## Electronics Quiz-10

As per analysis for previous years, it has been observed that students preparing for NEET find Physics out of all the sections to be complex to handle and the majority of them are not able to comprehend the reason behind it. This problem arises especially because these aspirants appearing for the examination are more inclined to have a keen interest in Biology due to their medical background.

Furthermore, sections such as Physics are dominantly based on theories, laws, numerical in comparison to a section of Biology which is more of fact-based, life sciences, and includes substantial explanations. By using the table given below, you easily and directly access to the topics and respective links of MCQs. Moreover, to make learning smooth and efficient, all the questions come with their supportive solutions to make utilization of time even more productive. Students will be covered for all their studies as the topics are available from basics to even the most advanced.

Q1.

•  0, 1, 1
•  0, 1, 0
•  1, 1, 0
•  1, 0, 1
Solution
(c) The figure shown in the circuit is a half wave rectifier. During the positive half of the input cycle, when junction diode conducts, output across RL will vary in accordance with AC input. During the negative half cycle, junction diode will get reverse biased and hence no output will be obtained across RL.

Q2.The Output of Y is

•  High for all the high inputs
•  High for all the low inputs
•  High when A=1,B=1,C=0
•  Low for all low inputs
Solution

Q3.

•  AND
•  NAND
•  OR
•  NOR
Solution
(d) For this, the boolean expanssionis Y=(A+B), which is for NOR gate.

Q4. The device that can act as a complete electronic circuit is
•  ZENER diode
•  junction diode
•  Integrated circuit
•  junction Transistor
Solution
(C)

Q5.Consider a p-n junction as a capacitor, formed with p and n-materials acting as thin metal electrodes and depletion layer width acting as separation between them. Basing on this, assume that a n-p-n transistor is working as an amplifier in CE configuration. If C1 and C2 are the base-emitter and collector-emitter junction capacitances, then
•  C1>C2
•  C1< C2
•  C1=C2
•  C1=C2=0
Solution
(A)

Q6. Wires P and Q have the same resistance at ordinary (room) temperature. When heated, resistance of P increases and that of Q decreases. We conclude that
•  P and Q are conductors of different materials
•  P is N-type semiconductor and Q is P-type semiconductor
• P is semiconductor and Q is conductor
•  P is conductor and Q is semiconductor
Solution
(d) Conductor has positive temperature coefficient of resistance but semiconductor has negative temperature coefficient of resistance

Q7.When a semiconductor is heated, its resistance
•  Increase
•  Decreases
•  Remains Same
•  Nothing Definite
Solution
(A)

Q8.In a common base amplifier circuit, calculate the change in base current if that in the emitter current is 2mA and Î±=0.98
•  0.04 mA
•  1.96 mA
•  0.98 mA
•  2 mA
Solution
(a) Î±=(∆Ic)/(∆Ie) ⇒ ∆Ic=0.98×2=1.96 mA ∆Ib=∆Ie-∆Ic=2-1.96=0.04mA.

Q9.A triode whose mutual conductance is 2.5 m A/volt and anode resistance is 20 kilo ohm, is used as an amplifier whose amplification is 10. The resistance connected in plate circuit will be
Solution

Q10. An electron-hole pair is formed when light of maximum wavelength 6000 â„« is incident on the semiconductor. What is the band gap energy of the semiconductor?
•  3.31×10-19 J
•  3.07×10-19 J
•  2.07×10-19 J
• 2.07 J
Solution
(a) Both energy gap, E=hc/Î» =(6.62 ×10-34×3 ×108)/(6000 ×10-10) )=3.31 ×10-19) J

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