be complex to handle and the majority of them are not able to comprehend the reason behind it. This problem arises especially because these aspirants appearing for the examination are more inclined to have a keen interest in Biology due to their medical background. Furthermore, sections such as Physics are dominantly based on theories, laws, numerical in comparison to a section of Biology which is more of fact-based, life sciences, and includes substantial explanations. By using the table given below, you easily and directly access to the topics and respective links of MCQs. Moreover, to make learning smooth and efficient, all the questions come with their supportive solutions to make utilization of time even more productive. Students will be covered for all their studies as the topics are available from basics to even the most advanced. .

Q1. A wire of length 5m and radius 1 mm has a resistance of 1 ohm. What length of the wire of the same material at the same temperature and of radius 2 mm will also have a resistance of 1 ohm?
•  1.25 m
•  2.5 m
•  10 m
•  20 m
Solution
R∝ 1/r2 ⇒R1/R2 =l1/l2 ×(r22)/(r12 )⇒1/1=5/l2 ×(2/1)2⇒l2=20m

•  2.4 V
•  3.4 V
•  4.0 V
•  6.0 V
Solution
If the voltmeter is ideal then given circuit is an open circuit, so reading of voltmeter is equal to the e.m.f. of cell i.e.,6V

Q3. An electron (charge =1.6×10-19coulomb) is moving in a circle of radius 5.1×10-11 m at a frequency of 6.8×1015 revolutions/sec. The equivalent current is approximately?
•  5.1×10-3 amp
•  6.8×10-3 amp
•  1.1×10-3 amp
•  2.2×10-3 amp
Solution
i=ev=1.6×10-19×6.8×1015=1.1×10-3 amp

Q4. In the following Wheatstone bridge P/Q=R/S. If key K is closed, then the galvanometer will show deflection?
•  In left side
•  In right side
•  No deflection
•  In either side
Solution
Pressing the key does not disturb current in all resistances as the bridge is balanced. Therefore, deflection in the galvanometer in whatever direction it was, will stay

Q5. The amount of heat generated in 500Ω resistance, when the key is thrown over from contact 1 to 2, as shown in figure is?
•  10℃
•  7.5℃
•  5.0℃
•  2.5℃
Solution
When the key is in contact with 1, then energy stored in the condenser =1/2 CE2 But when the key is thrown to contact 2, total heat H=I2 (500+330)=1/2 CE2 H1=I2 (500) H1/H=R1/((R1+R2)) H1=500/830×1/2×5×10-6×(200)2 H1=60×10-3 J

Q6. In potentiometer a balance point is obtained, when?
•  The e.m.f. of the battery becomes equal to the e.m.f. of the experimental cell
•  The p.d. of the wire between the +ve end to jockey becomes equal to the e.m.f. of the experimental cell
•  The p.d. of the wire between +ve point and jockey becomes equal to the e.m.f. of the battery
•  The p.d. across the potentiometer wire becomes equal to the e.m.f. of the battery
Solution
The p.d. of the wire between the +ve end to jockey becomes equal to the e.m.f. of the experimental cell

Q7. With the rise of temperature the resistivity of a semiconductor?
•  Remains unchanged
•  Increases
•  Decreases
•  First increases and then decreases
Solution
For semiconductor the temperature coefficient of resistance (α) is negative. Hence, resistivity will decrease with the temperature rise.

Q8. Five equal resistances, each of resistance R,are connected as shown in figure below. A battery of V volt is connected between A and B.The current flowing in FC will be?
•  3V/R
•  V/R
•  V/2R
•  2V/R
Solution

Q9. I-Vcharacteristic of a copper wire of length L and area of cross-section A is shown in figure. The slope of the curve becomes?
•  More if the experiment is performed at higher temperature
•  More if a wire of steel of same dimension is used
•  More if the length of the wire increased
•  Less if the length of the wire increased
Solution
Slope of graph =I/V=1/R If experiment is performed at higher temperature then resistance increase and hence slope decrease, choice (a) is wrong. Similarly in choice (b) and (c) resistance increase. But for choice (d) resistance R increases, so slope decreases

Q10. If 2.2 kilowatt power is transmitted through a 10 ohm line at 22000 volt, the power loss in the form of heat will be?:
•  0.1 watt
•  1 watt
•  10 watt
•  100 watt
Solution
For power transmission power loss in line PL=i2 R If power of electricity is P and it is transmitted at voltage V, then P=Vi⇒i=P/V PL=(P/V)2 R=(P2 R)/V2 =(2.2×103×2.2×103×10)/(22000×22000)=0.1W ## Want to know more

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BEST NEET COACHING CENTER | BEST IIT JEE COACHING INSTITUTE | BEST NEET, IIT JEE COACHING INSTITUTE: Current Electricity Quiz 12
Current Electricity Quiz 12
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