As per analysis for previous years, it has been observed that students preparing for NEET find Physics out of all the sections to be complex to handle and the majority of them are not able to comprehend the reason behind it. This problem arises especially because these aspirants appearing for the examination are more inclined to have a keen interest in Biology due to their medical background.
Furthermore, sections such as Physics are dominantly based on theories, laws, numerical in comparison to a section of Biology which is more of fact-based, life sciences, and includes substantial explanations. By using the table given below, you easily and directly access to the topics and respective links of MCQs. Moreover, to make learning smooth and efficient, all the questions come with their supportive solutions to make utilization of time even more productive. Students will be covered for all their studies as the topics are available from basics to even the most advanced.
Q1. Which of the following has the maximum number of unpaired electrons?
Solution
Mg^(2+)=[Ne] [Zero unpaired electrons] Ti^(3+)=[Ar]3d^1 [One unpaired electrons] Fe^(2+)=[Ar]3d^5 [Five unpaired electrons] V^(3+)=[Ar]3d^2 [Two unpaired electrons]
Mg^(2+)=[Ne] [Zero unpaired electrons] Ti^(3+)=[Ar]3d^1 [One unpaired electrons] Fe^(2+)=[Ar]3d^5 [Five unpaired electrons] V^(3+)=[Ar]3d^2 [Two unpaired electrons]
Q2.The maximum number of electrons in a p-orbital with n=6 and m=0 can be:
Solution
Only 2 electrons in p-orbitals can have m=0.
Only 2 electrons in p-orbitals can have m=0.
Q3. In hydrogen spectrum most energetic transitions of electrons are found in:
Solution
Lyman series spectral lines have smaller λ and thus, higher energy.
Lyman series spectral lines have smaller λ and thus, higher energy.
Q4. For an electron, if the uncertainty in velocity is ∆v, the uncertainty in its position (∆x) is given by:
Solution
∆x∙∆v≥h/4Ï€m
∆x∙∆v≥h/4Ï€m
Q5.Maximum number of electrons present in "N" shell is :
Solution
No. of electron in a shell =2n^2
No. of electron in a shell =2n^2
Q6. Which of the following is correctly matched?
Solution
1/λ=R[1/1^2 -1/2^2 ]=3R/4 λ=h/p P=h/λ=h×3R/4=3Rh/4
1/λ=R[1/1^2 -1/2^2 ]=3R/4 λ=h/p P=h/λ=h×3R/4=3Rh/4
Q7.A certain negative ion X^(2-) has in its nucleus 18 neutrons and 18 electrons in its extra nuclear structure. What is the mass number of the most abundant isotope of X?
Solution
The X-atom has 18 neutrons and 16 electrons and thus, 16 protons also. Thus, it is _16 S^34. The most abundant isotope of sulphur is _16 S^32.
The X-atom has 18 neutrons and 16 electrons and thus, 16 protons also. Thus, it is _16 S^34. The most abundant isotope of sulphur is _16 S^32.
Q8.The scientist who proposed the atomic model based on the quantization of energy for the first time is
Solution
Niels Bohr utilised the concepts of quantisation of energy (proposed by Max planck) first time to give a new model of atom.
Niels Bohr utilised the concepts of quantisation of energy (proposed by Max planck) first time to give a new model of atom.
Q9.Which one of the following is the set of correct quantum numbers of an electron in 3d orbital?
Solution
For 3d-orbital, n=3 For d-orbital, l=2 and m=-2,-1,0,+1,+2 s=±1/2 ∴ The correct set for 3d-orbital is n=3,l=2,m=1,s=+1/2
For 3d-orbital, n=3 For d-orbital, l=2 and m=-2,-1,0,+1,+2 s=±1/2 ∴ The correct set for 3d-orbital is n=3,l=2,m=1,s=+1/2
Q10. Identify the least stable ion amongst the following
Solution
Li^-=1s^2,2s^2(In it all subshells are saturated so, it is stable) Be^-=1s^2,2s^2,2p^1 (very much less stable) B^-=1s^2,2s^2,2p^2 (less stable) C^-=1s^2,2s^2,2p^3 (stable due to presence of half-filled 2p-subshell)
Li^-=1s^2,2s^2(In it all subshells are saturated so, it is stable) Be^-=1s^2,2s^2,2p^1 (very much less stable) B^-=1s^2,2s^2,2p^2 (less stable) C^-=1s^2,2s^2,2p^3 (stable due to presence of half-filled 2p-subshell)