Q1. If ‘F’ is faraday and ‘N’ is Avogadro number, then charge of electron can be expressed as
Solution
If F is Faraday and N is Avogadro number, charge of electron = F/N
If F is Faraday and N is Avogadro number, charge of electron = F/N
Q2.For a given cell reaction; Cr+3H_2 O+OCl^- ⟶Cr^(3+) 3Cl^- +6OH^-, the species undergoing reduction is :
Solution
Cl in OCl^-has oxidation number as +1. Thus, Cl^+ +2e ⟶Cl^- (i.e.,reduction of OCl^-)
Cl in OCl^-has oxidation number as +1. Thus, Cl^+ +2e ⟶Cl^- (i.e.,reduction of OCl^-)
Q3. E° for F_(2+)+2e=2F^- is 2.8 V, E° for 1/2〖 F〗_2+e=F^- is:
Solution
E° does not depend on stoichiometry of change
E° does not depend on stoichiometry of change
Q4. Which is correct representation for a cell at equilibrium?
Solution
At equilibrium E_cell=0.
At equilibrium E_cell=0.
Q5.Cu(II) sulphate solution is treated separately with KCl and KI. In which case, Cu^(2+) be reduced to Cu^+?
Q6. For gold plating, the electrolyte used is
Solution
For gold plating the electrolyte K [Au(CN)_2] is used.
For gold plating the electrolyte K [Au(CN)_2] is used.
Q7.The specific conductivity of 0.1 N KCl solution is 0.0129 Ω^(-1) cm^(-1). The resistance of the solution in the cell 100Ω. The cell constant of the cell will be
Solution
Specific conductivity (κ) = 1/R ×cell constant Cell constant=κ ×R = 0.0129 × 100 = 1.29
Specific conductivity (κ) = 1/R ×cell constant Cell constant=κ ×R = 0.0129 × 100 = 1.29
Q8.Passage of 96500 coulomb of electricity liberates ….litre of O_2at NTP during electrolysis.J
6.5
5.6
22.2
11.2
Solution
96500 C or 1F will liberate 1 eq. of O_2 or 1/4 mole O_2 or 5.6 litre O_2 at NTP.
96500 C or 1F will liberate 1 eq. of O_2 or 1/4 mole O_2 or 5.6 litre O_2 at NTP.
Q9.The cell reaction is spontaneous, when
Solution
△G = △H - T△S For a spontaneous cell reaction, △H should be negative and △S should be positive. Hence, △G should be negative.
△G = △H - T△S For a spontaneous cell reaction, △H should be negative and △S should be positive. Hence, △G should be negative.
Q10. Which of the following statements is not applicable to electrolytic conductors?
Solution
B
B