## Electronics Quiz-6

As per analysis for previous years, it has been observed that students preparing for NEET find Physics out of all the sections to be complex to handle and the majority of them are not able to comprehend the reason behind it. This problem arises especially because these aspirants appearing for the examination are more inclined to have a keen interest in Biology due to their medical background.

Furthermore, sections such as Physics are dominantly based on theories, laws, numerical in comparison to a section of Biology which is more of fact-based, life sciences, and includes substantial explanations. By using the table given below, you easily and directly access to the topics and respective links of MCQs. Moreover, to make learning smooth and efficient, all the questions come with their supportive solutions to make utilization of time even more productive. Students will be covered for all their studies as the topics are available from basics to even the most advanced.

Q1. The relation between number of free electrons (n) is a semiconductor and temperature (T) is given by

•  n∝T
•  n∝T2
•  n∝√T
•  n∝T3/2
Solution
(d) For semiconductor, n=AT3/2 e(-Eg/2kT); So, n∝T3/2.

Q2.A zener diode, having breakdown voltage equal to 15 V, is used in a voltage regulator circuit shown in figure. The current through the diode is
•  20 mA
•  5 mA
•  10 mA
•  15 mA
Solution

Q3.  The current in the circuit shown in the figure, considering ideal diode is

•  20 A
•  2×10-3A
•  200 A
•  2×10-4A
Solution
(b) Potential difference across diode = 3.2 – 3 = 0.2 V ∴ Current through diode i=0.2/100=2×10-3 A

Q4. The diode used in the circuit shown in the figure has a constant voltage drop of 0.5 V at all currents and a maximum power rating of 100 milli-watt. What should be the value of the resistance R, connected in series with the diode, for obtaining maximum current?

Solution
(b) R=(Voltage drop)/Current ∴ Current in circuit, I=P/V=〖100×10-3/0.5=0.2 A R=1/0.2=5 Î©

Q5.A p-type material is electrically …….
•  Positive
•  Negative
•  Neutral
•  Depends on the concentration of p impurities
Solution
(c) A p-type material is electrically neutral.

Q6. Which of the following statements is not correct when a junction diode is in forward bias?
•  The width of depletion region decreases.
•  Free electrons on n-side will move towards the junction.
• Holes on p-side move towards the junction.
•  Electrons on n-side and holes on p-side will move away from junction.-1
Solution
(d) In forward biasing both electrons and protons move towards the junction and hence the width of depletion region decreases.

Q7.For a common emitter amplifier, the audio signal voltage across the collector resistance 2kÎ© is 2 V. If the current amplification factor of the transistor is 220, and the base resistance is 1.5 Î©, the input signal voltage and base current are
•  0.1 V and 1 Î¼A
•  0.15 V and 10 Î¼A
•  1.015 V and 1 Î¼A
•  0.0075 V and 5 Î¼A
Solution
(d) The collector current IC=Î²I_b=2/〖2×103 IC=1×10-3 A The base current Ib=10-3/200 Ib=5×10-6 A Ib=5Î¼A

Q8.The relation between dynamic plate resistance (rp) of a vacuum diode and plate current in the space charge limited region, is

•  rp∝Ip
•  rp∝Ip3/2
•  rp∝1/Ip
•  rp∝1/(Ip)1/3
Solution
(d) The dynamic plate resistance is r_p=(∆Vp)/(∆ip ) Now for a vacuum diode ip=KVp3/2⇒Vp=(ip/K)2/3 ⇒(∆Vp)/(∆ip )=2/(3K2/3 ) ip2/3-1 ⇒rp=(constant) ip-1/3⇒rp∝1/(Ip1/3

Q9.The forbidden energy gap in Ge is 0.72 eV, given, hc = 12400 eV-â„«. The maximum wavelength of radiation that will generate electron hole pair is
•  172220 â„«
•  172.2 â„«
•  17222 â„«
•  1722 â„«
Solution
(c) Energy gap ,Eg=hc/Î» Î»=hc/Eg =12400/0.72=17222 â„«

Q10. If the forward voltage in a semiconductor diode is changed from 0.5 V to 0.7 V, then the forward current changes by 1.0 mA. The forward resistance of diode junction will be
Solution

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