## Sum to n terms of an Arithmetic progression - Basic

The sum of n terms of AP is the sum(addition) of first n terms of the arithmetic sequence. It is equal to n divided by 2 times the sum of twice the first term – 'a' and the product of the difference between second and first term-'d' also known as common difference, and (n-1), where n is numbers of terms to be added.

Q1.  The sum of first n natural numbers is

•   n(n – 1)
•  n(n – 1)/2
•  n(n + 1)
•   n(n + 1)/2

n(n + 1)/2

Q2.  The sum of all natural numbers between 1 and 100 which are multiples of 3 is

•  1680
•  1683
•  1681
•  1682

1683

Q3.  The sum of 1+3+5+7+..... upto n terms is

•   (n+1)2
•  (2n)2
•  n2
•   (n-1)2

n2

Q4.  If the sum of the series 2+ 5+ 8+11 ....... is 60100, then the number of terms are

•   100
•   200
•  150
•  250

200

Q5.  If the first term of an A.P. be 10, last term is 50 and the sum of all the terms is 300, then the number of terms are

•  5
•  8
•  10
•  15

10

Q6.  The sum of the numbers between 100 and 1000 which is divisible by 9 will be

•  55350
•   57228
•  97015
•  62140

55350

Q7.  If the sum of three numbers of a arithmetic sequence is 15 and the sum of their squares is 83, then the numbers are

•   4, 5, 6
•  3, 5, 7
•  1, 5, 9
•  2, 5, 8

3, 5, 7

Q8.  There are 15 terms in an arithmetic progression. Its first term is 5 and their sum is 390. The middle term is

•  23
•   26
•   29
•   32

26

Q9.  The sum of numbers from 250 to 1000 which are divisible by 3 is

•  135657
•   136557
•   161575
•  156375

156375

Q10.  Four numbers are in arithmetic progression. The sum of first and last term is 8 and the product of both middle terms is 15. The least number of the series is

•   4
•   3
•   2
•   1

1

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