## CHEMISTRY CHEMICAL EQUILBRIUM QUIZ-4

The one subject in NEET which is candidates who can easily attain good marks is Chemistry. That's the reason, often, one doesn’t pay notice and choose to compromise it. But if one wants to rank above others, the tip is to be thorough with NEET chemistry concepts. The understanding of reactions and definite basic understanding is what requires major attention in Chemistry but once done it only gets simpler from there. The main focus on the to-do list should be on getting a hang of the NCERT syllabus of NEET chemistry.
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Q1.  The pH of 10-10M NaOH solution is nearest to
•  -4
•  -10
•  4
•  7
Solution
(d) Given, concentration of NaOH=10-10 M NaOH →Na+ + OH- 10-10 10-10 10-10 ∴[OH-] from NaOH=10-10 ∴ Total [OH-]=10-7+10-10 =10-7(1+0.001) =10-7(1001/1000) =10-10×1001 pOH=-log⁡[OH-] =-log⁡(1001×10-10) =-3.004+10 =6.9996 ∵ pH+pOH=14 ∴ pH=14-6.9996 =7.0004=7

Q2.HSO4-+OH-→SO42-+H2O
Which is correct about conjugate acid base pair?
•  HSO4- is conjugate acid of base SO42-
•  HSO4- is conjugate base of base SO42-
•  SO42- is conjugate acid of acid HSO4-
•  None of the above
Solution
a) The residual part of the acid after removal of a proton from the molecule of an acid, is called its conjugate base. Thus, conjugate base=Acid-H^+ and a base after accepting a proton gets converted into its conjugate acid. Thus, HSO4- is conjugate acid of base SO42-.
Q3.  Which of the following is a Lewis acid?
•  AlCl3
•  Cl-
•  CO
•  C2H2
Solution
(a) According to Lewis acid is any species (molecule, radial or ion) that can accept an electron pair to form a coordinate covalent bond. Thus, acid is an electron deficient species e.g., BF3,AlCl3,SO3 and all cations etc

Q4. The equilibrium constant for the reaction N2(g)+O2(g)⇌2NO(g) at temperature Tis 4×10-4. The value of Kc for the reaction NO(g)⇌1/2 N2(g)+1/2 O2(g) at the same temperature is
•  25
•  50
•  75
•  100
Solution
b) N2 (g)+O2 (g)⇌2NO(g) Kc=[NO]2/[N2 ][O2] =4×10-4 NO(g)⇌1/2 N2 (g)+1/2 O2 (g) Kc'=([N2 ](1/2) [O2 ](1/2))/([NO]) =1/√(Kc )=1/√(4×10-4 ) =1/(2×10-2 )=100/2=50

Q5.The equilibrium constant for the reaction, 2X(g)+Y(g)⇌2Z(g) is 2.25 litre mol-1. What would be the concentration of Y at equilibrium with 2.0 mole of X and 3.0 mole of Z in one litre vessel?
•  1.0 M
•  2.25 M
•  2.0 M
•  4.0 M
Solution
a) Kc=[Z]2/([X]2 [Y] )=(3)2/((2)2 (Y))=2.25,∴[Y]=1M

Q6.For a hypothetical equilibrium: 4A+5B⇌4x+6y; the equilibrium constant Kc has the unit:
•  mol2litre-2
•  litre mol-1
•  litre2mol-2
•  mol litre-1
Solution
d) Unit of K_c=[ ]∆n.∆n=+1.

Q7.The correct statement about buffer solution is:
•  It contains a weak acid and its conjugate base
•  It contains a weak base and its conjugate acid
•  It shows little change in pH on adding small amount of an acid or base
•  All of the above
Solution
d)Buffer is (CH3 COOH)⁡ + (CHCOO-) and has pH fixed.

Q8.In the reaction, 3A+2B→2C, the equilibrium constant Kc is given by
•  ([3A]×[2B])/([C])
•  ([A]3×[B])/([C])
•  [C]2/([A]3×[B]2)
•  ([C])/([3A][2B])
Solution
c) 3A+2B→2C Kc=(concentration of products)/(concnetration of reactants) =[C]2/([A]3×[B]2 )

Q9.NaOH(aq),HCl(aq)andNaCl(aq) concentration of each is 10-3 M. Their pH will be respectively p=Kc ?
•  10, 6, 2
•  11, 3, 7
•  10, 2, 6
•  3, 4, 7
Solution
b) NaOH=[OH- ]=10(-3) [H+ ][OH- ]=10-14 [H+ ]=10-11 pH=-log⁡[H+] =-log⁡[10-11 ]=11 HCl(aq)=[H+ ]=10-3 pH=-log⁡[10-3 ]=3 NaCl(aq)=Neutral; [H+ ]=[OH- ]=10-7 ie,pH=7

Q10. In the following reversible reaction, 2SO2+O2⇌2SO3+Q cal
Most suitable condition for the higher production of SO3 is

•   Low temperature and high pressure
•   Low temperature and low pressure
•   High temperature and high pressure
•  High temperature and low pressure
Solution
a) Reaction is exothermic and volume is decreasing from left to right, so for higher production of SO_3, there should be low temperature and high pressure

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