## MATHEMATICS DETERMINANT QUIZ-1

As per analysis for previous years, it has been observed that students preparing for JEE MAINS find Mathematics out of all the sections to be complex to handle and the majority of them are not able to comprehend the reason behind it. This problem arises especially because these aspirants appearing for the examination are more inclined to have a keen interest in Mathematics due to their ENGINEERING background.

Furthermore, sections such as Mathematics are dominantly based on theories, laws, numerical in comparison to a section of Engineering which is more of fact-based, Physics, and includes substantial explanations. By using the table given below, you easily and directly access to the topics and respective links of MCQs. Moreover, to make learning smooth and efficient, all the questions come with their supportive solutions to make utilization of time even more productive. Students will be covered for all their studies as the topics are available from basics to even the most advanced.

Q1.   For the values of A,B,C and P,Q,R the value of

•  0
•  cos Acos Bcos C
•  sin Asin Bsin C
•  cos Pcos Qcos R
Solution
Q2.If x,y,z are in AP, then the value of the det A where
:
•  0
•  1
•  2
•  None of these
Solution

=>|A|=0 [∵2y=x+z]

Q3.
is equel to
•   ax+y+z+bp+q+r+c
•  0
•  abc+xyz+ppr
•  None of these
Solution

Q4.
•  ±1
•  ±2
•  ±3
•  ±5
Solution
∵
⇒ Î±=±3

Q5.
•  1=3(∆2)2
•
d/dx
(∆1)=3∆2
•
d/dx
(∆1)=2∆2
•  1=3∆23/2
Solution

d/dx(∆1=3(x2-ab) and ∆2= |x b a x| =x2-ab ∴d/dx(∆1)=3(x2-ab)=3∆2

Q6.
•  9a2(a+b)
•  9b2(a+b)
•  a2(a+b)
•  b2(a+b)
Solution
⇒∆=3|a+b|(3b2)=9b2(a+b)

Q7
•
1/a
+
1/b
+
1/c
=0
•
1/a
-
1/b
-
1/c
=0
•
1/b
+
1/c
-
1/a
=0
•
1/b
-
1/c
-
1/a
=0
Solution
⇒ ab+bc+ca=0

Q8.

•  Î± / Î² is one of the cube roots of unity
•  Î± is one of the cube roots of unity
•  Î² is one of the cube roots of unity
•  Î±Î² is one of the cube roots of unity
Solution

(Î± / Î²)3=1⇒(Î± / Î²) is one of the cube roots of unity.

Q9.
•  z-x
•  x-y
•  y-z
•  None Of these
Solution

Hence, the repeating factor is (z-x)

Q10.
•  0
•  1
•  xyz
•  logxyz
Solution
=(1-zy)-y(x -x z) +z (y x -log zx ) =(1-y)-y (x-x) +z(x-x) =(1-1)-0+0=0

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