## MATHEMATICS TRIOGONOMETRY RATIOS AND IDENTITIES QUIZ-8

As per analysis for previous years, it has been observed that students preparing for JEE MAINS find Mathematics out of all the sections to be complex to handle and the majority of them are not able to comprehend the reason behind it. This problem arises especially because these aspirants appearing for the examination are more inclined to have a keen interest in Mathematics due to their ENGINEERING background.

Furthermore, sections such as Mathematics are dominantly based on theories, laws, numerical in comparison to a section of Engineering which is more of fact-based, Physics, and includes substantial explanations. By using the table given below, you easily and directly access to the topics and respective links of MCQs. Moreover, to make learning smooth and efficient, all the questions come with their supportive solutions to make utilization of time even more productive. Students will be covered for all their studies as the topics are available from basics to even the most advanced.

Q1. If sin⁡Î¸/6, cos⁡Î¸ and tan⁡Î¸ are in GP, then the general value of Î¸ is
•  2nÏ€± Ï€/3,n∈I
•  2nÏ€± Ï€/6,n∈I
•  2nÏ€+(-1)n Ï€/3,n∈I
•  n Ï€+ Ï€/3,n∈I
Solution

Q2.If cos⁡Î¸=8/17 and Î¸ lies in the first quadrant, then the value of cos⁡(30°+Î¸)+cos⁡(45°-Î¸)+cos⁡(120°-Î¸), is
•  23/17 ((√3-1)/2+1/√2)
•  23/17 ((√3+1)/2+1/√2)
•  23/17 ((√3-1)/2-1/√2)
•  23/17 ((√3+1)/2-1/√2)
Solution

Q3.  If tan⁡Î¸=a/b, then b cos⁡2Î¸+a sin⁡2Î¸=
•  a
•  b
•  b/a
•  a/b
Solution

Q4. If cos⁡x=tan⁡y,cos⁡y=tan⁡z,cos⁡z=tan⁡x, then the value of sin⁡x is
•  2 cos⁡18°
•  cos⁡18°
•  sin⁡18°
•  2sin⁡18°
Solution

Q5.

•  3/4
•  1/2
•  2
•  5/4
Solution

Q6.

•  1/2
•  cos⁡Ï€/8
•  1/8
•  (1+√2)/(2√2)
Solution

Q7.If in a triangle ABC,cos⁡A cos⁡B+sin⁡A sin⁡B sin⁡C=1, then the triangle is
• Isosceles
•  Right angled
•  Isosceles right angled
•  Equilateral
Solution

Q8.If sin⁡x+sin2x=1, then value of cos2x+cos2⁡x is
•  1
•  2
•  1.5
•  None of these
Solution

Q9.The maximum value of cos2⁡A+cos2B-cos2C, is
•  0
•  1
•  3
•  2
Solut

Q10. If A+C=B, then tan⁡A tan⁡B tan⁡C=
•  tan⁡A tan⁡B tan⁡C
•  tan⁡B-tan⁡C-tan⁡A
•  tan⁡A+tan⁡C-tan⁡B
•  None of these
Solution

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