## MATHEMATICS FUNCTION QUIZ-4

As per analysis for previous years, it has been observed that students preparing for JEE MAINS find Mathematics out of all the sections to be complex to handle and the majority of them are not able to comprehend the reason behind it. This problem arises especially because these aspirants appearing for the examination are more inclined to have a keen interest in Mathematics due to their ENGINEERING background.

Furthermore, sections such as Mathematics are dominantly based on theories, laws, numerical in comparison to a section of Engineering which is more of fact-based, Physics, and includes substantial explanations. By using the table given below, you easily and directly access to the topics and respective links of MCQs. Moreover, to make learning smooth and efficient, all the questions come with their supportive solutions to make utilization of time even more productive. Students will be covered for all their studies as the topics are available from basics to even the most advanced.

Q1.

•  4
•  3
•  2
•  1
Solution

Q2. Let f:R→R:f(x)=x2 and g:R→R:g(x)=x+5, then gof is
•  (x+5)
•  (x+52)
•  (x2+52)
•  (x2+5)
Solution
gof=g{f(x) }=g(x2)=x2+5

Q3.  Let X and Y be subsets of R, the set of all real numbers. The function f:X→Y defined by f(x)=x2 for x∈X is one-one but not onto, if (Here, R+ is the set of all positive real numbers)
•  X=Y=R+
•  X=R,Y=R+
•  X=R+,Y=R
•  X=Y=R
Solution
Clearly, X=R+ and Y=R

Q4.

•  [-Ï€/4,Ï€/4]
•  [0,3/√2]
•  (-3,3)
•  None of these
Solution

Q5.

•  The set of all real numbers
•  The set of all positive real numbers
•  (-2, 2)
•  [-2, 2]
Solution

Q6. The domain of sin-1(log3x) is
•  [-1, 1]
•  [0, 1]
•  [0,∞]
•  [1/3,3]
Solution

Q7.

• x>0
•  |x|≥1
•  |x|≥4
•  x≥4
Solution

Q8.

•  f is a bijection
•  f is an injection only
•  f is surjection on only
•  f is neither an injection nor a surjection
Solution

Q9.The composite mapping fog of the maps f:R→R,f(x)=sin⁡x and g:R→R,g(x)=x2, is
•  x2 sin⁡x
•  (sin⁡x )2
•  sin⁡x2
•
sin⁡x/x2
Solution

Q10. Let A={2,3,4,5,…,16,17,18}. Let be the equivalence relation on A×A, cartesian product of A and A, defined by (a,b)≈(c,d) if ad=bc, then the number of ordered pairs of the equivalence class of (3, 2) is
•  4
•  5
•  6
•  7
Solution

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