NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry
NCERT Solutions for class 7 maths chapter 10 practical geometry exercise 10.1
Question:1 Draw a line, say AB, take a point C outside it. Through C, draw a line parallel to AB using ruler and compasses only.
Answer:
1. Draw the line AB
2. Mark any point C outside AB and a point D on AB
3. Join CD
4. Draw an arc with convenient radius with D as centre cutting AB at E and DC at F
5. With the same radius as in step 4 draw an arc IGH with C as a centre and cutting line AC at G.
6 Place one tip of the compass on E and adjust the opening so that pencil tip touches at F.
7. With the same opening in step 6 and G as centre cut an arc at J on IGH.
8. Join CJ and extend the line. This line will be parallel to AB
Question:2 Draw a line 
Answer:
1. Draw a line l. Mark a point P on the line
2. With p as a centre and with any radius draw an arc which touches the line at A and B
3. Take a length more than AP with A as centre draw an arc. with the same length on compass and B as centre draw an arc to cut the previous arc at Q.
4. Join PQ. PQ is perpendicular to the line l
5. Take 4 cm on the compass and with P as centre cut an arc on line PQ at C. The length PC=4 cm
6. with P as a centre and any radius, draw an arc to cut line l at D and PQ at E.
7. with the same radius as in step 6 draw an arc GF with centre C so that it cuts the line PQ at G.
8. Take the length DE on the compass and with G as centre draw an arc to cut FG at J
9. Join CJ and extend the line to name it as line m. Now the line l is parallel to line m
Question:3 Let
Answer:
1. Draw the line PQ parallel to l using the steps to draw parallel lines
2. Draw the line RS parallel to PQ using the steps to draw parallel lines
the two parallel lines make the shape of a parallelogram PQRS.
NCERT solutions for class 7 maths chapter 10 practical geometry exercise 10.2
Question:1 Construct 
Answer:
1. Draw a line XY = 4.5 cm
2. with x as centre and length= 6cm draw an arc
3. with y as centre and length = 5cm draw another arc to cut the arc drawn in step 2 at Z
4. Join XZ and YZ. XYZ is the required triangle
Question:2 Construct an equilateral triangle of side 5.5 cm.
Answer:
an equilateral triangle of side 5.5 cm :
1. Draw a line AB = 5.5 cm
2. with A as centre and length= 5.5cm draw an arc
3. with B as centre and length = 5.5cm draw another arc to cut the arc drawn in step 2 at C
4. Join AC and BC.ABC is the required triangle
Question:3 Draw ?PQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. What type of triangle is this?
Answer:
PQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm:
1.Draw a line QR = 3.5 cm
2. With Q as centre and length = 4 cm draw an arc
3. With R as centre and length = 4cm draw another arc to cut the previous arc at P
4. Join QP and QR. Then PQR is the required triangle
As we can see two sides of the triangle are same so The triangle is an isosceles triangle.
Question:4 Construct 
Answer:
1. Draw a line AB = 2.5 cm
2. with A as centre and length= 6.5cm draw an arc
3. with B as centre and length = 6cm draw another arc to cut the arc drawn in step 2 at C
4. Join AC and BC. ABC is the required triangle
On measuring angle B comes out to be 90 degrees.
NCERT solutions for class 7 maths chapter 10 practical geometry exercise 10.3
Question:1 Construct 
Answer:
1. Draw a line DE = 5cm
2. Draw a line DX making 90 degrees with DE.
3. cut the length DF =3cm using the compass on the line DX
4. Join E and F
DEF is the required triangle
Question:2 Construct an isosceles triangle in which the lengths of each of its equal sides is 6.5 cm and the angle between them is 
Answer:
1. Draw a line DE = 6.5 cm
2. Draw a line DX making 110 degrees with DE.
3. cut the length DF =6.5 cm using the compass on the line DX
4. Join E and F
DEF is the required triangle
Question:3 Construct 
Answer:
1. Draw a line AC = 5 cm
2. Draw a line CX making 60 degrees with AC from C.
3. cut the length BC =7.5 cm using the compass on line CX
4. Join A and B
ABC is the required triangle
NCERT solutions for class 7 maths chapter 10 practical geometry exercise 10.4
Question:1 Construct 
Answer:
1. Draw the line AB=5.8 cm
2. At A making an angle 60 degrees with AB draw a line AX
3. At B making an angle 30 degrees with AB draw a line BY
4. The lines AX and BY intersect at C ( in case the drawn line AX or BY is small extend it to intersect each other)
ABC is the requires triangle
Question:2 Construct 
Answer:
the sum of angles of a triangle is 180 degrees. Given angles PQR and QRP, so the angle QPR= 180-(105+40)=35 degrees
1. Draw the line PQ=5 cm
2. At Q making an angle 105 degrees with PQ draw a line QY
3. At P making an angle 35 degrees with PQ draw a line PX
4. The lines PX and QY intersect at R ( in case the drawn line PX or QY is small extend it to intersect each other)
PQR is the required triangle
Question:3 Examine whether you can construct 
Answer:
No, we cannot construct such that EF = 7.2 cm,
NCERT solutions for class 7 maths chapter 10 practical geometry exercise 10.5
Question:1 Construct the right angled 
Answer:
the right-angled
1. Draw QR = 8 cm
2. Draw a perpendicular QX to QR at Q
3. From R and with length = 10 cm cut an arc on QX. The arc meet QX at P
4. Join PR
PQR is the required triangle
Question:2 Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long.
Answer:
a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long:
1. Draw QR = 4 cm
2. Draw a perpendicular QX to QR at Q
3. From R and with length = 6 cm cut an arc on QX. The arc meet QX at P
4. Join PR
Triangle PQR is the required triangle
Question:3 Construct an isosceles right-angled triangle ABC, where 
Answer:
1. Draw CA = 6 cm
2. Draw a perpendicular CX to CA at C
3. From C and with length = 6 cm cut an arc on CX. The arc meet CX at B
4. Join BA
Triangle ABC is the required triangle
Responsive Table
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