As per analysis for previous years, it has been observed that students preparing for NEET find Physics out of all the sections to be complex to handle and the majority of them are not able to comprehend the reason behind it. This problem arises especially because these aspirants appearing for the examination are more inclined to have a keen interest in Biology due to their medical background.

Furthermore, sections such as Physics are dominantly based on theories, laws, numerical in comparison to a section of Biology which is more of fact-based, life sciences, and includes substantial explanations. By using the table given below, you easily and directly access to the topics and respective links of MCQs. Moreover, to make learning smooth and efficient, all the questions come with their supportive solutions to make utilization of time even more productive. Students will be covered for all their studies as the topics are available from basics to even the most advanced.

**Q1.**Figure shows a network of three resistance. When some potential difference is applied across the network, the thermal powers dissipated by A,B and C in the ratio

**Q2.**If an increase in length of copper wire is 0.5% due to stretching, the percentage increase in its resistance will be

Approximate change in resistance=2×% change in length by stretching

**Q3.**Thermoelectric constant of a thermocouple are Î± and Î². Thermoelectric power at inversion temperature is

**Q4.**A current of 1.5 A flows through a copper voltameter. The thickness of copper deposited on the electrode surface of size 50 cm×10 cm is 20 min will be (density of copper =9000 kg-m

^{-3}and ECE of copper=0.00033gC

^{-1}

**Q5.**The resistance between the terminal points A and B of the given infinitely long circuit will be

**Q6.**A battery of emf E and internal resistance r is connected to an external resistance R the condition for maximum power transfer is

**Q7.**For the network shown in the figure the value of the current i is

The given network is a balanced Wheatstone bridge. It’s equivalent resistance will be R=18/5 Î© So current from the battery i=V/R=V/(18/5)=5V/18

**Q8.**A resistor has a colour code of green, blue, brown and silver. What is its resistance?

R=56×10±10%=560+10%

**Q9.**A battery having e.m.f. 5V and internal resistance 0.5 Î© is connected with a resistance of 4.5 Î© then the voltage at the terminals of battery is

i=E/(R+r)=5/(4.5+0.5)=1A V=E-ir=5-1×0.5=4.5 Volt

**Q10.**The temperature of cold junction of thermocouple is 0°C. If the neutral temperature is 270°C, then the inversion temperature is