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As per analysis for previous years, it has been observed that students preparing for JEE MAINS find Mathematics out of all the sections to be complex to handle and the majority of them are not able to comprehend the reason behind it. This problem arises especially because these aspirants appearing for the examination are more inclined to have a keen interest in Mathematics due to their ENGINEERING background.

Furthermore, sections such as Mathematics are dominantly based on theories, laws, numerical in comparison to a section of Engineering which is more of fact-based, Physics, and includes substantial explanations. By using the table given below, you easily and directly access to the topics and respective links of MCQs. Moreover, to make learning smooth and efficient, all the questions come with their supportive solutions to make utilization of time even more productive. Students will be covered for all their studies as the topics are available from basics to even the most advanced.

Q1.
•  0
•  1
•  (A/a)2
•  (a/A)2
Solution
Q2.

•
•   None of these
Solution

Q3.  If 2sin2Ï€/8 is a root of the equation x2+ax+b=0, where a and b are rational numbers,
then a-b is equal to
•  -5/2
•  -3/2
•  -1/2
•   1/2
Solution

Q4.
•  0
•  1
•  2
•  None of these
Solution
Q5. Let Î±, Î² be the roots of the equation x2-ax+b=0 and An=Î±n+Î²n. Then, An+1-aAn+bAn-1 is equal to
•  -a
•  -
•  0
•  a-b
Solution
(C)
Here, Î±2-aÎ±+b=0 and Î²2+aÎ²+b=0
Now, An+1-aAn+bAn-1
=Î±n+1+Î²n+1-a(Î±n+Î²n)+b(Î±n-1+Î²n-1)
=Î±n-1(Î±2-aÎ±+b)+Î²n-1(Î²2-aÎ²+b)
=0
Q6. If x2+px+q=0 has the roots Î± and Î², then the value of (Î±-Î²)2 is equal to
•  A circle with centre at the origin
•  A straight line passing through the origin
•  The single point (0,-2)
•  None of these
Solution
Q7.
•  4C
•  4C +1
•  3C
•  2C
Solution 7
Q8.
•  [1/3, 3]
•  (1/3, 3)
•  (3, 3)
•  (-1/3, 3)
Solution
Q9.
• -1
•  1
•  0
•  None of these
Solution
Q10. If Î± and Î² are the roots of the equation ax2+bx+c=0, (c≠0), then the equation whose roots are 1(aÎ±+b) and 1(aÎ²+b) is
•  acx2-bx+1=0
•  x2-acx+bc+1=0
•  acx2+bx-1=0
• None of these
Solution

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